How to press the button in case if the number entered in edit control box is even

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I want to press the Button in case if the number entered in edit control box is even.
I am new to MFC Dialog based application visual studio 2015.
Need Help

What I have tried:

I want to press the Button in case if the number entered in edit control box is even.
I am new to MFC Dialog based application visual studio 2015.
Need Help

Posted 12-Jun-18 20:17pm

Member 13866664

Updated 13-Jun-18 8:37am

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[no name] 13-Jun-18 2:22am

Clicking a button is a user action. Do you mean to call the click handler from code?
Please share your code and what you have tried so far.

Maciej Los 13-Jun-18 2:26am

Good point!
My virtual 5!

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CPallini · Answer 1 · 2018-06-12T21:44:00

Get the integer, say n, from the edit box.
Check is n is even, namely: bool is_even = (n % 2 == 0);
Call the button code (I would put it in a separate method say DoMyWonderfulAction and then call it appropriately both from code and the button).

Please note, there are several ways to implement point 1. If the edit box is already mapped to an integer variable (the UpdateData mechanism), the better. Otherwise you have to get the string (e.g. via GetWindowText method) and then parse it (for instance, via _ttoi[^]) in order to get the integer value.

Patrice T · Answer 2 · 2018-06-13T08:38:00

Quote:
yes i want to click the button from code.
if variable entered in edit control box is even then button get clicked.

This is a bad idea !
Imagine the user want to enter the even number 123456.
As the user type the number, you have:
1 => odd
12 => even
123 => odd
1234 => even
12345 => odd
123456 => even
When do you click your button ?

Imagine the user want to enter the even number 246.
As the user type the number, you have:
2 => even
24 => even
246 => even
When do you click your button ?

This kind of situation is the reason why clicking on button is left to user.

How to press the button in case if the number entered in edit control box is even

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