Enabling and Diabling a Control - C / C++ / MFC Discussion Boards

arbster5-Jan-07 9:18

5-Jan-07 9:18

I'm trying to delete a value inside a specific key. Whats wrong with the example code I've written to do this?

<br />
<br />
HKEY hkey;<br />
	RegOpenKeyEx(HKEY_LOCAL_MACHINE, "SOFTWARE\\Belkin\\Belkin 802.11g Wireless PCI Card\\1.0.0", 0, KEY_SET_VALUE , &hkey);<br />
	RegDeleteValue(HKEY_LOCAL_MACHINE,"test");<br />
	RegCloseKey(hkey);<br />

Re: whats wrong with this code?

Michael Dunn5-Jan-07 9:29

Michael Dunn

5-Jan-07 9:29

RegDeleteValue(hkey,"test");

--Mike--
Visual C++ MVP Cool | :cool:

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Re: whats wrong with this code?

David Crow5-Jan-07 10:07

David Crow

5-Jan-07 10:07

arbster wrote:
Whats wrong with the example code I've written to do this?

What's wrong is that you are not looking at any return values. Functions return a value for a reason.

"Approved Workmen Are Not Ashamed" - 2 Timothy 2:15

"Judge not by the eye but by the heart." - Native American Proverb

Re: whats wrong with this code?

Cristian Amarie5-Jan-07 20:56

Cristian Amarie

5-Jan-07 20:56

... and even wronger is the missing usage of _T() for string arguments.

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Re: whats wrong with this code?

Stephen Hewitt7-Jan-07 11:48

Stephen Hewitt

7-Jan-07 11:48

Thats not wrong if you're not concerned with Unicode.

Steve

Re: whats wrong with this code?

Cristian Amarie7-Jan-07 20:16

Cristian Amarie

7-Jan-07 20:16

True, but is quite rare the code that escapes from Unicode today...

Nuclear launch detected

Re: whats wrong with this code?

Hamid_RT5-Jan-07 18:55

Hamid_RT

5-Jan-07 18:55

You opend your key so you must use of hkey on the RegDeleteValue

WhiteSky

Enabling and Diabling a Control

celllllllll5-Jan-07 8:07

celllllllll

5-Jan-07 8:07

Hi All,

I have two ComboBox controls
{A(it has items like A1, A2 and A3)and
B (B has B1, B2 and B3)}
and one spin control (Z).

Now, my task is that when from control A, A1 is selected then full control B should be diabled. And for all others A2 and A3, B should get enabled.

This is how my code is:

m_CtrlA.SetCurSel(0);<br />
	m_CtrlB.ResetContent();<br />
	if (m_CtrlA.GetCurSel() == A1)<br />
	{<br />
		m_CtrlB.EnableWindow(FALSE);		<br />
		m_Spin.SetRange(0,1000);			<br />
	}<br />
<br />
	else<br />
	{<br />
		m_CtrlB.EnableWindow(TRUE);<br />
	}<br />

So, the problem is what this code is doing is that it is disabling the full m_CtrlB for every case. But I want to disable it for A1 only.

I would really appreciate if someone could help me.

Thanks a lot in advance

C++Prog

Re: Enabling and Diabling a Control

Eytukan5-Jan-07 8:19

Eytukan

5-Jan-07 8:19

Assuming, A1 is of type int and it's value is 0, you should remove
m_CtrlA.SetCurSel(0);. because it sets the selection back to 0th item A1 and hence making the if condition useless.

:Gong: 歡迎光臨吐西批 :Gong:

Re: Enabling and Diabling a Control

jeron15-Jan-07 8:19

jeron1

5-Jan-07 8:19

In the if statement, A1 is used. What is A1 defined as?

m_CtrlA.SetCurSel(0);<br />
m_CtrlB.ResetContent();<br />
if (m_CtrlA.GetCurSel() == A1)

if it's not 0 then this will never be equal, because you set the current selection to 0 before the if statement is executed.

Re: Enabling and Diabling a Control

celllllllll5-Jan-07 8:28

celllllllll

5-Jan-07 8:28

Thanks for the quick response.

A1 is define as:

#define A1 (0)

So, its value is Zero.

And yes I should get rid of

m_CtrlA.SetCurSel(0);

C++Prog

Re: Enabling and Diabling a Control

Eytukan5-Jan-07 8:36

Eytukan

5-Jan-07 8:36

celllllllll wrote:

And yes I should get rid of

m_CtrlA.SetCurSel(0);

C++Prog

You should get rid of m_CtrlA.SetCurSel(0); and C++ Programming ? Roll eyes | :rolleyes:

just kidding.

:Gong: 歡迎光臨吐西批 :Gong:

hiding variables

swjam5-Jan-07 7:37

swjam

5-Jan-07 7:37

say a member function
void MyClass::memFx(int a)
{
int a;
a = 25

cout << "a: " << a << endl;
}

if I call the fx with parameter 5 what will display? what are the other rules of hiding variables? sorry i need your help as I have no compiler with me atm.
thx.

Re: hiding variables

Eytukan5-Jan-07 7:52

Eytukan

5-Jan-07 7:52

This would give a redefinition error since you have a already in the function parameter. But hiding variables? can you explain it better?

:Gong: 歡迎光臨吐西批 :Gong:

Re: hiding variables

C^hris L^osinger5-Jan-07 11:10

C^hris L^osinger

5-Jan-07 11:10

VuNic wrote:
This would give a redefinition error since you have a already in the function parameter.

a small modification, and it will compile fine:

void memFx(int a)
{
	{
	   int a;
	   a = 25;
		
	   cout << "a: " << a << endl ;
	}
}

that's variable hiding. the 'a' inside the brackets hides the 'a' from the containing scope, and so the function always outputs 25.

inner scope hides outer scope.

i'm not sure what all the rules are, though.

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Re: hiding variables

Eytukan5-Jan-07 16:45

Eytukan

5-Jan-07 16:45

"Variable hiding"- Just learnt. Thanks Chris. Smile | :)

:Gong: 歡迎光臨吐西批 :Gong:

Re: hiding variables

S Douglas7-Jan-07 0:24

S Douglas

7-Jan-07 0:24

Chris Losinger wrote:
that's variable hiding. the 'a' inside the brackets hides the 'a' from the containing scope, and so the function always outputs 25.

inner scope hides outer scope.

So what exactly is the purpose of this part of the language? Or in what circumstance would it be used?

I'd love to help, but unfortunatley I have prior commitments monitoring the length of my grass. :Andrew Bleakley:

Re: hiding variables

C^hris L^osinger7-Jan-07 4:35

C^hris L^osinger

7-Jan-07 4:35

S Douglas wrote:
Or in what circumstance would it be used?

i've always used it accidentally. i don't know why anyone would want to use it on-purpose.

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Re: hiding variables

S Douglas7-Jan-07 14:15

S Douglas

7-Jan-07 14:15

Chris Losinger wrote:
i don't know why anyone would want to use it on-purpose.

Out of curiosity, I tried it on a small routine I know gets called and it indeed compiles fine in VS2005 no warnings / errors and it definitely changes the flow. Wierd Unsure | :~

I'd love to help, but unfortunatley I have prior commitments monitoring the length of my grass. :Andrew Bleakley:

How to minimize exposed resources

Joe Smith IX5-Jan-07 6:40

Joe Smith IX

5-Jan-07 6:40

I noticed when I open my (both debug&released) EXE in Res(ource)Hacker, it displays Icon, Menu, Dialog, String Table, Icon Group, and Version Info.

I compared this to several other EXE (not by me), and they only have Icon, Icon Group, and Version Info displayed.

Anybody knows how to prevent the user from using Resource Hacker to change the Menu/String Table?

Thanks in advance.

Re: How to minimize exposed resources

Dominik Reichl5-Jan-07 6:59

Dominik Reichl

5-Jan-07 6:59

You can simply pack your executable using a tool like UPX[^].

Note that UPX is free, but it's possible to unpack the packed executables, i.e. it won't prevent hackers frm editing your resources. If you want to compress+protect your executable, you could try ASPack[^], but note that it's a commercial program.

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Re: How to minimize exposed resources

James R. Twine5-Jan-07 7:24

James R. Twine

5-Jan-07 7:24

   Well, not every application uses dialog templates in resources to generate their interfaces, they can generate them dynamically (in memory). Same goes for menus. Also, not all applications use the String Table to store constant strings.

   Generally, most applications use them. For example, if you open up Explorer.exe, you will get everything.

   Also, note that applications generated by different languages/environments may or may not use resources like a MFC app. For example, a VB application I have handy only contains Icon and Version resources. VB Forms are not static Dialog templates, I guess.

   Peace!

-=- James
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debug_hex command error

ikbahrian5-Jan-07 5:08

ikbahrian

5-Jan-07 5:08

Actually I want to print the buffer in minicom using debug_hex..but it gives error could u please let me know looks like error in debug_hex command.. Confused | :confused:

buffer_send->buf[buffer_send->buf_end++]=0x01;
buffer_send->buf[buffer_send->buf_end++]=0x01;
buffer_send->buf[buffer_send->buf_end++]=0x01;

for(j=0,j<3;j++)
debug_hex(buffer_send[j])

thanks.

Re: debug_hex command error

David Crow5-Jan-07 6:07

David Crow

5-Jan-07 6:07

ikbahrian wrote:
...but it gives error...

Is it error 17? Roll eyes | :rolleyes:

"Approved Workmen Are Not Ashamed" - 2 Timothy 2:15

"Judge not by the eye but by the heart." - Native American Proverb

Re: debug_hex command error

ikbahrian6-Jan-07 0:56

ikbahrian

6-Jan-07 0:56

thx david. i giving wrong argument to debug_hex..the right one is

debug_hex(buffer_send->buf[buffer_send->buf_ptr+j]);

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