Want to return array from one ajax jquery function to called function

Question

1.00/5 (1 vote)

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 var s= []; 
s = function1();// want values here in array 
function function1() {
         //var b = [1,2];
          
         $.ajax({
             type: "POST",
             contentType: "application/json; charset=utf-8",
             data: "{}",
             url: "/Bus/AjaxMethod",
             dataType: "json",
             success: function (data) {
                 debugger;
                 var b = [1, 2];
                 //var b = [];
                 //b = data.split(',');
                  
                 
                 //for (var i = 0; i < data.length; i++) {
                  
                 //    alert(data[i].SeatNo.split(',')); // its working
                  
                  
                 //}
      
                 return b;
             },
             
                 error: function (data) {
                     alert("Error");
                     console.log("Error ", data);
                 }

         });
          
         debugger;
         return b;
     };

What I have tried:

Hi, im new to jquery i dont know much how to return values. so pls help me.

Posted 11-Mar-22 20:11pm

Raja 22S

Updated 14-Mar-22 0:06am

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OriginalGriff · Answer 1 · 2022-03-11T20:20:00

Solution 1

Try here: JavaScript return Statement[^]

Posted 11-Mar-22 20:20pm

OriginalGriff

Comments

Raja 22S 12-Mar-22 2:42am

ok sir, thank u

Richard Deeming · Answer 2 · 2022-03-14T00:06:00

The first "a" in "AJAX" stands for asynchronous. That means the function returns before the request has completed.

You cannot use the values returned from the AJAX request until that request has completed.

You'll need to return a Promise[^], which will return the array value once the request has completed.

JavaScript

function function1() {
    return $.ajax({
        type: "POST",
        contentType: "application/json; charset=utf-8",
        data: "{}",
        url: "/Bus/AjaxMethod",
        dataType: "json",
    }).then(function(data){
        debugger;
        return data.split(',');
    }).fail(function(data){
        console.log("Error ", data);
        alert("Error");
    });
}

You will then need to delay the code which uses the return value until the method returns. You can either use a continuation:

JavaScript

function1().then(function(s) {
    debugger;
    console.log("Returned array", s);
});

or use async and await[^]:

JavaScript

async function doIt(){
    const s = await function1();
    debugger;
    console.log("Returned array", s);
}

doIt();