|
I see, thank you. I'm reading about CSS right now.
Dave
|
|
|
|
|
Hi,
I have a XML string. I want to load it to Multiple tables using visual basic. How do I do that?
Thanks
|
|
|
|
|
I have implemented WSE security on my .net web service and would like to know how to make a request to the service using perl-lite or Java. Can someone point me to an article that explains how this can be done? Thank you,
Jason W.
|
|
|
|
|
I have to develop a tool which will consist of questionnaires and the user has to rate every category. I have to use XML as data source and the changes made will be stored in the XML file.
I am using a tree view on the left side of the form to display the categories present in the XML file. I want to have details of that category and the questions to be displayed on the right side on clicking any of the node of the tree. Since, the questions will be different for each node present in the tree, can someone suggest me any way to achieve this. I think using a dataset for changing the questions on click of a tree view node will be an option.
can anyone help me with the code. I am struggling frm past 3 and half weeks.
Thanks again.
|
|
|
|
|
well, for some strange reason I do everything the hard way (not using dataset) so my idea doesn't have to be optimal solution. Since dataset si in-memory storage for data, it should be also possible to store data in treeView itself - now I mean Tag property of TreeNode. Let say you have class/structure (say Question)representing your question, than set Tag property to instance (created while reading XML file) of your class Question. When user click tree node, unbox myQuestion = (Question)myTreeNode.Tag and show question in controls of right side of the form...
ashushere wrote:
I am struggling frm past 3 and half weeks.
 Did I miss something? (OTOH I am working on something what I expected to be finished before 20th of December  )
best regards,
David 'DNH' Nohejl
Never forget: "Stay kul and happy" (I.A.)
|
|
|
|
|
Working with WSE 2.0 I would like to modify the UsernameToken to include an additional string value to be passed in along with the username and password by the client. Is this possible? Can someone point me to an example of it being done? Thank you,
Jason W.
|
|
|
|
|
Never mind, I figured out how to work around this which was an easier solution.
Jason W.
|
|
|
|
|
I can not read a XML file with or without a scheme using XMLDocument.LoadXML() without getting an exception.
Thanks for your suggestions.
Given this XML file name 'simple1.xml'
<?xml version="1.0" encoding="utf-8" ?>
<book>
<title> my books title</title>
</book>
I had hoped to read it in with this code.
string pathfilename = @"C:\XML_Class\Example\ReadWriteFamily\simple1.xml";
try
{
XmlNode currNode;
XmlDocument doc = new XmlDocument();
//The LoadXml statement throws this exception
//"System.Xml.XmlException: The data at the root level is invalid.
//Line 1, position 1.\r\n at System.Xml.XmlTextReader.ParseRoot()\r\n
//at System.Xml.XmlTextReader.Read()\r\n at System.Xml.XmlValidatingReader.ReadWithCollectTextToken()\r\n
//at System.Xml.XmlValidatingReader.Read()\r\n at System.Xml.XmlLoader.Load(XmlDocument doc, XmlReader reader, Boolean preserveWhitespace)\r\n
//at System.Xml.XmlDocument.Load(XmlReader reader)\r\n at System.Xml.XmlDocument.LoadXml(String xml)\r\n
//at ReadWriteFamily.Form1.ReadSimple1_Click(Object sender, EventArgs e)
//in c:\\xml_class\\example\\readwritefamily\\form1.cs:line 236" string
doc.LoadXml(pathfilename); //exception throw here
XmlDocumentFragment docFrag = doc.CreateDocumentFragment();
docFrag.InnerXml="<title>inserted title</title>" ;
// insert the availability node into the document
currNode = doc.DocumentElement.FirstChild;
currNode.InsertAfter(docFrag, currNode.LastChild);
//save the output to a file
//doc.Save(pathfilename2);
}
catch (Exception eException)
{
string s =eException.ToString();
Console.WriteLine ("Exception: {0}", s);
}
}
}
|
|
|
|
|
method LoadXml() method takes as parameter actual markup, not filename. That's why it throws exception, cuz "C:\XML_Class\Example\ReadWriteFamily\simple1.xml" is definitely not a valid well-formed XML markup  Use Load() method instead.
best regards,
David 'DNH' Nohejl
Never forget: "Stay kul and happy" (I.A.)
|
|
|
|
|
|
I have a project that uses a style sheat to transform data. I want to save the result into DB to use at a later time. When I convert the stream to a string, or attempt to load it back into a dom doc, it fails.
Code: C# -- Out ms is memory stream
xslt.Transform(XmlDoc, null, OutMS, null);
returnXML = System.Text.Encoding.Default.GetString(OutMS.ToArray());
I have tried every type of encoding. utf 8, 16 etc...
Unprintable characters on the front of every one.
Thanks T. J.
|
|
|
|
|
well I don't have experiences with this, bt you could take a look at XmlResolver as I suspect you need to provide it in order to deal with entites - and I *think* (read I have no idea) XSLT could encode some unprintable characters - since whitespace is normaly not an issue as XML processors ignore it.
I also remeber guy who had problem with encoding (XML in string) and I think he solved it with String.Replace(). Try search forum...
I am not sure, I may say BS so plz correct me if I am wrong...
best regards,
David 'DNH' Nohejl
Never forget: "Stay kul and happy" (I.A.)
|
|
|
|
|
Found the solution Thanks anyway. Here it is if anyone wants to know.
There is a stringwriter object based on textwriter that will work. here is the code.
StringWriter writer = new StringWriter();
////////////////////////////////////////
// Load Template into Transformer and //
// Transform the XML that came in //
////////////////////////////////////////
xslt.Transform(XmlDoc.CreateNavigator(), null, writer, null);
returnXML = writer.ToString();
Thanks T. J.
|
|
|
|
|
I am trying to write a schema to validate an xml file. I can get it to validate everything correctly. I have one problem though. In the xml file, after a certain element, I am not going to know what will be there.
ex.
<Node1>
<Node2>
<Node3>
//After this point, the layout could change at any time (and without notice I might add)
//and I don't want to have to keep changing the schema everytime the layout changes.
</Node3>
</Node2>
</Node1>
Anyways, my question is, how would I write the schema to stop the validation at that point? Thanks.
|
|
|
|
|
hi,
<xs:any> should do the job.
W3C XML Schema spec.[^]
best regards,
David 'DNH' Nohejl
Never forget: "Stay kul and happy" (I.A.)
|
|
|
|
|
When I change it I get this exception "The 'http://www.w3.org/2001/XMLSchema:any' element is not supported in this context". Any advice.
|
|
|
|
|
Nevermind, I changed it to
<xs:complexType name="Node4">
<xs:sequence>
<xs:any namespace="##any" minOccurs="0" maxOccurs="unbounded" processContents="skip" />
<xs:sequence>
<xs:complexType>
<xs:element name="Node4" type="Node4" minOccurs="0" maxOccurs="1" />
Maybe not that exactly, but it worked. Thanks for the help
|
|
|
|
|
I have been teaching myself XML for a short time noe, and I want to move into using it with JavaScript for web sites. However, I would like to avoid using the typical "new ActiveXObject(Microsoft.XMLDOM)" line. Is there an alternative to ActiveX/Microsoft?
|
|
|
|
|
|
 :->:->:->
|
|
|
|
|
I'm new to XML and today a guy asked me how to get to a particular node in a very big XML file(1-2 Gigs).
Do you guys have any ideas?
Thanks so much.
|
|
|
|
|
Anonymous wrote:
very big XML file(1-2 Gigs)
 That's not good...
Well first (obvious) idea is not to read whole XML document to memory - XmlDocumentXmlTextReader, bt I am not sure how to get particular node - is it described with XPath or ...how?
Anonymous wrote:
I'm new to XML
hmm in case you don't know XPath, XmlDocument, XmlTextReader etc. feel free to ask - or google 
best regards,
David 'DNH' Nohejl
Never forget: "Stay kul and happy" (I.A.)
|
|
|
|
|
Hi, i want to display info from 2 tables [users] and [friends]. there are a relations between users.id and friends.iduser. when i display i only can display the info from the table [users].
Anyone could help me on displaying info from relations tables? any has a little example plz?
|
|
|
|
|
hmmm, that looks like SQL problem... how does it go with XML/XSL?
Anyway, if it is SQL, you can do something like
SELECT users.name, friends.idontknowhat FROM users, friends WHERE users.id = friends.iduser
or is it in XML? 
best regards,
David 'DNH' Nohejl
Never forget: "Stay kul and happy" (I.A.)
|
|
|
|
|
i have declared two XML objects the first has as datasrc=select * from users and the 2 has select * from users where iduser=@iduser, the problem that i have is that i dont know how to pass the second variable , the iduser from the first xml object, is this posible??
any sugerencies?
thanks
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
