algorithmic question for order of function

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Hi:
I need two function in this condition:

if f(n)=O(g(n)) then Log f(n) != Log (g(n))

additional information :!= means not equal

pleas introduce two this function.

Posted 17-Feb-12 1:59am

Member 4029136

Updated 17-Feb-12 5:28am

wizardzz

v2

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Comments

YvesDaoust 17-Feb-12 8:47am

The second part of the condition does not make sense; it is the same as f(n) != g(n), I don't think this is intended.

wizardzz 17-Feb-12 11:28am

Sounds like homework.

Pradeep yaduvanshy 17-Feb-12 12:03pm

As i think there O(g(n)) is the Order of meant worst case complexity.

then there so simple solution.

every functions f(n) and g(n) satisfy this if f(n)!= g(n).....

like
let f(n)=n^3 and g(n)=n^3-4*n+8

then f(n)==O(g(n))

bt log(f(n)) is not equal to log(g(n))...

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Pradeep yaduvanshy · Answer 1 · 2012-02-17T06:20:00

Solution 1

As i think there O(g(n)) is the Order of meant worst case complexity. then there so simple solution. every functions f(n) and g(n) satisfy this if f(n)!= g(n)..... like let f(n)=n^3 and g(n)=n^3-4*n+8 then f(n)==O(g(n)) bt log(f(n)) is not equal to log(g(n))...

Posted 17-Feb-12 6:20am

Pradeep yaduvanshy