How do I remove 0 from numbers 10 and above?

Question

1.00/5 (1 vote)

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Hello! How can I remove the preceding '0' from number 10 above? Only numbers 1-9 should have preceding '0'.

SAMPLE INPUT:
40

SAMPLE OUTPUT:
01.02.03.04.05.06.07.08.09.10
11.12.13.14.15.16.17.18.19.20
21.22.23.24.25.26.27.28.29.30
31.32.33.34.35.36.37.38.39.40

MY CODE'S OUTPUT:
01.02.03.04.05.06.07.08.09.010
011.012.013.014.015.016.017.018.019.020
021.022.023.024.025.026.027.028.029.030
031.032.033.034.035.036.037.038.039.040

Can you help me, please? I tried different ways but still won't work. I'm new in programming btw, that's why I don't know much.

What I have tried:

C++

#include <iostream>
using namespace std;

int main()
{
int a, b;
cin >> b;

if (b > 100){
  cout << "OUT OF RANGE";
  }
else {
    for (int a = 1; a <= b; a++){
      cout << "." << "0" << a;
    }
  }
}

Posted 27-Sep-21 16:41pm

Jinhwan Kim 2021

Updated 28-Sep-21 12:18pm

merano99

v5

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Comments

jeron1 28-Sep-21 19:09pm

Not sure why the question was downvoted, a question was asked, the input, expected output, actual output, and code attempt was provided. A little harsh I think.

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OriginalGriff · Accepted Answer · 2021-09-27T20:06:00

Solution 1

Try using the stream formatting operators:

C++

#include <iostream>
#include <iomanip>

using namespace std;

int main()
    {
    int i = 1;
    int j = 17;
    cout << std::setw(2) << std::setfill('0') << i << "," << j << std::endl;
    return 0;
    }

Posted 27-Sep-21 20:06pm

OriginalGriff

Comments

CPallini 28-Sep-21 2:57am

5.

merano99 28-Sep-21 18:10pm

5.