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GeneralRe: trying to write an XSL conditional statement Pin
Philip Fitzsimons14-Apr-04 22:45
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GeneralRe: trying to write an XSL conditional statement Pin
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GeneralXSL Sorting Pin
afronaut1-Apr-04 4:40
afronaut1-Apr-04 4:40 
Hey all. I've written a simple program that will go through Source Safe and get comments developers attach to files. I've set the output to look like this:

<ProjectChanges>
<Row>
<Comment file="FileOne.afro">Updated Code Blah</Comment>
<DateOfChange file="FileOne.afro">3/23/2004 8:00:33 PM</DateOfChange>
<User file="FileOne.afro">Afronaut</User>
</Row>
<Row>
<Comment file="FileOne.afro">Updated Code Blah</Comment>
<DateOfChange file="FileOne.afro">3/23/2004 8:00:33 PM</DateOfChange>
<User file="FileOne.afro">Afronaut</User>
</Row>
...
</ProjectChanges>

Source Safe forces you to iterate through the changes on a file by file basis - that's why I don't just retrieve the data based on date in the first place.

Is there a way, using XSLT, that I can display the changes irrespective of file, ordered by date?
Something like:

Date Change | File Name | Description of Change | Developer

I'm thinking it would is along the lines of:
<xsl:for-each select="Row">
<xsl:sort select="Row/DateOfChange" order="descending"... />
</xsl:for-each>

But isn't this just going to sort within the output of the Row element, not irrespective of element?
Can anyone suggest a better file format for me? My last resort is to just use a single table *.mdb file but it isn't a very effecient approach.

Thanks in advance -


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*->>something new.
cout << "dav1d\n";
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