converting Integer To Words

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how convert integer value to words:
eg: 1020=Thousand and twenty

Posted 3-Sep-12 20:54pm

rajin kp

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[no name] 4-Sep-12 3:00am

I can give you all the code, but what have you tried?

4 solutions

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Ganesh Nikam · Accepted Answer · 2012-09-03T21:20:00

try this

Call
AmountInWords obj=new AmountInWords();
obj.Convert(10450.67)

AmountinWords.cs

C#

class AmountInWords
   {
       private static String[] units = { "Zero", "One", "Two", "Three",
           "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven",
           "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen",
           "Seventeen", "Eighteen", "Nineteen" };
       private static String[] tens = { "", "", "Twenty", "Thirty", "Forty",
           "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };


       public String ConvertAmount(double amount)
       {
           try
           {
               int amount_int = (int)amount;
               int amount_dec = (int)Math.Round((amount - (double)(amount_int)) * 100);
               return  convert(amount_int) + "  point "
                       + convert(amount_dec) ;
           }
           catch (Exception e)
           {
               // TODO: handle exception
           }
           return "";
       }

       public String convert(int i)
       {
           //
           if (i < 20)
               return units[i];
           if (i < 100)
               return tens[i / 10] + ((i % 10 > 0) ? " " + convert(i % 10) : "");
           if (i < 1000)
               return units[i / 100] + " Hundred"
                       + ((i % 100 > 0) ? " and " + convert(i % 100) : "");
           if (i < 100000)
               return convert(i / 1000) + " Thousand "
                       + ((i % 1000 > 0) ? " " + convert(i % 1000) : "");
           if (i < 10000000)
               return convert(i / 100000) + " Lakh "
                       + ((i % 100000 > 0) ? " " + convert(i % 100000) : "");
           return convert(i / 10000000) + " Crore "
                   + ((i % 10000000 > 0) ? " " + convert(i % 10000000) : "");
       }

   }

__TR__ · Accepted Answer · 2012-09-03T21:00:00

Solution 1

Take a look at this CP article
Convert numbers to words in English and Asian format[^]

Convert VB.net code to C# here[^]

Posted 3-Sep-12 21:00pm

__TR__

Comments

__TR__ 4-Sep-12 3:27am

Why downvoted ?

amirmohamad 4-Sep-12 3:38am

5+

__TR__ 4-Sep-12 3:48am

Thanks.

Mohamed Mitwalli 5-Sep-12 5:43am

5+

__TR__ 5-Sep-12 6:11am

Thanks Mohamed.

rajin kp 8-Oct-12 2:48am

THANKS

VIPINVIVEK · Accepted Answer · 2012-09-03T21:01:00

I have written the program to convert currency to string.
little bit modifications to this program will do your work.

C#

class Program
    {
        static void Main(string[] args)
        {
            string ammount=string .Empty ;
        Rep:
            Console.WriteLine("Enter the Ammount");
            ammount = Console.ReadLine();
            Regex r=new Regex (@"^[0-9]+(\.[0-9]+)?$");
            if (!r.IsMatch(ammount)|ammount .Length >9)
            {
                Console.Clear();
                Console.WriteLine("Enter Valid Number within Thousand Core\n");
                goto Rep;
            }
            string inWord = ConvertIntoCurrency(ammount.Trim());
            if (inWord == "Error")
            {
                Console.WriteLine("Enter Valid Number within Thousand Core\n");
                goto Rep;
            }
            Console.WriteLine("Ammount in words : "+inWord);
            Console.ReadLine();
        }


        //Function To Convert the Ammount
        static  string ConvertIntoCurrency(string ammount)
        {
            string inWords=string .Empty;
            int dec=0,cur,ix;
            cur = (int)double.Parse(ammount);
            string[] words = { ".Hundred.", ".Thousand.", ".Thousand.", ".Lakh.", ".Lakh.", ".Core.", ".Core." };
            int[] devidors = { 100, 1000, 1000, 100000, 100000, 10000000, 10000000 };

            if (ammount.IndexOf('.') > 0)
            {
                dec = int.Parse(ammount.Substring(ammount.IndexOf('.') + 1));

                if (dec >= 100)
                {
                    cur += dec / 100;
                    dec = dec % 100;
                }
            }

            if (cur == 0 & dec > 0)
                return dec.ToString() + ".Paise";
            if (cur == 0 & dec == 0)
                return "Nill";
            if (cur.ToString().Length > 9)
                return "Error";


           while (cur.ToString().Length > 2)
           {
               ix = cur.ToString().Length-3;
               inWords += (cur / devidors[ix]).ToString() + words[ix]+"And.";
               cur = cur % devidors[ix];
           }

           if (cur > 0)
           {
                inWords += cur.ToString();
           }

            if (inWords.LastIndexOf(".And.")==inWords .Length -5)
                inWords = inWords.Remove(inWords.Length - 5);

            if (cur == 1)
                inWords += ".Rupee";
            else
                inWords += ".Rupees";

            if (dec > 0)
                inWords += ".And." + dec.ToString() + ".Paise";
            return inWords;
        }

    }

**JF2015** · Accepted Answer · 2012-09-03T21:02:00

See this short post for C#. I briefly tested it and it works very well:
http://forums.exchangecore.com/topic/684-convert-number-to-words-c-console-application/[^]
You just need to copy the two functions to your code to use it:

C#

static String NumWordsWrapper(double n)
      {
         string words = "";
         double intPart;
         double decPart = 0;
         if (n == 0)
            return "zero";
         try
         {
            string[] splitter = n.ToString().Split('.');
            intPart = double.Parse(splitter[0]);
            decPart = double.Parse(splitter[1]);
         }
         catch
         {
            intPart = n;
         }

         words = NumWords(intPart);

         if (decPart > 0)
         {
            if (words != "")
               words += " and ";
            int counter = decPart.ToString().Length;
            switch (counter)
            {
               case 1: words += NumWords(decPart) + " tenths"; break;
               case 2: words += NumWords(decPart) + " hundredths"; break;
               case 3: words += NumWords(decPart) + " thousandths"; break;
               case 4: words += NumWords(decPart) + " ten-thousandths"; break;
               case 5: words += NumWords(decPart) + " hundred-thousandths"; break;
               case 6: words += NumWords(decPart) + " millionths"; break;
               case 7: words += NumWords(decPart) + " ten-millionths"; break;
            }
         }
         return words;
      }

      static String NumWords(double n) //converts double to words
      {
         string[] numbersArr = new string[] { "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" };
         string[] tensArr = new string[] { "twenty", "thirty", "fourty", "fifty", "sixty", "seventy", "eighty", "ninty" };
         string[] suffixesArr = new string[] { "thousand", "million", "billion", "trillion", "quadrillion", "quintillion", "sextillion", "septillion", "octillion", "nonillion", "decillion", "undecillion", "duodecillion", "tredecillion", "Quattuordecillion", "Quindecillion", "Sexdecillion", "Septdecillion", "Octodecillion", "Novemdecillion", "Vigintillion" };
         string words = "";

         bool tens = false;

         if (n < 0)
         {
            words += "negative ";
            n *= -1;
         }

         int power = (suffixesArr.Length + 1) * 3;

         while (power > 3)
         {
            double pow = Math.Pow(10, power);
            if (n > pow)
            {
               if (n % Math.Pow(10, power) > 0)
               {
                  words += NumWords(Math.Floor(n / pow)) + " " + suffixesArr[(power / 3) - 1] + ", ";
               }
               else if (n % pow > 0)
               {
                  words += NumWords(Math.Floor(n / pow)) + " " + suffixesArr[(power / 3) - 1];
               }
               n %= pow;
            }
            power -= 3;
         }
         if (n >= 1000)
         {
            if (n % 1000 > 0) words += NumWords(Math.Floor(n / 1000)) + " thousand, ";
            else words += NumWords(Math.Floor(n / 1000)) + " thousand";
            n %= 1000;
         }
         if (0 <= n && n <= 999)
         {
            if ((int)n / 100 > 0)
            {
               words += NumWords(Math.Floor(n / 100)) + " hundred";
               n %= 100;
            }
            if ((int)n / 10 > 1)
            {
               if (words != "")
                  words += " ";
               words += tensArr[(int)n / 10 - 2];
               tens = true;
               n %= 10;
            }

            if (n < 20)
            {
               if (words != "" && tens == false)
                  words += " ";
               words += (tens ? "-" + numbersArr[(int)n - 1] : numbersArr[(int)n - 1]);
               n -= Math.Floor(n);
            }
         }

         return words;

      }

converting Integer To Words

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