int k, n = 2; k = (k = n + 5)++; cout << k << '\n'; k = ++(k = n + 5); cout << k << '\n';
i = i++
i
operator=
k
k=n+5
f(int &i, int &j, int &k) { i = ++j + k++; }
k = i++ + ++i
k = k++
k = ++k
k = (k = n + 5)++;
(k = n + 5)++
var
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