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Member 12823445 wrote: if the class is ever published, or if any of you have access to it in the non compiled version
If it's part of .NET, then it's in the Reference Source[^]
Sent from my Amstrad PC 1640
Bad command or file name. Bad, bad command! Sit! Stay! Staaaay...
AntiTwitter: @DalekDave is now a follower!
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To add to what Griff said; you can easily decompile any .NET assembly. I'm using ILSpy, but there are more alternatives.
Bastard Programmer from Hell
If you can't read my code, try converting it here[^]
"If you just follow the bacon Eddy, wherever it leads you, then you won't have to think about politics." -- Some Bell.
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using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace ConsoleApp5
{
class Parser
{
public int res;
char element_of_arr;
string text;
public Parser(string input)
{
text = input;
}
public int String_Parser()
{
for (int i = 0; i != text.Length; i++)
{
char element_of_arr = text[i];
switch (element_of_arr)
{
case '1':
res *= 10 + 1;
break;
case '2':
res *= 10 + 2;
break;
case '3':
res *= 10 + 3;
break;
case '4':
res *= 10 + 4;
break;
case '5':
res *= 10 + 5;
break;
case '6':
res *= 10 + 6;
break;
case '7':
res *= 10 + 7;
break;
case '8':
res *= 10 + 8;
break;
case '9':
res *= 10 + 9;
break;
case '0':
res *= 10;
break;
}
}
return res;
}
}
class Program
{
public static void Main(string[] args)
{
Console.WriteLine("Write digits");
string input = Console.ReadLine();
Console.WriteLine("Try parse it...");
Parser text = new Parser(input);
Console.WriteLine(text.String_Parser());
Console.ReadKey();
}
}
}
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Your calculations are wrong res *= 10 + 3; is the same as res *= 13; But you do not need that switch statement, just replace it with:
res *= 10;
res += element_of_arr - '0';
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res is integer, which is a value type - so it's default value is zero.
When you do this:
res *= 10 + 1; You are effectively saying this:
res = res * (10 + 1); Not
res = (res * 10) + 1;
So if you start with zero, you will always get zero as a result.
But is there a good reason why you don't just use int.TryParse:
Console.WriteLine("Try parse it...");
int result;
if (int.TryParse(input, out result))
{
Console.WriteLine(result);
}
else
{
Console.WriteLine(string.Format("\"{0}\" is not a valid integer", input));
}
Sent from my Amstrad PC 1640
Bad command or file name. Bad, bad command! Sit! Stay! Staaaay...
AntiTwitter: @DalekDave is now a follower!
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Moving code from form to form
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E-i-e-i-o
This space for rent
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Your minimalist approach to asking questions and describing problems does nothing for you at all.
It's simply not possible to provide you any helpful information because nobody has any clue what you're talking about!
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Ctrl-C Ctrl-V
".45 ACP - because shooting twice is just silly" - JSOP, 2010 ----- You can never have too much ammo - unless you're swimming, or on fire. - JSOP, 2010 ----- When you pry the gun from my cold dead hands, be careful - the barrel will be very hot. - JSOP, 2013
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He said moving, not copying.
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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ctrl-X ctrl-v, then?
"Never attribute to malice that which can be explained by stupidity."
- Hanlon's Razor
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Using my way, he can go back and re-do the Ctrl-C when he accidently hits Ctrl-C on an empty line in the new file (we've all done it).
".45 ACP - because shooting twice is just silly" - JSOP, 2010 ----- You can never have too much ammo - unless you're swimming, or on fire. - JSOP, 2010 ----- When you pry the gun from my cold dead hands, be careful - the barrel will be very hot. - JSOP, 2013
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Yep - that's a particularly stupid option, and one of the first things I turn off.
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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from time to time, I see some sample code that is handed to me that has a code snippet that looks like this:
<code>public string Name { get; set; }</code>
Does this actually do anything? Does it really make it so that one can set and get the "Name" string variable?
I have always thought that what is required is something like this:
<code>private string name;
public string Name
{
get
{
return this.name;
}
set
{
this.name = value;
}
}</code>
Am I correct?
Please advise.
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how to create interface loging
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Use ILog<t> where : T interface
Or for a real answer that will work, please be more specific.
"There are three kinds of lies: lies, damned lies and statistics."
- Benjamin Disraeli
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This is not a good question - we cannot work out from that little what you are trying to do.
Remember that we can't see your screen, access your HDD, or read your mind - we only get exactly what you type to work with.
So stop trying to type as little as possible and help us to help you!
Sent from my Amstrad PC 1640
Bad command or file name. Bad, bad command! Sit! Stay! Staaaay...
AntiTwitter: @DalekDave is now a follower!
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I am using custom client connection for 10 tcp clients.
bool _flagScanner1Connect = true;
private xyzTranmissionProtocol xyz1TranmissionProtocol = null;
private static readonly object LockWhileConnectingForScanner1 = new object();
internal ICustomClient Scanner1Conn;
System.Threading.Timer _tmrCheck1ClientConn;
public void Start1ScannerConn() { try { _tmrCheck1ClientConn = new System.Threading.Timer(Check1ScannerConn, null, TimeSpan.FromSeconds(0), TimeSpan.FromSeconds(5));
}
catch (Exception )
{
}
}
private void Check1ScannerConn(object state)
{ if (!_flagScanner1Connect) return;
lock (LockWhileConnectingForScanner1) {
if (Scanner1Conn == null || Scanner1Conn.CommunicationState == ClientCommunicationStates.Disconnected) {
try { _tmrCheck1ClientConn.Change(Timeout.Infinite, Timeout.Infinite);
Scanner1Conn = CustomClientFactory.CreateClient(new CustomClientTcpEndPoint(“Scanner IpAdress”, “Scanner Port Number”));
Scanner1Conn.Connected += Scanner1Conn_Connected; ;
Scanner1Conn.Disconnected += Scanner1Conn_Disconnected;
Scanner1Conn.MessageReceived += Scanner1Conn_MessageReceived;
xyz1TranmissionProtocol = new xyzTranmissionProtocol();
Scanner1Conn.TransmissionProtocol = xyz1TranmissionProtocol;
Scanner1Conn.Connect();
//SEND A PING MESSAGE
_tmrCheck1ClientConn.Change(TimeSpan.FromSeconds(5), TimeSpan.FromSeconds(5));
}
catch (Exception )
{
if (_flagScanner1Connect)
try
{
Scanner1Conn?.Disconnect();
}
catch { }
try
{
Scanner1Conn?.Dispose();
}
catch { }
try
{
Scanner1Conn = null;
}
catch { }
}
finally
{
_tmrCheckClientConn.Change(TimeSpan.FromSeconds(5), TimeSpan.FromSeconds(5));
}
}
}
}
I have written 10 different functions for 10 bar code scanners. above code is for 1 scanner. if i use 3 scanners or less than 3 my application will work. but if i use more than 3 scanners then message received events will not work And the application will become very slow. can anyone help me out to solve this issue.
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I'll bet that what's going on is that you're experiencing one or more run-time exceptions, but since you're just swallowing them, you have no idea that they are happening.
Remove the empty catch blocks, and you'll get a better idea of what's happening in your code.
The difficult we do right away...
...the impossible takes slightly longer.
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I have a gridview with 2 columns and 5 rows-these are fixed.
I want the user to reorder the rows only not the columns. How can i do this? At present i can just reorder the rows.
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Sorry?
Dipk11 wrote: I want the user to reorder the rows only not the columns. How can i do this? At present i can just reorder the rows.
That sounds like it's doing what you wanted it to ...
Remember that we can't see your screen, access your HDD, or read your mind - we only get exactly what you type to work with.
Sent from my Amstrad PC 1640
Bad command or file name. Bad, bad command! Sit! Stay! Staaaay...
AntiTwitter: @DalekDave is now a follower!
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Sorry! My Bad
I can just rearrange the columns, not rows.
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Message Removed
-- modified 10-Jul-18 13:26pm.
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Message Removed
modified 10-Jul-18 13:26pm.
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