How to launch a dialog box in windows services

Question

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my code

my code in the start of the service funcation.

code:

C++

SappDialog obj;
CoInitialize(NULL);
AFX_MANAGE_STATE(AfxGetStaticModuleState());
HINSTANCE hInst1= GetModuleHandle (0);
HWND hDlg;
hDlg = CreateDialog(hInst1, MAKEINTRESOURCE(IDD_DIALOG1), 0, DialogProc, 0);
ShowWindow(hDlg, 5);

IDD_DIALOG1 - my Dialog box id.

if i try like that the dialog box is not launching.
i want to launch the dialog box, before service get starts.

Posted 6-Nov-12 23:07pm

@BangIndia

Updated 6-Nov-12 23:21pm

Jochen Arndt

v2

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enhzflep 7-Nov-12 6:09am

You were given the answer yesterday. (here)
Sergey already told you that you don't do that with a service. What makes you think the answer will be different if you re-phrase the same question? My 1.

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jim lahey · Answer 1 · 2012-11-06T23:45:00

Think about what you're trying to achieve. You want to show a dialog before the service starts, but if you put the dialog code in the service, the service has to start before you show the dialog. I'd leave the service as it is, and have a small app that you can use to start the service with which shows the dialog before starting the service.

If you need a GUI you should rethink. The wikipedia article: http://en.wikipedia.org/wiki/Windows_service[^] clearly states "a Windows service is a long-running executable that performs specific functions and it is designed not to require user intervention"