Not getting XML nodes

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Hi ,
I am trying to select an xml node without parent node , but am not getting the value . Someone please help .

What I have tried:

C#

XmlNodeList nodes = root.SelectNodes("//sdnDetails");
        foreach (XmlNode node in nodes)
        {
            XmlNode fnamexml = node.SelectSingleNode("firstName");
            if(fnamexml != null)
            {
                string a = fnamexml.InnerText;
            }
        }

xml :

XML

<?xml version="1.0" standalone="yes"?><sdnList xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://tempuri.org/sdnList.xsd">
<publshInformation>
<Publish_Date>12/15/2022</Publish_Date>
<Record_Count>447</Record_Count></publshInformation>
<sdnDetails>
<uid>9639</uid>
<firstName>Ismail Abdul Salah</firstName>
<lastName>HANIYA</lastName>
<sdnType>Individual</sdnType>
</sdnDetails>
</sdnList>

Posted 23-Feb-23 20:39pm

Member 12926744

Updated 24-Feb-23 2:22am

PIEBALDconsult

v2

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Member 15627495 24-Feb-23 3:30am

as XML tree is a 'hard' hierarchy, you have to mention litterals about 'depth',
when you write "//" you are at 'root' level

try :  root.selectNodes("//sdnDetails/sdnType");

but take the time to read about '' 'LINQ' for Xml'' too, because of lot of feature to fetch Xml tree by LINQ query.

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Richard Deeming · Accepted Answer · 2023-02-23T22:16:00

Your XML document has a default namespace of "http://tempuri.org/sdnList.xsd".

Unfortunately, the System.Xml classes don't support default namespaces. Instead, you'll need to use an XmlNamespaceManager to define an alias for the default namespace, and use that in your queries:

C#

XmlNamespaceManager nsmgr = new XmlNamespaceManager(root.OwnerDocument.NameTable);
nsmgr.AddNamespace("d", root.NamespaceURI);

XmlNodeList nodes = root.SelectNodes("//d:sdnDetails", nsmgr);
foreach (XmlNode node in nodes)
{
    XmlNode fnamexml = node.SelectSingleNode("d:firstName", nsmgr);
    ...
}

It's slightly easier with LINQ to XML[^]:

C#

XNamespace ns = root.Name.Namespace;
IEnumerable<XElement> nodes = root.Descendants(ns + "sdnDetails");
foreach (XElement node in nodes)
{
    XElement fnamexml = node.Element(ns + "firstName");
    ...
}