Help in if statemment

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C

Java

if(x & 1) != 0

how does the statement work?
i can't get it
any help please??

Posted 28-Mar-12 18:46pm

yamen-nassif

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Sergey Alexandrovich Kryukov · Accepted Answer · 2012-03-28T18:51:00

Solution 2

It checks up if the first (least-significant) bit of x is set (equals to 1, not to 0).
Only the syntax requires brackets around to condition: if ((x & 1) != 0) ….

—SA

Posted 28-Mar-12 18:51pm

Sergey Alexandrovich Kryukov

Comments

yamen-nassif 29-Mar-12 0:55am

thx

Sergey Alexandrovich Kryukov 29-Mar-12 10:47am

You are welcome.
--SA

ProEnggSoft 29-Mar-12 1:27am

+5

Sergey Alexandrovich Kryukov 29-Mar-12 10:47am

Thank you.
--SA

Monjurul Habib 30-Mar-12 4:52am

5!

Sergey Alexandrovich Kryukov 30-Mar-12 11:18am

Thank you, Monjurul.
--SA

**JF2015** · Accepted Answer · 2012-03-28T18:49:00

Solution 1

This is a bitwise operation. See here for more information:
http://www.leepoint.net/notes-java/data/expressions/bitops.html[^]
So, x&1 checks if the first bit is set, x&2 checks if the second bit is set and so on...

Posted 28-Mar-12 18:49pm

JF2015

Updated 28-Mar-12 18:55pm

v3

Comments

Sergey Alexandrovich Kryukov 29-Mar-12 0:52am

Sure a 5. (I even answered when the condition is true, please see... :-))
--SA

yamen-nassif 29-Mar-12 0:53am

Ok with (x&1) i get it

what about (x&2) (x&4)

does it mean that i have to look at x in binary????

Sergey Alexandrovich Kryukov 30-Mar-12 11:20am

Sure. 2 = 1 << 1 and 4 = 1 << 2, first and second bits. What's the problem?
--SA

Monjurul Habib 30-Mar-12 4:53am

5!

Sergey Alexandrovich Kryukov 30-Mar-12 11:19am

Thank you, Monjurul.
--SA