Activation of more than one class dynamically..

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hii
can anyone plz tell me how to activate all classes inherited from base class dynamically same time.
i create dynamic class using codedom..but now when i execute my software i have to write code for that class..(activation line)
e.g

C#

Frames.Add(new Business_Layer.SSN());
Frames.Add(new Business_Layer.ZipCode());
Frames.Add(new Business_Layer.First_Name());

if i created a dynamic class with a name phone..how can i dynamically add that line below above coded lines..

Posted 14-Jul-11 1:04am

dooa

Updated 17-Jul-11 5:41am

DaveAuld

v2

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ely_bob 14-Jul-11 17:48pm

Are you talking about code injection? or a component based creation approach?

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Alex Perepletov · Answer 1 · 2011-07-17T18:57:00

You should consider using dependency injection, such as MEF or Unity. But for something very simple and dirty you could do as follows:

C#

namespace Business_Layer
{
    using System;
    class SSN
    {
        public SSN()
        {
            Console.WriteLine(GetType().Name);
        }
    }
    class ZipCode
    {
        public ZipCode()
        {
            Console.WriteLine(GetType().Name);
        }
    }
    class First_Name
    {
        public First_Name()
        {
            Console.WriteLine(GetType().Name);
        }
    }
    class Phone
    {
        public Phone()
        {
            Console.WriteLine(GetType().Name);
        }
    }
}
namespace ConsoleApplication2
{
    using System;
    using System.Linq;
    using System.Reflection;
    class Program
    {
        static void Main(string[] args)
        {
            var myTypes =  Assembly.GetExecutingAssembly().GetTypes().Where(x => x.Namespace == "Business_Layer");
            foreach (var type in myTypes)
            {
                Frames.Add(Activator.CreateInstance(type));
            }
        }
    }
}

Output:

SSN<br />
ZipCode<br />
First_Name<br />
Phone<br />
Press any key to continue . . .