a regular expression must have two decimal place

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how to change this regular expession to must have two decimal place

HTML

((0)+(\.[1-9](\d)?))|((0)+(\.(\d)[1-9]+))|(([1-9]+(0)?)+(\.\d+)?)|(([1-9]+(0)?)+(\.\d+)?)

cause i try 0.0123 it work but if i try 1.123 it don't wok, if i try 0.1 is don't work

i have try this [0-9]+\.[0-9][0-9](?:[^0-9]|$) it work al above what i mention, but i doesnt work for 0.00
so i have this text box and a regularexpressionvalidator, how should i check against 0.00?

Posted 2-Feb-12 18:36pm

cutexxbaby

Updated 2-Feb-12 18:41pm

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Wendelius · Answer 1 · 2012-02-02T18:40:00

Solution 1

Do you mean that you must have at least two decimals. Perhaps something like:

\d{1}.(\d){2,32}

Posted 2-Feb-12 18:40pm

Wendelius

Comments

cutexxbaby 3-Feb-12 0:41am

[0-9]+\.[0-9][0-9](?:[^0-9]|$) it work al above what i mention, but i doesnt work for 0.00
so i have this text box and a regularexpressionvalidator, how should i check against 0.00?

cutexxbaby 3-Feb-12 0:42am

plus if the expression you give dont allow me 0.01 or 0.10

Wendelius 3-Feb-12 1:01am

Don't quite understand, when I tested it, 0.01 matches the expression just fine

LanFanNinja 3-Feb-12 1:03am

Don't know if this will help you but it helped me out a while back.
Regex for 0.00

Rajeev Jayaram · Answer 2 · 2012-02-02T19:40:00

Solution 2

Check this similar post,

SOF[^]

Hope it helps.

Posted 2-Feb-12 19:40pm

Rajeev Jayaram