how to find the largest substring in a given string containing spaces b/n them.

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If my string is: "hi how to find the largest substring"
My output should be: The largest of the substring is--> substring

I have created a procedure, it works fine but it requires a space at the end of my string.
Thanks in advance if u suggest any procedure that could override this procedure to get the required output.

SQL

alter procedure largerSubstring @baseString varchar(250)
AS
begin
	declare @subString varchar(max),@len int,@largestSubString varchar(max),@prevLength int,@originalLength int
	set @prevLength=0
	set @originalLength=len(@baseString)
	while(@originalLength>0)
	BEGIN
		set @subString=left(@baseString,charindex(' ',@baseString)-1)
		if(len(@subString)>@prevLength)
		begin
			set @prevLength=len(@subString)
			set @largestSubString=@subString;
		end	
		set @baseString=substring(@baseString,charindex(' ',@baseString)+1,@originalLength)

		set @originalLength=@originalLength-(len(@subString)+1)
	END
	print 'the largest string length is--> '+convert(varchar,@prevLength)
	print 'the largest susstring is-->'+@largestSubString
end

Posted 20-Feb-12 17:49pm

The Doer

Updated 20-Feb-12 19:00pm

André Kraak

v3

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Comments

Nilesh Patil Kolhapur 20-Feb-12 23:53pm

Hi teju,
your class rank trigger not working properly check it out.

Nilesh Patil Kolhapur 20-Feb-12 23:54pm

post your procedure to get better answer.

The Doer 21-Feb-12 0:24am

Nilesh it that class rank trigger works for me.., i have put 2 triggers over there.., in which u found difficulty?

The Doer 21-Feb-12 0:33am

I have posted my procedure..,
as i am setting the substring value as seperated by 'spaces' hence it requires a space at the end of the string.
set @subString=left(@baseString,charindex(' ',@baseString)-1)

AmitGajjar 21-Feb-12 1:00am

if you need space at the end of string then place it why you worry more to find other solution ?

André Kraak 21-Feb-12 1:00am

Edited question:
Corrected pre tags
"Treat my content as plain text..." option disabled.

The Doer 21-Feb-12 1:17am

thanks andre,, i was not knowing such stuffs...

The Doer 21-Feb-12 1:18am

amit..,bcoz none of the string ends with spaces so...

3 solutions

Solution 3

Hey,
if U Need Space at end of string then press Alt+255 it inserted blank Character.
Good Luck

Posted 21-Feb-12 20:41pm

Nilesh Patil Kolhapur

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Costica U · Accepted Answer · 2012-02-21T00:18:00

Try this

SQL

alter procedure largerSubstring
    @baseString varchar(250)
AS
begin

    declare @subString          varchar(max),
            @len                int,
            @largestSubString   varchar(max),
            @prevLength         int,
            @foundIndex         int
    
    set @baseString         = isnull(rtrim(ltrim(@baseString)),'')
    set @prevLength         = 0
    set @largestSubString   = @baseString
    
    while(len(@baseString)>0)
    begin
        set @foundIndex = charindex(' ',@baseString)
        if @foundIndex = 0 -- not found
            begin
            set @subString  = @baseString
            set @baseString = ''
            end
        else
            begin
	    set @subString  = left(@baseString,@foundIndex-1)
	    set @baseString = ltrim(right(@baseString,len(@baseString)-@foundIndex))
            end

	 if(len(@subString)>@prevLength)
	   begin
	   set @prevLength         = len(@subString)
	   set @largestSubString   = @subString;
	   end	
    end
    print 'the largest string length is--> '+convert(varchar,@prevLength)
    print 'the largest susstring is-->'+@largestSubString

end

Jaganathan Bantheswaran · Accepted Answer · 2012-02-21T00:41:00

Hi,

Here is the another version,

SQL

CREATE PROCEDURE [dbo].[usp_GetLengthyString] 
(   
 @sInputString VARCHAR(8000) 
) AS
BEGIN
DECLARE @sItem VARCHAR(8000)
DECLARE @lengthyString VARCHAR(8000)
DECLARE @sDelimiter VARCHAR 
SET @sDelimiter = ' '
DECLARE @List TABLE (string VARCHAR(8000), leng INT)
WHILE CHARINDEX(@sDelimiter,@sInputString,0) <> 0 
BEGIN 
	SELECT  @sItem=RTRIM(LTRIM(SUBSTRING(@sInputString,1,CHARINDEX(@sDelimiter,@sInputString,0)-1))), 
			@sInputString=RTRIM(LTRIM(SUBSTRING(@sInputString,CHARINDEX(@sDelimiter,@sInputString,0)+LEN(@sDelimiter),LEN(@sInputString))))
	IF LEN(@sItem) > 0 
		INSERT INTO @List 
		SELECT @sItem, LEN(@sItem)
END
IF LEN(@sInputString) > 0 
	INSERT INTO @List 
	SELECT @sInputString, LEN(@sInputString) -- Put the last item in

SELECT @lengthyString = string FROM @List ORDER BY leng ASC

PRINT 'The longest sub string is ' + @lengthyString

END

how to find the largest substring in a given string containing spaces b/n them.

3 solutions

Solution 1

Solution 2

Solution 3

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