get startup adr of application

Question

0.00/5 (No votes)

See more:

hi ...

in vs2008 (C#):

I have :
1. a main project (windows app)
2. WCF Library
3. WCF Host
4. WCF Client (Windows app)

for testing my service with created client, I call my client form in my main proj and after getting the input requirement of service by this form , I start making response of service by calling my service contract method .

in this service I need to create a proper connection string with recieved parameter for request and I need my application startup path (D:\myProj.dll) to get access to an exe file , Unfortunately after using diffrent kinds of codes that return this path, exactly at point of calling my service, I get another paths I don't need (myproj,bin.debug or c:\programfiles\visual studio9\common7\IDE) can U help me ?

for additional info I have to say that I added this path by a command to post-build event of my service library and client.

plz help me to get access to this path (startup path of my project -> D:\myProj.dll)

thank you in advance

Posted 21-May-12 10:03am

shimashim

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Sergey Alexandrovich Kryukov · Answer 1 · 2012-05-21T11:32:00

So, start-up path, not "adr", right?

If you have some code in some assembly, this call can give you the executing assembly:

C#

string assemblyLocation = System.Reflection.Assembly.GetExecutingAssembly().Location;

Naturally, you can get the location of any other assembly, for example, the entry assembly, using System.Reflection.Assembly.GetEntryAssembly(); etc. Basically, this way you find a location of a main executable module of some assembly, which is a file. (An assembly itself does not have to be a single file, even though VS only support creation of single-module assemblies; the file is also a module, not an assembly.)

Now, you can extract the directory path:

C#

string exePath = System.IO.Path.GetDirectoryName(assemblyLocation);

Please see:
http://msdn.microsoft.com/en-us/library/system.reflection.assembly.aspx[^],
http://msdn.microsoft.com/en-us/library/system.io.path.aspx[^].

I don't understand how can you "get access to an exe file", and how is this related to WCF, but it looks like this is your problem. :-)

—SA