DNS "AAAA, MX, CNAME" record Process

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Friends,

I am creating a sample that Queries data from DNS protocol to fetch "AAAA, MX, CNAME" record types.

I have couple of Questions:

1. Using Wireshark software I looked at the data packet querying "AAA,MX,CNAME" types returns only "Authoritative nameservers"; no answer dose it mean it has no records??

2. I am not sure how to parse these "AAA,MX,CNAME" records to C#.

Any answers or like???

Thanks
Joe

Posted 7-Nov-11 19:09pm

Joe Rozario

Updated 8-Nov-11 6:05am

Yvan Rodrigues

v2

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sjelen 8-Nov-11 11:28am

1. yes
2. take a look at this article:
http://www.codeproject.com/KB/IP/DNS_NET_Resolver.aspx

Joe Rozario 9-Nov-11 5:01am

Hi friend

Thanks for your answer and link, it works fine,
i need little more information

1. Using the solution in the article , I am able to get all records of a domain (but not able to get the sub records) any help?
For example if i have domain like "google.com" it lists all the record types for google.com, this is ok , but i need to get a records like "mail.google.com" also

Thanks
Joe

sjelen 9-Nov-11 7:51am

What you are trying is something like 'zone transfer' - it is used to transfer all records between master and slave name servers in a domain.
In theory, this can be done by querying for "ANY" or "ALL" on the authoritative NS.
However for security reasons this type of transfer is usually restricted only between trusted IPs or networks, so you will not get all records.
In another words - it is only possible with name servers that allow zone transfer.

Joe Rozario 9-Nov-11 9:38am

Thanks again ,

yes i was doing zone transfer, now i found the answer,

if we search Query using "QType.AXFR" we get all the records

Note: The DNS server should allow our host to fetch recoreds.

Thanks

Joe Rozario 15-Nov-11 1:07am

Hi Friend,

i need to do "Incremental Zone transfer", when i Query "IXFR = 251, // incremental transfer [RFC1995]" what type of values will i get? and what the configuration i need to set in DNS?

can you please give me an idea??or link?

Thanks
Joe

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