reverse of a number in c#

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1.00/5 (2 votes)

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C#

C#4.0

Hi i want to get reverse of a number in c#

Posted 10-Jan-12 18:29pm

Member 8557048

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Sergey Alexandrovich Kryukov 11-Jan-12 1:12am

Please, define reversed number. And why not implementing it by yourself?
--SA

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Abhinav S · Answer 1 · 2012-01-10T18:37:00

Let me help you get thinking. You can try writing the code yourself.

Divide the number by 10 and take the mod (remainder) value. You get the first digit.
Now divide the number by 10 and ignore the part after the decimal.
Divide the number by 10 again and take the mod value. You get the second digit.
Now divide the number by 10 and ignore the part after the decimal.
And so on...till you have got all the digits.

Now place them all in the reverse order and print them out (if you want to use string operations).

If you don't want to use string operations, you can start multiplying the last digit by 10.
Then the second last by 10*10 = 100
Then the third last by 10*10*10= 1000
And so on....

Finally add this result and you will get the reversed number.

chandrashekhar racharla · Answer 2 · 2012-01-10T18:33:00

Solution 1

Hi,

This link may help you http://social.msdn.microsoft.com/Forums/en-US/csharplanguage/thread/220e694a-4613-47e4-99ec-1f25893db1b0/[^]

Posted 10-Jan-12 18:33pm

chandrashekhar racharla

Prasad_Kulkarni · Answer 3 · 2012-01-10T18:34:00

Solution 2

Hi,
Try this;

C#

int n = 12345;
int left = n;
int rev = 0;
while(left>0)
{
  r = left % 10;
  rev = rev * 10 + r;
  left = left / 10;
}

Console.WriteLine(rev);

And the best example with snaps on following link:
Reverse[^]

Posted 10-Jan-12 18:34pm

Prasad_Kulkarni

Updated 10-Jan-12 18:35pm

v2

Ganesan Senthilvel · Answer 4 · 2012-01-10T18:34:00

Solution 3

C#

public int ReverseInt(int num)
{
    int result=0;
    while (num>0)
    {
       result = result*10 + num%10;
       num /= 10;
    }
    return result;
}