Re: How can find other than The 7 bit default alphabet is present in EditBox? - C / C++ / MFC Discussion Boards

giannib2k12-Apr-11 22:04

12-Apr-11 22:04

Hello, I need to rotate 90° my "graphical objects" on screen (text, lines, rect....)
Is it possible to do it just by changing any VIEW properties or anything similar ?

thanks

Re: Rotate View

C^hris L^osinger13-Apr-11 2:52

C^hris L^osinger

13-Apr-11 2:52

if you don't need your app to work on Win9x boxes, you can use SetWorldTransform[^]

image processing toolkits | batch image processing

Re: Rotate View

giannib2k13-Apr-11 3:16

giannib2k

13-Apr-11 3:16

Thanks for your suggestion, I'll try.
Don't you know if there is any MFC similar function ?

Re: Rotate View

C^hris L^osinger13-Apr-11 3:25

C^hris L^osinger

13-Apr-11 3:25

CDC::SetWorldTransform[^]

image processing toolkits | batch image processing

Re: Rotate View

giannib2k13-Apr-11 3:31

giannib2k

13-Apr-11 3:31

Many thanks again
It was simple !!!
But I just have VisualStudio 2003. Frown | :(

I think I need an upgrade !

thanks Chris

Re: Rotate View

C^hris L^osinger13-Apr-11 3:35

C^hris L^osinger

13-Apr-11 3:35

take a look at this article: Draw oblique / slant text strings[^]

you don't really need an MFC version of the function.

image processing toolkits | batch image processing

How can find other than The 7 bit default alphabet is present in EditBox?

Le@rner12-Apr-11 21:23

Le@rner

12-Apr-11 21:23

Hi all,

i want to identify when user type other than The 7 bit default alphabet character in EditBox.

or

find after end of typing the editbox value contains other than 7 bit default alphabet character or not.

please tell me how can i find this.

thanks in advance.

Re: How can find other than The 7 bit default alphabet is present in EditBox?

Stefan_Lang12-Apr-11 22:33

Stefan_Lang

12-Apr-11 22:33

Two things:

1. Is that even possible? Most windows (including most type of edit boxes or other input controls) don't even accept nonprintable characters, and printable ones should always be 7 bit, unless you're using some exotic alphabet like chinese - in which case you most likely have wide characters (2 byte) anyway.
(Honest question - I do not know the answer)

2. Check the characters for high order bit like this:

bool is7bit(const std::string& input) {
   bool result(true);
   for (std::string::const_iterator it = input.begin(); it != input.end() && result; ++it)
      if (0x80 & *it)
         result = false;
   return result;
}

Note: obviously won't work if translated for multibyte characters since then std::string will contain wide chars as well!

Re: How can find other than The 7 bit default alphabet is present in EditBox?

Klaus-Werner Konrad13-Apr-11 11:53

Klaus-Werner Konrad

13-Apr-11 11:53

You are really an ignorant one - isn't it ???
Ever heard of languages like france, spanish, german ???
They all have umlauts (german are ÄäÖöÜüß) and all of them have Bit8 set ...

Grrrr..

Re: How can find other than The 7 bit default alphabet is present in EditBox?

Stefan_Lang13-Apr-11 22:31

Stefan_Lang

13-Apr-11 22:31

I'm sorry, I didn't recall what localized characters are mapped to. Blush | :O

Probably because I never care about ASCII encoding when I write a letter in german. Wink | ;)

And when I care about encoding, it's somehow always english text - if it is language related at all...

Re: How can find other than The 7 bit default alphabet is present in EditBox?

Klaus-Werner Konrad14-Apr-11 11:53

Klaus-Werner Konrad

14-Apr-11 11:53

Hmm - I'm a litte confused. Because of your name I assumed you're from Germany, and if you are a programmer you should know your primary language encoding (sorting algorhitms and such stuff

Re: How can find other than The 7 bit default alphabet is present in EditBox?

Stefan_Lang14-Apr-11 23:01

Stefan_Lang

14-Apr-11 23:01

1. So am I.
2. Yes I am
3. see 1 Wink | ;)

How can I append menu dynamically ?

_Flaviu12-Apr-11 20:35

_Flaviu

12-Apr-11 20:35

I have an menu : &Refresh , separator , &Modify and Suspen&d

In some cases , I want to append an menu dynamically :
and I try this :

pContextMenu->AppendMenu(MF_SEPARATOR,NULL,"-");
pContextMenu->AppendMenu(MF_POPUP,NULL,"&Export");

and does function , but not in the way that I want , I mean , at 'Export' item , I want to append other popup items , etc.

Ok, further , I don't know how to map handlers on this dynamically menu items ?

Thank you .

Re: How can I append menu dynamically ?

_Flaviu12-Apr-11 20:40

_Flaviu

12-Apr-11 20:40

Here is image of what I want to do :

Existing item
Existing item
Existing item
create separtor
Create popup item
-----------------Create new item
-----------------Create new item
Create new item
Create new item

and , after that , where I should put code on the new create menu items ?

Re: How can I append menu dynamically ?

వేంకటనారాయణ(venkatmakam)12-Apr-11 20:47

వేంకటనారాయణ(venkatmakam)

12-Apr-11 20:47

Means you want to add pop up menu to "Export" menu.
Then create a sub menu like,

CMenu SubMenu;
SubMenu.CreatePopupMenu();
SubMenu.AppendMenu(MF_STRING, IDM_EXPORT_PDF, _T("To Pdf");
SubMenu.AppendMenu(MF_STRING, IDM_EXPORT_WORD, _T("To Word");

Then Create Export Menu as,
pContextMenu->AppendMenu(MF_POPUP, SubMenu.m_hMenu,"Export");

Re: How can I append menu dynamically ?

Niklas L12-Apr-11 22:02

Niklas L

12-Apr-11 22:02

Depending on the scope of pContextMenu, you might have to detach the underlying HMENU from SubMenu to avoid having it destroyed by the destructor of CMenu.

pContextMenu->AppendMenu(MF_POPUP, SubMenu.Detach(), "Export");

home

Re: How can I append menu dynamically ?

_Flaviu12-Apr-11 23:32

_Flaviu

12-Apr-11 23:32

So , can I write code on IDM_EXPORT_PDF handler , if I want ?

Re: How can I append menu dynamically ?

_Flaviu12-Apr-11 23:35

_Flaviu

12-Apr-11 23:35

I think I know ... I map IDM_EXPORT_PDF in message map ... I will try .

Re: How can I append menu dynamically ?

_Flaviu13-Apr-11 0:27

_Flaviu

13-Apr-11 0:27

But if I want to append 2 menus , one of that have an popup menu ?
I try in this way , without succes :

CMenu menu,menuInEx;
menu.LoadMenu(IDR_MENU_RCLICK1);
menuInEx.LoadMenu(IDR_MENU_RCLICK_INEX);


CMenu* pContextMenu = menu.GetSubMenu(0);

POINT point;
point.x = pt.x;
point.y = pt.y;
::ClientToScreen(pNMHDR->hwndFrom,&point);
pContextMenu->AppendMenu(MF_SEPARATOR,NULL,_T("-"));
    pContextMenu->AppendMenu(MF_POPUP,reinterpret_cast<UINT_PTR>(menuInEx.m_hMenu),_T("--"));

Re: How can I append menu dynamically ?

వేంకటనారాయణ(venkatmakam)13-Apr-11 1:04

వేంకటనారాయణ(venkatmakam)

13-Apr-11 1:04

Flaviu 2 wrote:
I try in this way , without succes :

Does any pop menu displayed.If then Where is the problem.Does IDR_MENU_RCLICK1, IDR_MENU_RCLICK_INEX are valid resources?

Re: How can I append menu dynamically ?

_Flaviu13-Apr-11 2:03

_Flaviu

13-Apr-11 2:03

The fact is , if I have an valid IDR_MENU_RCLICK1 and IDR_MENU_RCLICK_INEX resources , how can I append both ?

Re: How can I append menu dynamically ?

_Flaviu13-Apr-11 2:22

_Flaviu

13-Apr-11 2:22

I think that what I want it's a stupid thing !?

Re: How can I append menu dynamically ?

వేంకటనారాయణ(venkatmakam)13-Apr-11 3:33

వేంకటనారాయణ(venkatmakam)

13-Apr-11 3:33

To Merge two menus use the following code,
Merging Two Menus[^]

And You can do merging Like this,

CMenu menu,menuInEx;
menu.LoadMenu(IDR_MENU_RCLICK1);
menuInEx.LoadMenu(IDR_MENU_RCLICK2);

ClientToScreen(&point);
CMenu* pContextMenu = menu.GetSubMenu(0);

MergeMenu(pContextMenu, &menuInEx, false);
pContextMenu->TrackPopupMenu(TPM_RIGHTALIGN, point.x, point.y, this);
CWnd::OnRButtonUp(nFlags, point);

Re: How can I append menu dynamically ?

Klaus-Werner Konrad13-Apr-11 11:57

Klaus-Werner Konrad

13-Apr-11 11:57

May be it's easier for us to answer your question if you show us the wanted menu structure ...

Re: How can I append menu dynamically ?

_Flaviu13-Apr-11 18:54

_Flaviu

13-Apr-11 18:54

Here is the structure of what I want :

Existing item
Existing item
Existing item
Existing item
New popup item
--------------New item
--------------New item
New item
New item

in part I insert new menu , but with all ( with initial number of new menu , you know ... )

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