How to convert String to Windows form object

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C#

private void SubMenuClicked(object sender, EventArgs e)
            {
                  Form _form;
                  string name = "frm";      
                  name+=((MenuItem)sender).Text;
                  _form = (Form)(name);
                  _form.ShowDialog();
            }

I am getting sum text and want to open that form on the basis of that text.

Posted 25-Aug-11 1:18am

Xeshan Ahmed

Updated 25-Aug-11 1:19am

Prerak Patel

v2

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Comments

Prerak Patel 25-Aug-11 7:19am

Use code block for code segments.

3 solutions

Solution 4

VB

' with reflection

Dim myAssembly As Assembly = Assembly.GetExecutingAssembly()

For Each t As Type In myAssembly.GetTypes()
  If t.IsPublic And t.BaseType.Name = "Form" Then
    If t.Name = NomeForm Then
      _obj = t.InvokeMember("", BindingFlags.CreateInstance, System.Type.DefaultBinder, New Object, Nothing)
      frm = CType(_obj, Form)
      frm.MdiParent = Me
      frm.Show()
      Exit For
    End If
  End If
Next

Posted 20-Oct-14 20:54pm

Grandelebo

Solution 3

You code is invalid, you cannot instantiate forms like this. If what you are trying to do is create and open instances of different forms in your project based on different menu item selections, you can use some code like this:

C#

switch(((MenuItem)sender).Text) {
    case "Item1":
        Form1 f1 = new Form1();
        f1.Show();
    case "Item2":
        Form2 f2 = new Form2();
        f2.Show();
}

Posted 25-Aug-11 1:25am

Shameel

Comments

#realJSOP 25-Aug-11 7:27am

Ummm, no. The most correct way (and surely what the user was after) was Prerak Patel's solution.

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Prerak Patel · Accepted Answer · 2011-08-25T01:23:00

Replace

C#

_form = (Form)(name);
_form.ShowDialog();

with

C#

Assembly[] assemblies = AppDomain.CurrentDomain.GetAssemblies();
Form f = null;
foreach (Assembly a in assemblies)
{
    Type[] types = a.GetTypes();
    foreach (Type t in types)
    {
        if (t.IsPublic && t.BaseType == typeof(Form))
        {
            if (t.FullName.Contains(name))
            {
                f = (Form)a.CreateInstance(t.FullName);
            }
        }
    }
}

if (f != null)
    f.ShowDialog();