I am given a question by my teacher stating: shift to the right side a user defined string by field width of 20 including the string.

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This is how I've written as just doing a %20s and string having more the lenghth the less width there is so. Sorry I'm not familiarized with fgets so Im doing this in hopes string hass less than 100 characters. How else to solve this?

What I have tried:

//Shifting the string by 20
#include<stdio.h>
int main(){
	char str[100];
	char blank;
	printf ("Enter a string\n");
	gets(str);
	printf ("\n%19c%s", blank, str);
	printf ("\nYour string was shifted to right by width of 20");
	return 0;
}

Posted 15-May-22 22:01pm

BrilliantTimely6874

Updated 15-May-22 22:38pm

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Patrice T 16-May-22 4:22am

And you have a question ?

2 solutions

Solution 2

C++

char blank;                       // you never initialise this variable
printf ("Enter a string\n");
gets(str);
printf ("\n%19c%s", blank, str);  // you only shift it 19 spaces

So try:

C++

printf ("Enter a string\n");
gets(str);
printf ("\n%20c%s", ' ', str);

But is that really what the question asks you to do?

Posted 15-May-22 22:38pm

Richard MacCutchan

Comments

CPallini 16-May-22 4:42am

"But is that really what the question asks you to do?"
Good question.

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OriginalGriff · Accepted Answer · 2022-05-15T22:33:00

Just use the printf formatting:

#include <stdio.h>

int main()
{
    char* str = "Hello World";
    printf("12345678901234567890\n");
    printf("%20s\n", str);
    printf("%-20s\n", str);
    printf("%20.20s\n", str);
    printf("%-20.20s\n", str);
    printf("%10s\n", str);
    printf("%-10s\n", str);
    printf("%10.10s\n", str);
    printf("%-10.10s\n", str);
    return 0;
}

Try it and you'll see what I mean.