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Nothing to see here. :innocent-whistle-smily:
In my defence, "3" is directly above "e" on the keyboard. 
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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Given some of the nonsense that appears when I type too fast I think you do very well.
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I was dreading it, Regex doesn't do the job and doesn't replace either?
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Regex can do the job. But running five+ separate regex operations on a string just to replace a few letters with their unaccented alternatives is overkill.
The other option, which is even nastier and less obvious, is to use Unicode normalization:
static string RemoveDiacritics(string stIn)
{
string stFormD = stIn.Normalize(NormalizationForm.FormD);
StringBuilder sb = new StringBuilder();
for(int ich = 0; ich < stFormD.Length; ich++)
{
UnicodeCategory uc = CharUnicodeInfo.GetUnicodeCategory(stFormD[ich]);
if (uc != UnicodeCategory.NonSpacingMark)
{
sb.Append(stFormD[ich]);
}
}
return sb.ToString().Normalize(NormalizationForm.FormC);
}
string input = "Príliš žlutoucký kun úpel dábelské ódy.";
string result = RemoveDiacritics(input); Source[^]
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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case 'Á' case 'À' case 'Ó' ... to be continue
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In [...] groups (alternatives) you don't want the |s.
[aeiou] as a regex will match any vowel, for example.
Software rusts. Simon Stephenson, ca 1994. So does this signature. me, 2012
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I use Regex match to find multiple words in Like mode (start and end point). I do not want the return to include the space as the first position and I do not want the final space to count as valid.
Regular Expression: "\b(?:.Road.|.ous.|.Street.)\b" Must Return: Match:9 length:5 End:13
Text: "have one house free."
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Hello there, I have a string that looks like this
\abc\rvr\sad\dqwdwq Some text \rfdqwdvr\rtgevr\rgwvrr\23rvrv Some text \rffewvr\rfewvr\rvfewrr\rvrwefewv
I want to match the parts of the string that are connected by the backslashes. I partially achieved this with
[\\][A-z0-9]+ but this only matches the first one. How can I match every part with backslashes in this string?
Thanks
modified 31-Aug-21 8:08am.
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Assuming you want to extract three strings:
- \abc\rvr\sad\dqwdwq
- \rfdqwdvr\rtgevr\rgwvrr\23rvrv
- \rffewvr\rfewvr\rvfewrr\rvrwefewv
Try:
([\\][A-Za-z0-9]+)+ Regexper[^]
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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hi would any one have a regex that would match (aug -) or(july -) or (june -)without the brackets
but would not match just (aug)or (july) or (june)
So far i have
\W*((?i)aug -(?-i))\W*
but this also matches aug which i dont want thanks
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I tried your regex in Expresso, and it matches "hello aug -goodbye" but not "hello aug goodbye".
So ... what are you talking about?
"I have no idea what I did, but I'm taking full credit for it." - ThisOldTony
"Common sense is so rare these days, it should be classified as a super power" - Random T-shirt
AntiTwitter: @DalekDave is now a follower!
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im using regex in placemint for placement of window and brousers
if i title a folder aug placemint macthes it , but i only want match on aug -
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Im no ideas what should be captured, so Im guessing that it should include alternates like...
\W*(?i)((?:aug|july|june)(?-i) -)\W*
Except that both \W* are redundant since they allow 0-occurrences, so they dont alter any matched text.
Its best to include samples to keep the experts from guessing, so I will try to save them some troubles...
Capture 'aug' or 'July' or 'JUNE' as whole words if followed by: 1-space, 1-hyphen, 0-or-1 space, and a 1-or-2 digit word.
.*\W(?i)(aug|july|june(?-i)) - ?\d{1,2}\W.*
Capture 'aug -' or 'July -' or 'JUNE -' with the same conditions...
.*\W(?i)((?:aug|july|june(?-i)) -) ?\d{1,2}\W.*
Capture 'aug -##' or 'July - ##' or 'JUNE - ##' with the same conditions...
.*\W(?i)((?:aug|july|june(?-i)) - ?\d{1,2})\W.*
Capture 'aug -' or 'July -' or 'JUNE -' as whole words, but only if - is followed by a non-word character like %.
This does seem the most unlikely, but Im trying to copy your original match, because no samples are being posted...
.*\W(?i)((?:aug|july|june)(?-i) -)\W.*
If none of these match properly, you should include samples of your text lines, and say what should be captured.
There is many experts who is not even going to answer, without first seeing some samples.
modified 5-Oct-21 21:01pm.
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Thanks for trying to help me with this, im a complete novice with regex
i am trying to capture 'aug -' or 'July -' or 'JUNE -'
sentance 'the aug' = would not match
sentance 'aug1' = would not match
sentance 'aug -2' = would not match
sentance 'aug -' = would match
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Im guessing that you posted 4 complete samples, and that 'sentance' means 1 whole line?...
\b(?i)((?:aug|july|june)(?-i) -)$
modified 5-Oct-21 21:01pm.
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yes thanks sentance means 1 whole line,
i tried \b(?i)((?:aug|july|june)(?-i) -)$
but its not matching anything
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Its a PCRE regex to capture text just like your 4th-sample, so matching any lines that end like...
aug -
Maybe you're using something else?? Not using $1 or \1 for replace?? Not giving full samples??
modified 5-Oct-21 21:01pm.
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example i use
\W*((?i)ALARM CLOCK(?-i))\W*
so any window that says alarm clock is placed at same position on desktop
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Without full samples relating to your posted question, Im really afraid nobody is going to help you.
This site shows how my regex matches what you said needs to matched.
https://regex101.com/r/cH4Jrg/1
Feel free to experiment with it, if that's easier than trying to describe what should be matched.
modified 5-Oct-21 21:01pm.
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Don't know if this is the correct solution but it seems to work.
Using the RegexOptions.RightToLeft option seems to work.
I'm not too familiar with Regex. I've created an expression to capture data in a line and it works except for the last group DataType which does not extract the value "dtText". Can someone help?
Thank You
Expression:
FieldName=(?<FieldName>.*?),ColumnWidth=(?<ColumnWidth>.*?),Size=(?<Size>.*?),DataType=(?<DataType>.*?)
Data:
FieldName=Field1,ColumnWidth=50,Size=10,DataType=dtText
Output:
FieldName: [Field1]
ColumnWidth: [50]
Size: [10]
DataType []
-- modified 22-Aug-21 19:28pm.
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.*? tells the expression to capture as little as possible. Since there's nothing to match after the last expression, the least it can capture is nothing, so that's precisely what it does.
If you're looking to capture everything up to the end of the line, then you'll want to add an end-of-line anchor:
...,DataType=(?<DataType>.*?)$
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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Thank you for your help 
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We are trying to create a new policy to detect Employer Identification Number (EIN) in MCAS. I'm very new to Regex so I need some help. We've tried the below regex and MCAS is showing me an error of: Capturing parenthesis not allowed in regular expression. Does anyone know how to convert the below regex to something without the capturing parentheses? Thanks!
([07][1-7]|1[0-6]|2[0-7]|[35][0-9]|[468][0-8]|9[0-589])-?\d{7}
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To prevent (Capturing|Groups), you can spec them as (?:Non|Capturing|Groups)
modified 5-Oct-21 21:01pm.
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