GDI+ - line chart - C# Discussion Boards

Console-Like Text Output Control Or....

16-Oct-04 8:56

String s = "Lorem ipsum dolor sit amet, kec=123abc";<br />
int index = s.IndexOf("kec=");

You can then use SubString method to extract what you need.

This posting is provided "AS IS" with no warranties, and confers no rights.

Alex Korchemniy

osirisgothra16-Oct-04 7:34

osirisgothra

16-Oct-04 7:34

Ok, this is fairly simple, i need to find/make a text control
that behaves much like a dos box except, i cant use the console because i want to be able
to use graphics (images, controls, etc) also within this space... how would i do this?

any ideas much appriciated
_O

Re: Console-Like Text Output Control Or....

Alex Korchemniy16-Oct-04 8:50

Re: Console-Like Text Output Control Or....

16-Oct-04 8:50

RichTextBox is the way to start. Then you need to find a way of getting the console part of it to work.

This posting is provided "AS IS" with no warranties, and confers no rights.

Alex Korchemniy

Alex Korchemniy16-Oct-04 8:52

16-Oct-04 8:52

Here is a little more help on redirecting the output of the console to a windows control: http://www.windowsforms.net/Forums/ShowPost.aspx?tabIndex=1&tabId=41&PostID=15807[^]

Wish you luck Smile | :)

This posting is provided "AS IS" with no warranties, and confers no rights.

Alex Korchemniy

GDI+ - line chart

xiaowenjie16-Oct-04 4:56

xiaowenjie

16-Oct-04 4:56

hi all, i need to plot a line chart. i plot my graph in a rectangle. im using this method:

Rectangle myRect1 = new Rectangle (105,115,644,375);<br />
myGraphics.TranslateTransform(105,490); //origin for my x,y axis<br />
for (drawLineIndex1=0; drawLineIndex1<9; drawLineIndex1++)<br />
{							<br />
	for (index1=0; index1<10; index1++)<br />
	{<br />
         ptf[index1] =new PointF(105,(-375/maxValue)* -2.3);	<br />
         //maxValue is the higest value that i wanna plot<br />
        //in this case, -2.3 is the minimum value<br />
	}<br />
}

myGraphics.DrawLine(myPen, ptf[drawLineIndex1], ptf[drawLineIndex1+1]);
however, this method only works for +ve perfectly. but for -ve value i can't fit the -ve points within the range of my rectangle . Is there any other way to plot a line chart for -ve and +ve values?

Chris

Kiran Satish16-Oct-04 6:11

16-Oct-04 6:11

Hi Chris,

Sorry I can't help you, but i want some help from u. I am also working on the same type of problem. But i am having values between 0 and some positive value (say 0 - 480000). I want to plot Line-Column chart for my data, as u see in an histogram of an image. Now how can i plot a 2D- graph for this. Using the same lines of code tht u have written. Meanwhile I will figure it out myself. But, if u can gimme some advice, plz.

thanks in advance,

Suman

xiaowenjie16-Oct-04 9:40

xiaowenjie

16-Oct-04 9:40

the simplified coding is :

<br />
 //this means that u draw 10 points since u start from zero<br />
 for (index1=0; index1<10; index1++)<br />
 {<br />
  ptf[index1] =new PointF(105 + 28,250); //PointF(X,Y)<br />
 }<br />
}<br />
//to joint the line on the point<br />
myGraphics.DrawLine(myPen, ptf[drawLineIndex1], ptf[drawLineIndex1+1]);

i hope this help.

Chris

Kiran Satish16-Oct-04 18:21

16-Oct-04 18:21

Hi,

i can understand ur code... but the problem is...

I have developed a Windows form Project in C# and in tht i am opening different bitmap images....now in tht when a bitmap is active and the user selects a menu button "Histogram"... i have to display the histogram of tht image in a seperate window.

Hope i am clear now... if u have any ideas plz share with me...

thanks,

Suman

Alex Korchemniy16-Oct-04 9:22

Re: How can i close my Form

16-Oct-04 9:22

Chris wrote:

for (index1=0; index1<10; index1++)<br />
{<br />
ptf[index1] =new PointF(105,(-375/maxValue)* -2.3);<br />
//maxValue is the higest value that i wanna plot<br />
//in this case, -2.3 is the minimum value<br />
}

Please clearify. The above code is supposed to be generating your points right? It doesn't accomplish anything since its always going to be the same PointF.

Another thing GDI drawing starts with the top left corner and goes down and right across. So you have to flip on the Y axis. Once you get the Point[] you can call DrawPolygon.

This posting is provided "AS IS" with no warranties, and confers no rights.

Alex Korchemniy

How can i close my Form

Zapss16-Oct-04 1:31

Zapss

16-Oct-04 1:31

Hello,
Iam new to c#
My Problem is something like this.

Create a sample windows application, having 2 textboxes & a command
button

Set the forms controlbox property to True

Write validation event for the textbox

private void txtpassword_Validating(object sender,System.ComponentModel.CancelEventArgs e)
if (txtempno.Text=="")
{
MessageBox.Show("Please Enter User Id and password","Invalid Data",MessageBoxButtons.OKCancel);
e.Cancel = true;
}

while running the application when the user clicks the button1
even button1 causes validation set false

the focus is still in of the textbox,
the validation event of the textbox still fire.

Same is the case when the user clicks the [X] button on the control box.

i.e validation event is fired and form is not closed

Form Causesvalidation property aslo set flase.

if i write the code in the Form1_closing event then also the problem is not being solved.

This is because the validation event of the textboxes is fired first so the execution never reaches the Form1_closing event.

How can i close my Form when user user click [X] button on the control box.
or button1?????????????????? Eek! | :eek:

sreejith ss nair16-Oct-04 4:45

sreejith ss nair

16-Oct-04 4:45

You can override the form close event. and can give your own event handler. So what you can do is ,set e.Cancel=false inside the overrided handler.
eg:

<br />
protected override void OnClosing(CancelEventArgs e)<br />
		{<br />
			try<br />
			{<br />
				if(MessageBox.Show("This Will Close Your Form . Do You Want To Continue ?","Conformation",MessageBoxButtons.YesNo,MessageBoxIcon.Information)  ==  DialogResult.No)<br />
				{<br />
					e.Cancel = true;<br />
					base.OnClosing (e);<br />
				}<br />
				else<br />
				{<br />
					this.Dispose();<br />
					<br />
				}<br />
			}<br />
			catch(Exception Ex)<br />
			{<br />
				MessageBox.Show("Ex.Message.ToString(),"Information",MessageBoxButtons.OK,MessageBoxIcon.Information);<br />
<br />
			}<br />
		}<br />

Sreejith Nair
[ My Articles ]

Re: How can i close my Form

Zapss16-Oct-04 20:40

Zapss

16-Oct-04 20:40

It works but validate event fires first before closing event ? again message displays that "please enter user id and pass word".............? after this closing

How can i handle this event in button click???

Subclass control over main class

Nekosan16-Oct-04 1:00

Nekosan

16-Oct-04 1:00

Im trying to crontrol a Buttons Visablity on the main Form1..
I've searched all over the internet for help on this subject and couldnt find any soo I will post my question here Smile | :)

My Code:

if (blargh == verc)
{
Form1 f = new Form1();
f.btn_Start.Visible = true;
f.btn_Patcher.Visible = false;
}
else
{
Form1 f = new Form1();
f.btn_Start.Visible = false;
f.btn_Patcher.Visible = true;
}
}

J4amieC16-Oct-04 2:36

J4amieC

16-Oct-04 2:36

Is this code in Form1 itself?

in which case you should have

this.btn_start.Visible = true;

Nekosan16-Oct-04 2:47

Nekosan

16-Oct-04 2:47

No its in a special class that checks a binary stream..
its not part of Form1..

Alex Korchemniy16-Oct-04 9:40

16-Oct-04 9:40

The button has to be declared "public" (or "internal" if you are in the same project and dont want other projects to be able to do the same). And this should work:

Form1 f = new Form1();<br />
if (blargh == verc)<br />
{<br />
     f.btn_Start.Visible = true;<br />
     f.btn_Patcher.Visible = false;<br />
}<br />
else<br />
{<br />
     f.btn_Start.Visible = false;<br />
     f.btn_Patcher.Visible = true;<br />
}<br />
f.Show(); // or f.ShowDialog();

This posting is provided "AS IS" with no warranties, and confers no rights.

Alex Korchemniy

Nekosan16-Oct-04 10:01

Nekosan

16-Oct-04 10:01

Thanks for trying Alex, that didnt work either.

Alex Korchemniy16-Oct-04 10:25

How to draw a custom graph/2D plot?

16-Oct-04 10:25

That way *has* to work. You probably have some code that changes the visibility during the Load event or something. Or maybe you are using a different button implementation that has a bug.

You can try another way. Pass the value to the Form and then handle the Load event and do what you need.

This posting is provided "AS IS" with no warranties, and confers no rights.

Alex Korchemniy

Kiran Satish15-Oct-04 19:24

Re: How to draw a custom graph/2D plot?

15-Oct-04 19:24

Hi all,

I am able to find all the values tht are needed to draw a histogram (graph) of an image... but i don't know how to draw a histogram (basically a 2D plot) for it. I want to display the histogram (graph) on a seperate window, whenever i click on a menu button.

Plz... gimme me some ideas or suggestions on how to implement tht...

thanks in advance,

Suman

Alex Korchemniy16-Oct-04 8:42

Re: How to draw a custom graph/2D plot?

16-Oct-04 8:42

You have the values. Now just loop and use DrawLine(); Based on the value calculate so that you have a different line height. Increase your X value and continue for the next value.

If this doesn't work for you - you might end up having to use SetPixel method.

This posting is provided "AS IS" with no warranties, and confers no rights.

Alex Korchemniy

Kiran Satish16-Oct-04 18:23