error in this below code plz solve any one

Question

1.00/5 (6 votes)

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C#

Line 29:         con.Open();
Line 30:         cmd = new SqlCommand("insert into login values('"+TextBox1.Text+"','"+TextBox3.Text+"'", con);
Line 31:         cmd.ExecuteNonQuery();
Line 32:     }
Line 33:

C#

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Configuration;
using System.Data;
using System.Web.Security;
using System.Web.UI.HtmlControls;
using System.Web.UI.WebControls.WebParts;
using System.Xml.Linq;
using System.Data.SqlClient;
using System.Drawing;


public partial class Default2 : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {
        
    }
    SqlConnection con = new SqlConnection("Data Source=CIODEV03\\SQLEXPRESS;Initial Catalog=EmployeeDB;Integrated Security=True");
    SqlCommand cmd;
    SqlDataReader dr;

    protected void Button1_Click(object sender, EventArgs e)
    {
        con.Open();
        cmd = new SqlCommand("insert into login values('"+TextBox1.Text+"','"+TextBox3.Text+"'", con);
        cmd.ExecuteNonQuery();
    }

    protected void LinkButton1_Click(object sender, EventArgs e)
    {
        con.Open();
        cmd = new SqlCommand("select * from login where UserName='" + TextBox1.Text + "'", con);
        dr = cmd.ExecuteReader();
        if (dr.Read())
        {
            Label1.Text = "UserName alredy Exist";
            this.Label1.ForeColor = Color.Red;
        }
        else
        {
            Label1.Text = "UserName is Avilable";
        }
    }
}

Posted 7-Feb-12 19:37pm

rockpune

Updated 7-Feb-12 19:39pm

NikulDarji

v2

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Comments

ckulasekaran 8-Feb-12 1:39am

Error in insert command or any where?

rockpune 8-Feb-12 1:44am

exception

Abey Thomas 8-Feb-12 1:39am

No code formatting, no explanation of what the error is.. how do someone help you?

rockpune 8-Feb-12 1:44am

exception

Abey Thomas 8-Feb-12 1:47am

what is the exception....?! please provide a dump of that.

rockpune 8-Feb-12 1:48am

cmd.ExecuteNonQuery();

NikulDarji 8-Feb-12 1:40am

pre tag added...

rockpune 8-Feb-12 1:44am

exception

Lakamraju Raghuram 8-Feb-12 1:40am

Mention the line which is creating error and use proper tags to made the code readable

Sergey Alexandrovich Kryukov 8-Feb-12 1:42am

Not a question. Use "Improve question" above.
--SA

Sergey Alexandrovich Kryukov 8-Feb-12 1:43am

Error or exception. Full error report or exception dump please, commented in relevant lines of code.
--SA

rockpune 8-Feb-12 1:44am

exception

rockpune 8-Feb-12 1:48am

cmd.ExecuteNonQuery();

4 solutions

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Abhinav S · Answer 1 · 2012-02-07T19:54:00

Solution 1

Make sure your field names match the string value type that you are passing in for the insert here - new SqlCommand("insert into login values('"+TextBox1.Text+"','"+TextBox3.Text+"'", con);.

Posted 7-Feb-12 19:54pm

Abhinav S

Comments

rockpune 8-Feb-12 2:09am

Incorrect syntax near the keyword 'values'.
Server Error in '/Checkavailabulity' Application.
Incorrect syntax near the keyword 'values'.
Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.

Exception Details: System.Data.SqlClient.SqlException: Incorrect syntax near the keyword 'values'.

Source Error:

Line 30:
Line 31: cmd = new SqlCommand("insert into values('"+TextBox1.Text+"','"+TextBox3.Text+"'", con);
Line 32: cmd.ExecuteNonQuery();
Line 33: }
Line 34:

Vitaly Obukhov · Answer 2 · 2012-02-07T20:14:00

C#

cmd = new SqlCommand("insert into login values('"+TextBox1.Text+"','"+TextBox3.Text+"'", con);

At least there is no ')'. Try something like this:

C#

cmd = new SqlCommand("insert into login values(@val1, @val2)", con);
cmd.Parameters.AddWithValue("@val1", TextBox1.Text);
cmd.Parameters.AddWithValue("@val2", TextBox3.Text);

SayreCC · Answer 3 · 2012-02-07T20:28:00

Hi,

Make sure the values in your Login Table is equal to values to enter upon login.

If you have 2 Columns in your Login table you must have 2 parameters to past via codebehind.

This is correct:
cmd = new SqlCommand("insert into login values(@val1, @val2)", con);
cmd.Parameters.AddWithValue("@val1", TextBox1.Text);
cmd.Parameters.AddWithValue("@val2", TextBox3.Text);

But if you want to identify the specific column fields:
cmd = new SqlCommand("insert into login (username, password, dates) values(@val1, @val2, @val3)", con);
cmd.Parameters.AddWithValue("@val1", TextBox1.Text);
cmd.Parameters.AddWithValue("@val2", TextBox3.Text);
cmd.Parameters.AddWithValue("@val3", DateTime.Now());

I hope this one can help.

Thank You

Aniket Yadav · Answer 4 · 2012-02-07T20:33:00

Solution 4

Specify The Field Names In The Insert Query

For Eg:

C#

INSERT INTO LOGIN (FieldName1, FieldName2) VALUES ('" + TextBox1.Text + "', '" + TextBox3.Text + "')

Posted 7-Feb-12 20:33pm

Aniket Yadav

v2

error in this below code plz solve any one

4 solutions

Solution 1

Solution 2

Solution 3

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