errors in this code / help

Question

1.33/5 (3 votes)

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//sum of two 5 bit  binary 

int ar1[ 5 ]; 
int ar2[5];
int ar3[6];
int i;
for (  i=0; i<5; i++) 
cin>>ar[i];
for (  i=0; i <5; i++)
cin>>ar1[i];
{
ar2[i] = ar[i] + ar1[i] + ar3[i];
if ( ar2[i] > 1)
{
ar3[i+1] = 1;
ar2[i] %= 2;
}
cout<<ar2[i]<<endl;}
return 0;

Posted 24-May-11 10:52am

maha001

Updated 24-May-11 10:53am

Albert Holguin

v2

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Manfred Rudolf Bihy 25-May-11 10:21am

REPOST!

3 solutions

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Albert Holguin · Answer 1 · 2011-05-24T10:57:00

Solution 1

You don't seem to understand why brackets are there...

loop with one statement:

for(int i=0; i<5;i++)
  x=i;

loop with more than one statement:

for(int i=0; i<5;i++)
{           //<-- More than one statement, must include brackets to keep it inside of statement
  x=i;
  y= x+5;
  //etc...
}

Posted 24-May-11 10:57am

Albert Holguin

Comments

Valery Possoz 24-May-11 17:39pm

I find it's quite funny that last week survey was about brackets!
http://www.codeproject.com/Surveys/1156/Do-you-wrap-single-line-statements-in-braces-or-be.aspx

Albert Holguin 24-May-11 23:46pm

it's ironic isn't it?

Richard MacCutchan · Answer 2 · 2011-05-24T11:57:00

Solution 2

This code and your previous question[^] really shows that you are trying to run before you can walk. Spend some more time reading your course notes and C++ documentation until you can understand the basic syntax of C++ including arrays, loops etc.

Posted 24-May-11 11:57am

Richard MacCutchan

HubSnippets · Answer 3 · 2011-05-25T04:00:00

Solution 3

In addition to above responses, in your code, the ar[] array was not declared with a particular data type, before been used. Also, check the use of brackets before the second "for" loop.

One of the qualities of a good programmer is patience!

Posted 25-May-11 4:00am

HubSnippets