limit of a long or int in java

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How to access the numbers greater than 2147483648(2^31) in java..

This is a small code compiled

C#

import java.io.*;
class Testlong
{public static void main(String args[]) throws Exception
 {
 long i=600851475143;
 System.out.println(i);
 }
 }

on the compilation i get following error

javac Testlong.java
Process started >>>
Testlong.java:5: integer number too large: 600851475143
long i=600851475143;
^
1 error
<<< Process finished.

any help..?
thanks in advance

sreedhar

Posted 24-Jul-11 22:52pm

sreedhar.mb

Updated 24-Jul-11 23:05pm

v2

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Comments

Firo Atrum Ventus 25-Jul-11 5:00am

You still ask this question despite the fact that you already aware of the existence of long data type. Hmm... What's your real question?

4 solutions

Solution 1

Use the long data type.

Posted 24-Jul-11 22:57pm

Shameel

Solution 2

Use Java long type which is signed 64-bit; -9,223,372,036,854,775,808 to 9,223,372,036,854,775,807 (inclusive), see http://download.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html[^].

—SA

Posted 24-Jul-11 22:57pm

Sergey Alexandrovich Kryukov

Solution 3

Using Long or Double...
http://www.javaexamples4u.com/2009/02/java-data-types.html[^]

Posted 24-Jul-11 22:59pm

Prerak Patel

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Firo Atrum Ventus · Accepted Answer · 2011-07-24T23:08:00

Solution 4

In order to insert a hardcoded long use long literal like this:

long i=600851475143l;

More details here.[^]

Posted 24-Jul-11 23:08pm

Firo Atrum Ventus

Updated 24-Jul-11 23:10pm

v2