How to divide list in lambda

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List<int> dd = new List<int>() { 1, 2, 3, 4, -1, -2, -4, 5, 9, 7, 5, 8, 9 };

how to Divide list in lambda with The condition is positive or negative number

result =[1,2,3,4],[-1,-2,-4],[5,9,7],[7, 5, 8, 9]

What I have tried:

<pre>   List<int> dd = new List<int>() { 1, 2, 3, 4, -1, -2, -4, 5, 9, 7, 5, 8, 9 };

how to Divide list in lambda with The condition is positive or negative number

result =[1,2,3,4],[-1,-2,-4],[5,9,7],[7, 5, 8, 9]

Posted 9-Jan-21 3:19am

mohsen_popo

Updated 9-Jan-21 4:22am

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[no name] 9-Jan-21 10:00am

How did you manage to turn one 7 into two 7's? [...7] and [7...]

And you want the result to be a "List of lists"?

BillWoodruff 9-Jan-21 12:17pm

You have not shown any code you TRIED: you just show the result you want.

Sandeep Mewara 9-Jan-21 15:33pm

Though you have tagged C#, can you confirm its in c# or python that you are trying it?

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OriginalGriff · Answer 1 · 2021-01-09T04:22:00

You can't really use Linq for that because Linq is not defined as a sequential execution stream - it could be out of order and you'd get well confused. It normally is executed from the start of the sequence to the end, but that isn't set in stone - a multithreaded optimisation could put it out of order and your sequences would be broken.

Instead, use simple, obvious code:

C#

List<int> dd = new List<int>() { 1, 2, 3, 4, -1, -2, -4, 5, 9, 7, 5, 8, 9 };
bool positive = dd[0] >= 0;
List<List<int>> results = new List<List<int>>();
List<int> current = new List<int>();
results.Add(current);
foreach (int i in dd)
    {
    if (positive && i >= 0) current.Add(i);
    else if (!positive && i < 0) current.Add(i);
    else
        {
        positive = !positive;
        current = new List<int>();
        results.Add(current);
        current.Add(i);
        }
    }

If you want to break a sequence when a sequence stops increasing / decreasing (and your sample data implies that but doesn't confirm it) then it's fairly obvious how to add that in.