How can I get root value from this tag in C#

Question

5.00/5 (1 vote)

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<id root="44da1b5a-c56a-46a4-bcb0-fde7784c8409" xmlns="urn:hl7-org:v3">

What I have tried:

I am unable to get this root value from tag in c#

Posted 28-Oct-21 19:22pm

Member 15411755

Updated 28-Oct-21 23:05pm

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PIEBALDconsult 29-Oct-21 9:52am

The same as you would any XML attribute.

2 solutions

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TheRealSteveJudge · Accepted Answer · 2021-10-28T20:51:00

Solution 1

You could use a regular expression.
Have a look at this example:

C#

using System;
using System.Text.RegularExpressions;

namespace ConsoleApp7
{
    class Program
    {
        static void Main()
        {
            var text = "<id root=\"44da1b5a-c56a-46a4-bcb0-fde7784c8409\" xmlns=\"urn:hl7-org:v3\">";

            var match = Regex.Match(text, "root=\"(?<ROOT>.*)\" xmlns");

            if (match.Success)
            {
                var root = match.Groups["ROOT"];

                Console.WriteLine(root);
            }
            else
            {
                Console.WriteLine("root not found.");
            }
            
            Console.ReadLine();
        }
    }
}

Posted 28-Oct-21 20:51pm

TheRealSteveJudge

Comments

Richard Deeming 29-Oct-21 4:59am

Parsing XML with a regex is likely to cause a rift in the space-time continuum. :)

TheRealSteveJudge 29-Oct-21 5:07am

Indeed, I thought the same at first, but <id root="44da1b5a-c56a-46a4-bcb0-fde7784c8409" xmlns="urn:hl7-org:v3"> is not valid XML and cannot be parsed.
You can verify this fact by using https://www.xmlvalidation.com/

Richard Deeming 29-Oct-21 5:09am

I know, but it's almost certainly part of a larger XML document. Especially since the OP originally posted his question as a "solution" to an old question about reading XML. :)

TheRealSteveJudge 29-Oct-21 5:27am

As your solution helps maintaining the space-time continuum you get 5*.

Richard Deeming · Accepted Answer · 2021-10-28T23:05:00

Assuming this is part of a larger XML document, since the fragment you've presented is not valid XML on its own, you need to select the element using the namespace-qualified name.

For example, using LINQ-to-XML:

C#

const string input = "<root><id root=\"44da1b5a-c56a-46a4-bcb0-fde7784c8409\" xmlns=\"urn:hl7-org:v3\"/></root>";
XDocument document = XDocument.Parse(input);

XNamespace ns = "urn:hl7-org:v3";
XElement id = document.Descendants(ns + "id").First();
string root = (string)id.Attribute("root");
// root == "44da1b5a-c56a-46a4-bcb0-fde7784c8409"

Overview - LINQ to XML | Microsoft Docs[^]