LISTVIEW random id for each row

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Hi,

all i want is to generate an ID to my listview per row it is possible?
for example i have 10 records in listview and i want to add an ID per row in randomly...

please help..

thanks in advance

Posted 8-Sep-11 19:12pm

Synergy08

Updated 8-Sep-11 19:21pm

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Pradeep Shukla 9-Sep-11 1:18am

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Pradeep Shukla · Answer 1 · 2011-09-08T19:26:00

There are a few ways you can generate a unique ID:

1-Use random() function to generate random number which you can use as an ID.
2-Use System.GUID.NewGUID() to generate GUID and use it. It would be an alphanumeric value though.
3-You can also use database tables to generate for you if you make it an IDENTITY column and return that value to be used as ID
4-Write your own custom logic...

The solution for your case should be like this:

Private randomClass as new Random

For i = 0 To CInt(10) - 1
strId &= Mid(strCodes, Int(Len(strCodes) * randomClass.Next() ) + 1, 1)
Next

For i = 0 To CInt(4) - 1
strId2 &= Mid(strCodes, Int(Len(strCodes) * randomClass.Next() ) + 1, 1)
Next

Rather than using Randomize() & Rnd(), I am using here the Random class and its method Next() to generate a new random number each time. You can also provide min and max value of your random number as parameter while calling Next() method.

Hope this would give you some idea to make a decision what you want to do.

Synergy08 · Answer 2 · 2011-09-08T19:42:00

prdshukla, Thanks for your opinion but i have already construct a logic structure... but my problem is for each row in my subitem column 3 each of them have the same ID, i want is a random id for each row. I am newbie in VB.net and i don't know how to manipulate for this kind of problem...

here's my sample code

<pre lang="vb">

  Public Const A As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
    Public Const B As String = "0123456789"

        lstLicense.Items.Clear()
        lstLicense.Enabled = True

        Dim strCodes As String
        Dim strId As String
        Dim strId2 As String
        Dim zz As String
        Dim item As ListViewItem
        Dim random As New Random
        strCodes = strCodes & A
        strCodes = strCodes & B

        Randomize()

        For i = 0 To CInt(10) - 1
            strId &= Mid(strCodes, Int(Len(strCodes) * Rnd()) + 1, 1)
        Next

        For i = 0 To CInt(4) - 1
            strId2 &= Mid(strCodes, Int(Len(strCodes) * Rnd()) + 1, 1)
        Next

        zz = strId & "-" & strId2


        txtPartNumber.Text = zz


        For d As Integer = 0 To DataGridView1.Rows.Count - 2


            With item

                item = lstLicense.Items.Add(DataGridView1.Item(1, d).Value.ToString, 0)
                item.SubItems.Add(DataGridView1.Item(3, d).Value.ToString)2
                item.SubItems.Add(zz)

            End With
        Next

Synergy08 · Answer 3 · 2011-09-08T20:15:00

thanks for your reply..

but i got an error

'Arithmetic operation resulted in an overflow.'

Private randomClass as new Random

For i = 0 To CInt(10) - 1
strId &= Mid(strCodes, Int(Len(strCodes) * randomClass.Next() ) + 1, 1)
Next
 
For i = 0 To CInt(4) - 1
strId2 &= Mid(strCodes, Int(Len(strCodes) * randomClass.Next() ) + 1, 1)
Next

Synergy08 · Answer 4 · 2011-09-09T01:41:00

for now i want to use "For i As Integer = 1 To 8" but i don't know how to combine with "

VB

strId2 += AZ(randomClass.Next(0, A.Length - 1)).ToString()
With item


                  item = lstLicense.Items.Add(DataGridView1.Item(2, io).Value.ToString, 0)
                  item.SubItems.Add(DataGridView1.Item(3, io).Value.ToString)
                  item.SubItems.Add(strId2)

              End With

bcoz' i want to generate an id for each row that have already record in listview

anyone have an idea?

LISTVIEW random id for each row

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