How do i retrive datediff(mm/dd/yyyy) format using sql2000

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SQL-server-2000

SQL-Server

how do i retrieve date diff with full format that show day,month,year at same time

Posted 6-Jul-11 20:01pm

Bibekananda Mallick

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walterhevedeich 7-Jul-11 2:02am

Your question is unclear? Do you mean you want to output a result from a datediff function in that format?

[no name] 7-Jul-11 2:04am

please describe more.

Corporal Agarn 7-Jul-11 14:09pm

Do you want DATEADD? Say SELECT DATEADD(day, -30, GETDATE())???

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Prerak Patel · Answer 1 · 2011-07-06T21:30:00

Solution 1

This would be useful to you. You need a procedure.
http://stackoverflow.com/questions/57599/how-to-calculate-age-in-t-sql-with-years-months-and-days[^]

Posted 6-Jul-11 21:30pm

Prerak Patel

OriginalGriff · Answer 2 · 2011-07-06T22:36:00

You can't. Even the stored procedure approach that Prerak recommends has a fatal flaw: there is no SQL date format that allows year or month zero. See MSDN[^]
I would strongly recommend that you instead return a number of days between the two dates

SELECT DATEDIFF(day, [date], GETDATE()) FROM myTable

and process that into a date if you really need it.