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Write a program to find the siblings of the given integer array. if no siblings found then return -1. input1 refers to the length of the input. input2 is the values and input3 is the value for which we need to find the siblings.

Example1:

input1: 5

input2: 1,2,3,4,5

input3: 1

output: {-1}

Explanation: As 1 is the root element which wont have any siblings so return value is -1.

Example2:

input1: 6

input2: 1,2,3,4,5,6

input3: 5

output: {4,6}

Explanation: {2,3} are the children of 1 and {4,5,6} are the children of {2,3} so the output is {4,6}

What I have tried:

public class Exam {

  public static void main(String[] args) throws IOException {
    int input1 = 6;
    int[] input2 = new int[] {1, 2, 3, 4, 5, 6};
    int input3 = 5;
    System.out.println(findSiblings(input1, input2, input3));
  }

  public static int[] findSiblings(int input1, int[] input2, int input3) {
    int[] result = new int[] {-1};
    if (input2[0] == input3) {
      return result;
    }

    
    return result;

  }
}
Posted
Updated 18-Oct-21 6:40am

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Just do it like this:
You have to do a little error handling for non existent elements there:
public static void main(String[] args) throws IOException {

        int[] inputArray = new int[] {1, 2, 3, 4, 5, 6,7};
        int siblingsToFindOf = 6;
        int[] results = findSiblings(inputArray.length, inputArray, siblingsToFindOf);//lenth as array len

        for(int i=0;i<results.length;i++){ //be aware of output arrays item by item. println cant print arrays as well
            System.out.print(String.valueOf(results[i]) + ",");
        }

    }

    public static int[] findSiblings(int input1, int[] input2, int input3) {
        int[] result = new int[] {-1};
        if (input2[0] == input3) {
            return result;
        }

        int siblingFindIndex = -1;
        for(int i=0;i<input2.length;i++){
            if(input2[i]==input3) { //If element at i position is search element
            siblingFindIndex = i;
            break; // end loop
            }
        }
        if(siblingFindIndex>-1){ //index was found in integer array
            result = new int[]{input2[siblingFindIndex-1],input2[siblingFindIndex+1]}; // add found index+1 as upper sibling and found Index -1 as lower sibling
             //to do -> check if both elements exists so there can be no array out of bounds
        }

        return result;

    }
 
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Comments
Richard MacCutchan 1-Aug-20 3:55am    
You do not help people by writing their homework assignments for them.
Pascal Petzoldt 1-Aug-20 5:50am    
It does not work well when they dont understand the code.

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