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GeneralRe: Advice on designing a simple task scheduler in embedded C, that can handle asynchronuous tasks? Pin
leon de boer11-Jun-18 2:52
leon de boer11-Jun-18 2:52 
GeneralRe: Advice on designing a simple task scheduler in embedded C, that can handle asynchronuous tasks? Pin
arnold_w11-Jun-18 3:13
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GeneralRe: Advice on designing a simple task scheduler in embedded C, that can handle asynchronuous tasks? Pin
leon de boer11-Jun-18 4:04
leon de boer11-Jun-18 4:04 
GeneralRe: Advice on designing a simple task scheduler in embedded C, that can handle asynchronuous tasks? Pin
arnold_w11-Jun-18 9:38
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AnswerRe: Advice on designing a simple task scheduler in embedded C, that can handle asynchronuous tasks? Pin
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QuestionC# combo box text color change Pin
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AnswerRe: C# combo box text color change Pin
Richard Andrew x648-Jun-18 10:54
professionalRichard Andrew x648-Jun-18 10:54 
Questionusing dynamic_cast with template classes. Pin
Tarun Jha5-Jun-18 1:48
Tarun Jha5-Jun-18 1:48 
//  Demonstrate dynamic_cast on template classes.
#include <iostream>
using namespace std;

template <class T>
class Num {
protected:
    T val;
public:
    Num(T x) { val = x;}
    virtual T getval() {    return val;    }
};

template <class T>
class SqrNum : public Num<T> {
public:
    SqrNum(T x) : Num<T>(x) {}
    T getval()  {   return (val * val);   }
};

int main(){
    Num<int> *bp, numInt_ob(2);
    SqrNum<int> *dp, sqrInt_ob(3);
    Num<double> numDouble_ob(3.3);

    bp = dynamic_cast<Num<int>*> (&sqrInt_ob);          //sqrInt_ob is from a derived class of Num<int>.
    if(bp) {
        cout << "Cast from sqrNum<int>* to Num<int>* OK.\n"
             << "Value is " << bp->getval() << endl;
    }
    else
        cout << "Error !\n\n";

    dp = dynamic_cast<SqrNum<int>> (&numInt_ob);        //numInt_ob is base class object and SqrNum is a derived class.
    if(dp)
        cout << "Error !\n";
    else {
        cout << "Cast from Num<int>* to SqrNum<int>* not OK.\n"
             << "Can't cast a pointer to a base object into\n"
             << "a pointer to a derived object\n\n";
    }

    bp = dynamic_cast<Num<int>*> (&numDouble_ob);        //Num<int> of type int & numDouble_ob is of type Num<double>
    if(bp)
        cout << "Error" << endl;
    else {
        cout << "Can't cast from Num<double>* to Num<int>*.\n"
             << "These are 2 different types.\n\n";
    }

    return 0;
}


in the code above i m getting error that
Quote:
error: 'val' was not declared in this scope
T getval() { return (val val); }
^~~


but
Quote:
class SqrNum : public Num<t>

according to this the protected value in the base class should just work fine as protected value in the derived class, but it isn't ?
How do i solve this problem ?

EDIT :
below is the working code:

//  Demonstrate dynamic_cast on template classes.
#include <iostream>
using namespace std;

template <class T>
class Num {
protected:
    T val;
public:
    Num(T x) { val = x;}
    virtual T getval() {    return val;    }
};

template <class T>
class SqrNum : public Num<T> {
public:
    SqrNum(T x) : Num<T>(x) {}
    T getval()  {   return (Num<T>::val * Num<T>::val);   }
};

int main(){
    Num<int> *bp, numInt_ob(2);
    SqrNum<int> *dp, sqrInt_ob(3);
    Num<double> numDouble_ob(3.3);

    bp = dynamic_cast<Num<int>*> (&sqrInt_ob);          //sqrInt_ob is from a derived class of Num<int>.
    if(bp) {
        cout << "Cast from sqrNum<int>* to Num<int>* OK.\n"
             << "Value is " << bp->getval() << endl;
    }
    else
        cout << "Error !\n\n";

    dp = dynamic_cast<SqrNum<int>*> (&numInt_ob);        //numInt_ob is base class object and SqrNum is a derived class.
    if(dp)
        cout << "Error !\n";
    else {
        cout << "Cast from Num<int>* to SqrNum<int>* not OK.\n"
             << "Can't cast a pointer to a base object into\n"
             << "a pointer to a derived object\n\n";
    }

    bp = dynamic_cast<Num<int>*> (&numDouble_ob);        //Num<int> of type int & numDouble_ob is of type Num<double>
    if(bp)
        cout << "Error" << endl;
    else {
        cout << "Can't cast from Num<double>* to Num<int>*.\n"
             << "These are 2 different types.\n\n";
    }

    return 0;
}

Thank you

modified 6-Jun-18 0:49am.

AnswerRe: using dynamic_cast with template classes. Pin
Richard MacCutchan5-Jun-18 3:20
mveRichard MacCutchan5-Jun-18 3:20 
GeneralRe: using dynamic_cast with template classes. Pin
Tarun Jha5-Jun-18 8:31
Tarun Jha5-Jun-18 8:31 
GeneralRe: using dynamic_cast with template classes. Pin
Richard MacCutchan5-Jun-18 21:00
mveRichard MacCutchan5-Jun-18 21:00 
AnswerRe: using dynamic_cast with template classes. Pin
CPallini5-Jun-18 11:03
mveCPallini5-Jun-18 11:03 
GeneralRe: using dynamic_cast with template classes. Pin
Tarun Jha5-Jun-18 18:45
Tarun Jha5-Jun-18 18:45 
GeneralRe: using dynamic_cast with template classes. Pin
CPallini5-Jun-18 21:22
mveCPallini5-Jun-18 21:22 
GeneralRe: using dynamic_cast with template classes. Pin
Tarun Jha6-Jun-18 3:11
Tarun Jha6-Jun-18 3:11 
GeneralRe: using dynamic_cast with template classes. Pin
CPallini6-Jun-18 22:26
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QuestionDevice manager in windows. Pin
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SuggestionRe: Device manager in windows. Pin
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GeneralTiniest portable executable Pin
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GeneralRe: Tiniest portable executable Pin
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Questioni would like to be a programmer Pin
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SuggestionRe: i would like to be a programmer Pin
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