load list from xml c# and output to listbox

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i have a listbox, and i want to save the items into an xml file.
this is the code to save:

try
            {
                XmlSerializer serializer = new XmlSerializer(typeof(string));
                TextWriter tw = new StreamWriter("C:\\Users\\Lifebook\\Desktop\\Usage Profiles.txt");
                for (int i = 0; i <= lstUsageProfile.Items.Count - 1; i++)
                {
                    serializer.Serialize(tw, lstUsageProfile.Items[i].ToString());
                }
                tw.Close();
            }
            catch (Exception ex)
            {
                MessageBox.Show("Error saving");
            }

This is the output of the xml

<string><node1></string>

this line is repeated for every node in the list box.

to save them it's no problem, but then i want to load them (for the next user who is working on the program)

but i can't load them up and put them back in the list box and removing the xml tags created by default.
pls help.

after that link, i improved my code to:

XmlSerializer deserializer = new XmlSerializer(typeof(List<string>));
TextReader textReader = new StreamReader("C:\\Users\\Lifebook\\Desktop\\Usage Profiles.txt");
List<string> up;
up = (List<string>)deserializer.Deserialize(textReader);
textReader.Close();

lstUsageProfile.Items.Add(up);</string></string></string>

and i'm getting this error

There is an error in XML document (2, 2).

Posted 25-Jul-11 1:57am

adnama

Updated 25-Jul-11 2:31am

Tarun.K.S

v6

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UJimbo · Answer 1 · 2011-07-25T02:27:00

The List was a change in the right direction. Take a look at this code for export and Import:

private void ExportXML()
{
   try
   {
      System.Collections.Generic.List<string> theList = new System.Collections.Generic.List<string>();
      XmlSerializer serializer = new XmlSerializer(typeof(System.Collections.Generic.List<string>));
      TextWriter tw = new StreamWriter(@"C:\Users\Lifebook\Desktop\Usage Profiles.txt");

      for (int i = 0; i <= lstUsageProfile.Items.Count - 1; i++)
      {
         theList.Add(lstUsageProfile.Items[i].ToString());
      }

      serializer.Serialize(tw, theList);
      tw.Close();
   }
   catch (Exception ex)
   {
      MessageBox.Show(ex.Message.ToString());
   }
}


private void ReadXML()
{
   try
   {
      System.Xml.XmlDocument doc = new System.Xml.XmlDocument();
      doc.Load(@"C:\Users\Lifebook\Desktop\Usage Profiles.txt");
      System.Xml.XmlElement root = doc.DocumentElement;
      System.Xml.XmlNodeList lst = root.GetElementsByTagName("string");

      foreach (System.Xml.XmlNode n in lst)
      {
         lstUsageProfile.Items.Add(n.InnerText);
      }
   }
   catch (Exception ex)
   {
     MessageBox.Show(ex.Message.ToString());
   }
}

Simon Dufour · Answer 2 · 2011-07-25T02:01:00

Solution 1

You should take a look to this article.
http://www.switchonthecode.com/tutorials/csharp-tutorial-xml-serialization[^]

Posted 25-Jul-11 2:01am

Simon Dufour