How to give Button Location at run time in asp.net

Question

0.00/5 (No votes)

See more:

Hi,
How to give button location in asp.net. At windows form we give as Button1.Location. In asp.net I am creating a button at run time and also adding it to a panel control. But i want to give correct Location for that button.

Posted 11-Jan-12 17:19pm

ssyuvaraja

Add a Solution

Comments

manognya kota 11-Jan-12 23:37pm

Check this link for the details :

http://forums.asp.net/t/1236573.aspx/1

3 solutions

Solution 2

hello,

try this

SQL

Button button1 = new Button();
button1.Text = "button";
button1.Attributes.Add("style", "Z-INDEX: 100; LEFT: 100px; POSITION: absolute; TOP: 176px");

change the value part to render the control where you want on the web form.

Posted 11-Jan-12 20:47pm

Jαved

Updated 11-Jan-12 20:48pm

v2

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

manognya kota · Accepted Answer · 2012-01-11T17:35:00

Solution 1

Hi,

Try this code,

C#

myComponent.Style.Add("top", topRandom.ToString() + "px");
myComponent.Style.Add("left", leftRandom.ToString() + "px");

Hope this helps.

Posted 11-Jan-12 17:35pm

manognya kota

Comments

ssyuvaraja 12-Jan-12 1:58am

Location is not changing.

ssyuvaraja · Accepted Answer · 2012-01-12T01:44:00

Solution 3

myComponent.Style.Add("margin-top", topRandom.ToString() + "px");
myComponent.Style.Add("margin-left", leftRandom.ToString() + "px");

Posted 12-Jan-12 1:44am

ssyuvaraja

Updated 12-Jan-12 1:51am

v2