15,892,537 members
Sign in
Sign in
Email
Password
Forgot your password?
Sign in with
home
articles
Browse Topics
>
Latest Articles
Top Articles
Posting/Update Guidelines
Article Help Forum
Submit an article or tip
Import GitHub Project
Import your Blog
quick answers
Q&A
Ask a Question
View Unanswered Questions
View All Questions
View C# questions
View C++ questions
View Javascript questions
View Visual Basic questions
View Python questions
discussions
forums
CodeProject.AI Server
All Message Boards...
Application Lifecycle
>
Running a Business
Sales / Marketing
Collaboration / Beta Testing
Work Issues
Design and Architecture
Artificial Intelligence
ASP.NET
JavaScript
Internet of Things
C / C++ / MFC
>
ATL / WTL / STL
Managed C++/CLI
C#
Free Tools
Objective-C and Swift
Database
Hardware & Devices
>
System Admin
Hosting and Servers
Java
Linux Programming
Python
.NET (Core and Framework)
Android
iOS
Mobile
WPF
Visual Basic
Web Development
Site Bugs / Suggestions
Spam and Abuse Watch
features
features
Competitions
News
The Insider Newsletter
The Daily Build Newsletter
Newsletter archive
Surveys
CodeProject Stuff
community
lounge
Who's Who
Most Valuable Professionals
The Lounge
The CodeProject Blog
Where I Am: Member Photos
The Insider News
The Weird & The Wonderful
help
?
What is 'CodeProject'?
General FAQ
Ask a Question
Bugs and Suggestions
Article Help Forum
About Us
Search within:
Articles
Quick Answers
Messages
Comments by Yan09 (Top 5 by date)
Yan09
8-Mar-11 4:01am
View
Ok, i see and have an idea of what to do...
Thank you very very very much for all your advises, knowledges sharing and patience to help me achieve my goals.
Yan09
7-Mar-11 7:59am
View
Hmmmmmm.....sorry, but i don't understand your solution.....
What did you mean by: reachable from both [S] and [T]. (A neighboor of S and T????, if it is what when [S]-[X]-[A]-[X]-[T])
If you have the time and if it do not annoy you, i would appreciate if you could explain me it kleaver, because i'm lost... and i'm really sorry ;-)
Yan09
7-Mar-11 6:01am
View
Hi dasblinkenlight,
imagine this:
1---2---S
\ /
T
If i follow the given logic: 2 is an articulation point, removing 2 do not disconnect S from T, so i should remove it, but removing 2 do remove one path from s to t (S-2-T)...
So this logic do not seem to keep all nodes between s and t......or am i still not understanding something?
Yan09
4-Mar-11 10:07am
View
This is really annoying.....cause the user absolutely want to enter a start point, a destination point and generate a visual graph containing all elements between theses twoo....
When you say: ...to which there exist non-overlapping paths from the source and....., i don't understand this, cause it means that for each vertices, i had to find all paths to source and paths to target, to be able to test if it exist non-overlapping ones, and finding paths is justly the problem....
Yan09
4-Mar-11 8:08am
View
Hi dasblinkenlight,
ok now i understand why it's so long...
For your question: Why do you need all paths, anyway? :
The user has to choose between one of the possible path in a list (to each path, tons of informations, statistiques and so on are added), but you're right, it's a non sense to present 1,594,323 results to a user, because it will not be exploitable....
But:
I was also using all returned paths to restrict my graph to vertices that are between source and target (if it is in a simple path, it's between the two vertices), and i think it's there i'm not right in my aproach.....
So how could i, for a given graph, a source vertex and a target vertex, extract a subgraph that contains only vertices that are between source and taget