Enabing and disabling button

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1.50/5 (2 votes)

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hi all,
i've a button. i want to enable and disable that button based on some conditions. how can i enable and disable the button through code.please help me..

Posted 1-Jun-11 1:00am

Jijesh Balakrishnan

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3 solutions

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barneyman · Accepted Answer · 2011-06-01T01:08:00

Solution 2

use the EnableWindow(...)[^] function, or method, depending on thr framework you're using (raw/MFC/ATL)

EnableWindow(hWindow,FALSE);
or
CWnd.EnableWindow(FALSE);
or
CWindow.EnableWindow(FALSE);

will disable the window

Posted 1-Jun-11 1:08am

barneyman

Comments

Nithin Sundar 1-Jun-11 7:09am

My 5!

Jijesh Balakrishnan 1-Jun-11 7:14am

i'm using MFC

Nithin Sundar 1-Jun-11 7:17am

That doesn't make a difference. MFC is basically a wrapper around win32.

Jijesh Balakrishnan 1-Jun-11 7:18am

thank you..

Joan M 1-Jun-11 12:10pm

Simple and direct... 5ed!

Nithin Sundar · Accepted Answer · 2011-06-01T01:12:00

Solution 3

Adding to the solution of Barneyman, if you're using Win32, you can use something like:

GetDlgItem (YOUR_CONTROL_ID_HERE)->EnableWindow(FALSE);

or the other alternate:

CWnd* myControl = GetDlgItem (YOUR_CONTROL_ID_HERE);

if(myControl)
{
    myControl->EnableWindow (FALSE);
}

Posted 1-Jun-11 1:12am

Nithin Sundar

Comments

Jijesh Balakrishnan 1-Jun-11 7:17am

Thank you..

karan joshua · Accepted Answer · 2011-06-01T01:04:00

Solution 1

try this:

if(condition1)
{
buttonName.enabled=false;
}

Posted 1-Jun-11 1:04am

karan joshua

Comments

Jijesh Balakrishnan 1-Jun-11 7:10am

no.its showing the following error. error C2228: left of '.EnableWindow' must have class/struct/union type

Nithin Sundar 1-Jun-11 7:15am

I think this is suitable only for .NET. Please clarify this!