C++ argument of type is incompatible with parameter of type

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Hi. I`ve written a function and it is doesn`t work. When I try to use it, parameter of type "char*" is underlined of red color. What I should to do?

What I have tried:

C++

<pre>#include <iostream>
#include <stdlib.h>
#include <Windows.h>
#include <string>
using namespace std;

int diap(char*, int, int);

int main() {
	int const max_size = 20;
	int a[max_size];
	int size = diap("Input size-->", 0, max_size);
	return 0;
}

int diap(char* s, int low, int high)
{
	double n;
	do {
		cout << s;
		cin >> n;
	} while ((n < low) || (n > high));
	return (int)n;
}

Posted 11-Dec-21 4:12am

JK_0809

Updated 11-Dec-21 4:47am

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Richard MacCutchan · Answer 1 · 2021-12-11T04:47:00

Solution 1

C++ now enforces the use of the const qualifier on constant values> Change your function to:

C++

int diap(const char* s, int low, int high)

Also, why are you inputting double types when all your comparisons and values are int types in the rest of the program? And, finally, your call to diap in your main function captures the return value but never does anything with it.

Posted 11-Dec-21 4:47am

Richard MacCutchan

Comments

JK_0809 11-Dec-21 14:40pm

Thanks for an answer. It is just the beginning of the program. But thanks for comment, I`ll change the type

merano99 13-Dec-21 16:48pm

Since the field starts at 0, the last index should not be larger than (max_size-1).

size = diap("Input size-->", 0, max_size-1)