Linux, Apache, MySQL, PHP

$query2 = MYSQL_QUERY("SELECT userid FROM users WHERE username='$username';") ;

$query2 = MYSQL_QUERY("SELECT userid,username FROM users WHERE username='$username';") ;

$userid2 = $result2['id']; 

$userid2 = $result2['userid']; 

$sql = "select uid from users where uname='".$user_name."'";
$rst = mysql_query($sql) or die("<br>PG: ".__FILE__."<br>LN: ".__LINE__."<br>ER: ".mysql_error()."<br>Q: ".$sql."<br>");

<?php
.. other code above
echo "<pre>";
while($row=mysql_fetch_assoc($rst))
{
   print_r($row);
}
echo "</pre>";
?>

your probable question:
When you type the url on address bar it behave normally. but when you click in the link in the page it creates a new window. Why?

//Executable

void functionA()
{
//code that calls to functions inside EXE
}

void functionB()
{
//code that calls to functions inside EXE
}

void functionC()
{
//code that calls to functions inside EXE
}

//Shared Library
void functionSL()
{
// I need to call functionA(), functionB() & functionC()
}

//Executable
void functionABC()
{
functionA();
functionB();
functionC();
}

//Shared library
//Must call functionABC()

void func(void (*callback)())
{
}

func(functionA);