Re: How to handle multiple exceptions(Try..Catch) - C# Discussion Boards

Re: How to handle multiple exceptions(Try..Catch)

Richard Deeming19-Sep-17 5:57

19-Sep-17 5:57

Firstly, that's not a valid XML document. You either need to remove the closing </AmazonTrackingResponse> tag, or insert the opening tag.

Secondly, you would read it in the same way as any other XML document:

var rspxml = XDocument.Parse("<?xml version=\"1.0\" encoding=\"UTF-8\"?><AmazonTrackingResponse><TrackingErrorInfo><TrackingNumber>12345678</TrackingNumber><TrackingErrorDetail><ErrorDetailCode>ERROR_101</ErrorDetailCode><ErrorDetailCodeDesc>INVALID TRACKING NUMBER</ErrorDetailCodeDesc></TrackingErrorDetail></TrackingErrorInfo></AmazonTrackingResponse>");

var errorInfo = rspxml.Descendants("TrackingErrorInfo").FirstOrDefault();
if (errorInfo != null)
{
    string trackingNumber = (string)errorInfo.Element("TrackingNumber");
    
    var detail = errorInfo.Element("TrackingErrorDetail");
    if (detail != null)
    {
        string errorCode = (string)detail.Element("ErrorDetailCode");
        string errorMessage = (string)detail.Element("ErrorDetailCodeDesc");
        // Do something with the error details...
    }
}

As for the XmlDocument vs XDocument, I'd suggest choosing one and sticking to it. The XDocument is generally easier to work with.

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Re: How to handle multiple exceptions(Try..Catch)

Bootzilla3319-Sep-17 6:05

Bootzilla33

19-Sep-17 6:05

Yeah I just post part of that tag. I didn't want to post the entire thing so that's why the beginning tag isn't showing here.

Also how would I check for errors on

rspxml.Root.Add(new XElement("APIVersion", "4.0"));

and I have an error code for if 'XML is not well formed', how would I do that one.

And thanks on using one between XMLDocument or XDocument.

modified 19-Sep-17 12:13pm.

Re: How to handle multiple exceptions(Try..Catch)

Bootzilla3319-Sep-17 9:58

Bootzilla33

19-Sep-17 9:58

rspxml.Root.Add(
    new XElement("API", "4.0"),
    new XElement("PackageTrackingInfo",
        new XElement("TrackingNumber", prc.ProNumber)
    ),
    new XElement("PackageDestinationLocation",
        new XElement("City", prc.Consignee),
        new XElement("StateProvince", prc.Consignee),
        new XElement("PostalCode", prc.Consignee),
        new XElement("CountryCode", prc.Consignee)
    ),
    new XElement("PackageDeliveryDate",
        new XElement("ScheduledDeliveryDate", prc.Consignee),
        new XElement("ReScheduledDeliveryDate", prc.Consignee)
    ),
    new XElement("TrackingEventHistory",
        prc.History.Select(item => new XElement("TrackingEventDetail",
            // TODO: Use the correct properties from the item, which weren't shown in your code:
            new XElement("EventStatus", item.EventStatus),
            new XElement("EventReason", item.EventReason),
            new XElement("EventDateTime", item.EventDateTime),
            new XElement("EventLocation", item.EventLocation)
        )
    )
);

@RichardDeeming, Question about this code. On the

new XElement("TrackingEventHistory",
        prc.History.Select(item => new XElement("TrackingEventDetail",

line what should that be because you have .Select but that gives me an error 'Shipment.HistoryCollection' does not contain a definition for 'Select' and no extension method 'Select' accepting a first argument of type 'Shipment.HistoryCollection' could be found (are you missing a using directive or an assembly reference?)

Is that code I should use and need to add something to eliminate the error. What I was thinking it should be is:

new XElement("TrackingEventHistory",
         new XElement("TrackingEventDetail",
            // TODO: Use the correct properties from the item, which weren't shown in your code:
            new XElement("EventStatus", prc.History),
            new XElement("EventReason", prc.History),
            new XElement("EventDateTime", prc.History),
            new XElement("EventLocation", prc.History)

Re: How to handle multiple exceptions(Try..Catch)

eddieangel19-Sep-17 12:18

eddieangel

19-Sep-17 12:18

Select is a Linq statement.

Try adding the proper using statement to the top of your class.

using System.Linq;
using System.Xml.Linq;

If those do not work you may need to cast your object to something else.

Re: How to handle multiple exceptions(Try..Catch)

Bootzilla3320-Sep-17 2:56

Bootzilla33

20-Sep-17 2:56

I already have these

using System.Linq;
using System.Xml.Linq;

You mentioned Cast to something else but not sure what to do there. Anyone else with any suggestions would be appreciated.If no one has any suggestions then I will have to go back to the ToString code I had previously and just go with that.
This is what I have now:

 public string ProcessXML(string xmlRequest)
        {
            XDocument rspxml = null;
            try
            {
                if (bool.Parse(WebConfigurationManager.AppSettings["Debug"]) == true)
                    File.WriteAllText(Path.Combine(Server.MapPath("Log"), DateTime.Now.ToString("MMddyyy_HHmmss") + ".xml"), xmlRequest);
                // Determine Method to Call
                XmlDocument doc = new XmlDocument();
                doc.XmlResolver = null;
                doc.LoadXml(xmlRequest);

                string method = doc.FirstChild.Name;
                XmlNode mainNode = doc.FirstChild;

                if (method.ToLower() == "xml")
                {
                    method = doc.FirstChild.NextSibling.Name;
                    mainNode = doc.FirstChild.NextSibling;
                }

                if (method == "AmazonTrackingRequest")
                {
                    Saia.Data.General.Shipment prc = new Data.General.Shipment();
                    string pronum = mainNode.SelectSingleNode("TrackingNumber").InnerText;
                    prc.GetByProNumber(decimal.Parse(pronum));

                    if (string.IsNullOrEmpty(pronum))
                    {
                        rspxml = XDocument.Parse("<?xml version=\"1.0\" encoding=\"UTF - 8\"?><AmazonTrackingResponse xmlns: xsi = 'http://www.w3.org/2001/XMLSchema-instance'xsi: noNamespaceSchemaLocation='AmazonTrackingResponse.xsd'><APIVersion >4.0</APIVersion><TrackingErrorInfo><TrackingNumber>12345678</TrackingNumber><TrackingErrorDetail><ErrorDetailCode>ERROR_101</ErrorDetailCode><ErrorDetailCodeDesc>INVALID TRACKING NUMBER</ErrorDetailCodeDesc></TrackingErrorDetail></TrackingErrorInfo></AmazonTrackingResponse>");
                    }
                    else
                    {
                        decimal tn = 0.0m;

                        if (decimal.TryParse(pronum, out tn))

                        {
                            prc.GetByProNumber(tn);
                        }
                        else
                        {
                            Console.WriteLine("Unable to parse '{0}'.", pronum);
                        }
                    }


                    rspxml = XDocument.Parse("<AmazonTrackingResponse xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xsi:noNamespaceSchemaLocation='AmazonTrackingResponse.xsd'></AmazonTrackingResponse>");
                    rspxml.Root.Add(new XElement("APIVersion", "4.0"));

                    var errorInfo = rspxml.Descendants("TrackingErrorInfo").FirstOrDefault();
                    if (errorInfo != null)
                    {
                        string packtrackinginfo = (string)errorInfo.Element("PackageTrackingInfo");

                        var detail = errorInfo.Element("TrackingErrorDetail");
                        if (detail != null)
                        {
                            string errorCode = (string)detail.Element("ErrorDetailCode");
                            string errorMessage = (string)detail.Element("ErrorDetailCodeDesc");
                            // Do something with the error details...
                        }
                    }


        rspxml.Root.Add(
        new XElement("API", "4.0"),
        new XElement("PackageTrackingInfo",
            new XElement("TrackingNumber", prc.ProNumber)
        ),
        new XElement("PackageDestinationLocation",
            new XElement("City", prc.Consignee),
            new XElement("StateProvince", prc.Consignee),
            new XElement("PostalCode", prc.Consignee),
            new XElement("CountryCode", prc.Consignee)
        ),
        new XElement("PackageDeliveryDate",
            new XElement("ScheduledDeliveryDate", prc.Consignee),
            new XElement("ReScheduledDeliveryDate", prc.Consignee)
        ),
        new XElement("TrackingEventHistory",
            new XElement("TrackingEventDetail",
            new XElement("EventStatus", prc.History),
            new XElement("EventReason", prc.History),
            new XElement("EventDateTime", prc.History)

        ),
         new XElement("EventLocation",
            new XElement("Street1", prc.History),
            new XElement("City", prc.History),
            new XElement("StateProvince", prc.History),
            new XElement("PostalCode", prc.History),
            new XElement("CountryCode", prc.History),
            new XElement("SignedForByName", prc.History)
        ),
         new XElement("PickupStoreInfo",
         new XElement("PickupDueDateDetails",
            new XElement("Date", prc.History),
            new XElement("UTCOffset", prc.History)
        ),
         new XElement("PickupID",
         new XElement("StoreName",
         new XElement("LocationID",
         new XElement("StoreLocation",
            new XElement("Street1", prc.History),
            new XElement("City", prc.History),
            new XElement("StateProvince", prc.History),
            new XElement("PostalCode", prc.History),
            new XElement("CountryCode", prc.History)
         )
         )
         )
         )
         )
         )
         );
                 

                    }


                
            }

            
            catch (CodeException e)
            {
                rspxml = XDocument.Parse("<?xml version=\"1.0\" encoding=\"UTF - 8\"?><AmazonTrackingResponse xmlns: xsi = 'http://www.w3.org/2001/XMLSchema-instance'xsi: noNamespaceSchemaLocation='AmazonTrackingResponse.xsd'><APIVersion>4.0</APIVersion ><TrackingErrorInfo><TrackingNumber>12345678</TrackingNumber><TrackingErrorDetail><ErrorDetailCode>ERROR_203</ErrorDetailCode><ErrorDetailCodeDesc>XML DOCUMENT NOT WELL FORMED</ErrorDetailCodeDesc></TrackingErrorDetail></TrackingErrorInfo></AmazonTrackingResponse>");
                Core.Framework.Debug.CodeException(xmlRequest, e);
            }
            catch (Exception e)
            {
                rspxml = XDocument.Parse("<?xml version=\"1.0\" encoding=\"UTF - 8\"?><AmazonTrackingResponse xmlns: xsi = 'http://www.w3.org/2001/XMLSchema-instance'xsi: noNamespaceSchemaLocation='AmazonTrackingResponse.xsd'><APIVersion>4.0</APIVersion ><TrackingErrorInfo><TrackingNumber>12345678</TrackingNumber><TrackingErrorDetail><ErrorDetailCode>ERROR_203</ErrorDetailCode><ErrorDetailCodeDesc>XML DOCUMENT NOT WELL FORMED</ErrorDetailCodeDesc></TrackingErrorDetail></TrackingErrorInfo></AmazonTrackingResponse>");
                Core.Framework.Debug.Exception(xmlRequest, e);
            }

            return rspxml.ToString();
        }
        public class EventCode
        {
            public enum EvCodes {Delivered, DispatchedForDelivery, DepartedFromTerminal, ArrivedAtDestinationTerminal, DNF};
            public static void Main()
            {
                string val = "Dispatched For Delivery";
                switch ((EvCodes)Enum.Parse(typeof(EvCodes), val.Replace(" ", "")))
                {
                    case EvCodes.DispatchedForDelivery:
                    case EvCodes.Delivered:
                        Console.WriteLine("EVENT_301");
                        break;
                    case EvCodes.DepartedFromTerminal:
                        Console.WriteLine("EVENT_202");
                        break;
                    case EvCodes.ArrivedAtDestinationTerminal:
                        Console.WriteLine("EVENT_202");
                        break;
                    case EvCodes.DNF:
                        Console.WriteLine("EVENT_101");
                        Console.WriteLine("EVENT_102");
                        break;
                   
                    default:
                        break;
                }

            }
        }
    }
}

modified 20-Sep-17 9:27am.

Re: How to handle multiple exceptions(Try..Catch)

Richard Deeming20-Sep-17 10:01

Richard Deeming

20-Sep-17 10:01

What interfaces are implemented by Shipment.HistoryCollection?

Presumably it implements IEnumerable, but not IEnumerable<T>; in which case, you need to insert a call to Cast[^] before the call to Select:

new XElement("TrackingEventHistory",
    prc.History.Cast<Saia.Data.General.Shipment.HistoryItem>().Select(item => new XElement("TrackingEventDetail",
        // TODO: Use the correct properties from the item, which weren't shown in your code:
        new XElement("EventStatus", item.EventStatus),
        new XElement("EventReason", item.EventReason),
        new XElement("EventDateTime", item.EventDateTime),
        new XElement("EventLocation", item.EventLocation)
    )
)

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Re: How to handle multiple exceptions(Try..Catch)

Bootzilla3321-Sep-17 3:58

Bootzilla33

21-Sep-17 3:58

OK this is what I have now and it seems to be working. A couple of questions/issues:

1. If you look at the commented out code below with the .ToString, I have PickupStoreInfo and then PickupDueDateDetails which is setup similar to the TrackingEventHistory and TrackingEventDetail, so would that be set up the same way with the Cast or should that be setup differently or is it ok like it is now.

rspxml.Root.Add(new XElement("PickupStoreInfo"));
                    //    rspxml.Root.Add(new XElement("PickupDueDateDetails"));
                    //    rspxml.Root.Element("PickupDueDateDetails").Add(new XElement("Date", prc.History.ToString()));
                    //    rspxml.Root.Element("PickupDueDateDetails").Add(new XElement("UTCOffset", prc.History.ToString()));

2. You mentioned about using one of either XDocument or XmlDocument, I tried this and when I change to XDocument on this line:

XmlDocument doc = new XmlDocument();

I get errors 'XDocument' does not contain a definition for 'XmlResolver' and no extension method 'XmlResolver' accepting a first argument of type 'XDocument' could be found (are you missing a using directive or an assembly reference?).

Same error definition for FirstChild, LoadXML.

If I change everything to XmlDocument like on this line from XDocument to XmlDocument:

rspxml = XDocument.Parse

I get 'XmlDocument does not contain definition for 'Parse'.

3.Is all of my syntax correct, specifically all of the parentheses after this line:

new XElement("CountryCode", prc.History)

I really appreciate all of your help and look forward to your response.

Here is the full code for this method:

public string ProcessXML(string xmlRequest)
        {
            XDocument rspxml = null;
            try
            {
                if (bool.Parse(WebConfigurationManager.AppSettings["Debug"]) == true)
                    File.WriteAllText(Path.Combine(Server.MapPath("Log"), DateTime.Now.ToString("MMddyyy_HHmmss") + ".xml"), xmlRequest);
                // Determine Method to Call
                XmlDocument doc = new XmlDocument();
                doc.XmlResolver = null;
                doc.LoadXml(xmlRequest);

                string method = doc.FirstChild.Name;
                XmlNode mainNode = doc.FirstChild;

                if (method.ToLower() == "xml")
                {
                    method = doc.FirstChild.NextSibling.Name;
                    mainNode = doc.FirstChild.NextSibling;
                }

                if (method == "AmazonTrackingRequest")
                {
                    Saia.Data.General.Shipment prc = new Data.General.Shipment();
                    string pronum = mainNode.SelectSingleNode("TrackingNumber").InnerText;
                    prc.GetByProNumber(decimal.Parse(pronum));

                    if (string.IsNullOrEmpty(pronum))
                    {
                        rspxml = XDocument.Parse("<?xml version=\"1.0\" encoding=\"UTF - 8\"?><AmazonTrackingResponse xmlns: xsi = 'http://www.w3.org/2001/XMLSchema-instance'xsi: noNamespaceSchemaLocation='AmazonTrackingResponse.xsd'><APIVersion >4.0</APIVersion><TrackingErrorInfo><TrackingNumber>12345678</TrackingNumber><TrackingErrorDetail><ErrorDetailCode>ERROR_101</ErrorDetailCode><ErrorDetailCodeDesc>INVALID TRACKING NUMBER</ErrorDetailCodeDesc></TrackingErrorDetail></TrackingErrorInfo></AmazonTrackingResponse>");
                    }
                    else
                    {
                        decimal tn = 0.0m;

                        if (decimal.TryParse(pronum, out tn))

                        {
                            prc.GetByProNumber(tn);
                        }
                        else
                        {
                            Console.WriteLine("Unable to parse '{0}'.", pronum);
                        }
                    }


                    rspxml = XDocument.Parse("<AmazonTrackingResponse xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xsi:noNamespaceSchemaLocation='AmazonTrackingResponse.xsd'></AmazonTrackingResponse>");
                    rspxml.Root.Add(new XElement("APIVersion", "4.0"));

                    var errorInfo = rspxml.Descendants("TrackingErrorInfo").FirstOrDefault();
                    if (errorInfo != null)
                    {
                        string packtrackinginfo = (string)errorInfo.Element("PackageTrackingInfo");

                        var detail = errorInfo.Element("TrackingErrorDetail");
                        if (detail != null)
                        {
                            string errorCode = (string)detail.Element("ErrorDetailCode");
                            string errorMessage = (string)detail.Element("ErrorDetailCodeDesc");
                            // Do something with the error details...
                        }
                    }


        rspxml.Root.Add(
        new XElement("API", "4.0"),
        new XElement("PackageTrackingInfo",
            new XElement("TrackingNumber", prc.ProNumber)
        ),
        new XElement("PackageDestinationLocation",
            new XElement("City", prc.Consignee),
            new XElement("StateProvince", prc.Consignee),
            new XElement("PostalCode", prc.Consignee),
            new XElement("CountryCode", prc.Consignee)
        ),
        new XElement("PackageDeliveryDate",
            new XElement("ScheduledDeliveryDate", prc.Consignee),
            new XElement("ReScheduledDeliveryDate", prc.Consignee)
        ),
        new XElement("TrackingEventHistory", 
        prc.History.Cast<Saia.Data.General.Shipment.HistoryItem>().Select(item => new XElement("TrackingEventDetail",
            new XElement("EventStatus", prc.History,
            new XElement("EventReason", prc.History),
            new XElement("EventDateTime", prc.History)

        ),
         new XElement("EventLocation",
            new XElement("Street1", prc.History),
            new XElement("City", prc.History),
            new XElement("StateProvince", prc.History),
            new XElement("PostalCode", prc.History),
            new XElement("CountryCode", prc.History),
            new XElement("SignedForByName", prc.History)
        ),
         new XElement("PickupStoreInfo",
         new XElement("PickupDueDateDetails",
            new XElement("Date", prc.History),
            new XElement("UTCOffset", prc.History)
        ),
         new XElement("PickupID",
         new XElement("StoreName",
         new XElement("LocationID",
         new XElement("StoreLocation",
            new XElement("Street1", prc.History),
            new XElement("City", prc.History),
            new XElement("StateProvince", prc.History),
            new XElement("PostalCode", prc.History),
            new XElement("CountryCode", prc.History)
         )
         )
         )
         )
         )
         )
         )
         )
         );
         
         

   

                    //rspxml.Root.Add(new XElement("PackageTrackingInfo"));
                    //rspxml.Root.Element("PackageTrackingInfo").Add(new XElement("TrackingNumber", prc.ProNumber.ToString()));
                    //rspxml.Root.Add(new XElement("PackageDestinationLocation"));
                    //rspxml.Root.Element("PackageDestinationLocation").Add(new XElement("City", prc.Consignee.ToString()));
                    //rspxml.Root.Element("PackageDestinationLocation").Add(new XElement("StateProvince", prc.Consignee.ToString()));
                    //rspxml.Root.Element("PackageDestinationLocation").Add(new XElement("PostalCode", prc.Consignee.ToString()));
                    //rspxml.Root.Element("PackageDestinationLocation").Add(new XElement("CountryCode", prc.Consignee.ToString()));
                    //rspxml.Root.Add(new XElement("PackageDeliveryDate"));
                    //rspxml.Root.Element("PackageDeliveryDate").Add(new XElement("ScheduledDeliveryDate", prc.Consignee.ToString()));
                    //rspxml.Root.Element("PackageDeliveryDate").Add(new XElement("ReScheduledDeliveryDate", prc.Consignee.ToString()));
                    //rspxml.Root.Add(new XElement("TrackingEventHistory"));
                    //foreach (Saia.Data.General.Shipment.HistoryItem itm in prc.History)
                    //{
                    //    rspxml.Root.Add(new XElement("TrackingEventDetail"));
                    //    rspxml.Root.Element("TrackingEventDetail").Add(new XElement("EventStatus", prc.History.ToString()));
                    //    rspxml.Root.Element("TrackingEventDetail").Add(new XElement("EventReason", prc.History.ToString()));
                    //    rspxml.Root.Element("TrackingEventDetail").Add(new XElement("EventDateTime", prc.History.ToString()));
                    //    rspxml.Root.Add(new XElement("EventLocation"));
                    //    rspxml.Root.Element("EventLocation").Add(new XElement("Street1", prc.History.ToString()));
                    //    rspxml.Root.Element("EventLocation").Add(new XElement("City", prc.History.ToString()));
                    //    rspxml.Root.Element("EventLocation").Add(new XElement("StateProvince", prc.History.ToString()));
                    //    rspxml.Root.Element("EventLocation").Add(new XElement("PostalCode", prc.History.ToString()));
                    //    rspxml.Root.Element("EventLocation").Add(new XElement("CountryCode", prc.History.ToString()));
                    //    rspxml.Root.Element("TrackingEventDetail").Add(new XElement("SignedForByName", prc.History.ToString()));
                    //    rspxml.Root.Add(new XElement("PickupStoreInfo"));
                    //    rspxml.Root.Add(new XElement("PickupDueDateDetails"));
                    //    rspxml.Root.Element("PickupDueDateDetails").Add(new XElement("Date", prc.History.ToString()));
                    //    rspxml.Root.Element("PickupDueDateDetails").Add(new XElement("UTCOffset", prc.History.ToString()));
                    //    rspxml.Root.Add(new XElement("PickupID"));
                    //    rspxml.Root.Add(new XElement("StoreName"));
                    //    rspxml.Root.Add(new XElement("LocationID"));
                    //    rspxml.Root.Add(new XElement("StoreLocation"));
                    //    rspxml.Root.Element("StoreLocation").Add(new XElement("Street1", prc.History.ToString()));
                    //    rspxml.Root.Element("StoreLocation").Add(new XElement("City", prc.History.ToString()));
                    //    rspxml.Root.Element("StoreLocation").Add(new XElement("StateProvince", prc.History.ToString()));
                    //    rspxml.Root.Element("StoreLocation").Add(new XElement("PostalCode", prc.History.ToString()));
                    //    rspxml.Root.Element("StoreLocation").Add(new XElement("CountryCode", prc.History.ToString()));

                    }


                
            }

            
            catch (CodeException e)
            {
                rspxml = XDocument.Parse("<?xml version=\"1.0\" encoding=\"UTF - 8\"?><AmazonTrackingResponse xmlns: xsi = 'http://www.w3.org/2001/XMLSchema-instance'xsi: noNamespaceSchemaLocation='AmazonTrackingResponse.xsd'><APIVersion>4.0</APIVersion ><TrackingErrorInfo><TrackingNumber>12345678</TrackingNumber><TrackingErrorDetail><ErrorDetailCode>ERROR_203</ErrorDetailCode><ErrorDetailCodeDesc>XML DOCUMENT NOT WELL FORMED</ErrorDetailCodeDesc></TrackingErrorDetail></TrackingErrorInfo></AmazonTrackingResponse>");
                Core.Framework.Debug.CodeException(xmlRequest, e);
            }
            catch (Exception e)
            {
                rspxml = XDocument.Parse("<?xml version=\"1.0\" encoding=\"UTF - 8\"?><AmazonTrackingResponse xmlns: xsi = 'http://www.w3.org/2001/XMLSchema-instance'xsi: noNamespaceSchemaLocation='AmazonTrackingResponse.xsd'><APIVersion>4.0</APIVersion ><TrackingErrorInfo><TrackingNumber>12345678</TrackingNumber><TrackingErrorDetail><ErrorDetailCode>ERROR_203</ErrorDetailCode><ErrorDetailCodeDesc>XML DOCUMENT NOT WELL FORMED</ErrorDetailCodeDesc></TrackingErrorDetail></TrackingErrorInfo></AmazonTrackingResponse>");
                Core.Framework.Debug.Exception(xmlRequest, e);
            }

            return rspxml.ToString();
        }

Re: How to handle multiple exceptions(Try..Catch)

Richard Deeming21-Sep-17 4:32

Richard Deeming

21-Sep-17 4:32

1) It's not clear what you're trying to do here. You're not adding an element for each history item, so you don't need the Select; you just need to pass in the correct values to the elements.

rspxml.Root.Add(new XElement("PickupDueDateDetails"),
    new XElement("Date", prc.PickupDueDate),
    new XElement("UTCOffset", prc.PickupDueDateOffset)
);

2) You can't just change the type and expect the existing code to work. You need to fix the existing code to use the correct methods for the type.

For example, this:

XmlDocument doc = new XmlDocument();
doc.XmlResolver = null;
doc.LoadXml(xmlRequest);

would become:

XDocument doc = XDocument.Parse(xmlResult);

This:

string method = doc.FirstChild.Name;
XmlNode mainNode = doc.FirstChild;

if (method.ToLower() == "xml")
{
    method = doc.FirstChild.NextSibling.Name;
    mainNode = doc.FirstChild.NextSibling;
}

would become:

XElement mainNode = doc.Root;
string method = mainNode.Name.LocalName;
// No need to check for the processing instruction here...

This:

string pronum = mainNode.SelectSingleNode("TrackingNumber").InnerText;

would become:

string pronum = (string)mainNode.Element("TrackingNumber");

3) I don't know. Does it compile? Does it do what you expect it to do?

I very much doubt that prc.History is the correct property to use for all of those elements.

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Re: How to handle multiple exceptions(Try..Catch)

Bootzilla3321-Sep-17 4:52

Bootzilla33

21-Sep-17 4:52

1) This may help explain. This is some of the XML I am trying to write out:

XML

</PackageDeliveryDate>
<TrackingEventHistory>
<TrackingEventDetail>
<EventStatus>LK</EventStatus>
<EventReason>AQ</EventReason>
<EventDateTime>2004-08-22T11:00:00-
08:00</EventDateTime>
<EventLocation>
<City>SEATTLE</City>
<StateProvince>WA</StateProvince>
<PostalCode>98107</PostalCode>
<CountryCode>US</CountryCode>
</EventLocation>
<SignedForByName>JOHN GALT</SignedForByName>
</TrackingEventDetail>
<PickupStoreInfo>
<PickupDueDateDetails>
<Date>2004-08-25</Date>
<UTCOffset>-07:00</UTCOffset>
</PickupDueDateDetails>
<PickupID>92253</PickupID>
<StoreName>US-PRI-DEL-03</StoreName>
<LocationID>19632</LocationId>
<StoreLocation>
<Street1>NW Market St</Street1>
<City>SEATTLE</City>
<StateProvince>WA</StateProvince>
<PostalCode>98107</PostalCode>
<CountryCode>US</CountryCode>
</StoreLocation>
</PickupStoreInfo>
</TrackingEventHistory>

Am I doing a rspxml.Root.Add for each section or can I use like this:

new XElement("PickupStoreInfo",
        new XElement("PickupDueDateDetails",
           new XElement("Date", prc.History),
           new XElement("UTCOffset", prc.History)
       ),

So based off this, how would that be written out in the code.

2) I updated the code and that seems to be working ok.

3) It does compile. And yes those are supposed to be prc.History. There are only two elements/fields that I'm concerned with and that is the Consignee and History so yes they should be prc.History. I just need to pull in the fields for in those two areas.

Re: How to handle multiple exceptions(Try..Catch)

Richard Deeming21-Sep-17 5:18

Richard Deeming

21-Sep-17 5:18

Bootzilla33 wrote:

new XElement("PickupStoreInfo",
    new XElement("PickupDueDateDetails",
        new XElement("Date", prc.History),
        new XElement("UTCOffset"</span>, prc.History)
    ),

Since PickupDueDateDetails is a child of PickupStoreInfo, that's the correct way to do it.

But passing prc.History as the value for every node isn't going to produce the correct values in the resulting XML. Instead, you'll get the result of calling prc.History.ToString() inserted into every node.

If you don't need to pass a value in the node, it would be better to not pass a value to it, or exclude it from the document.

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Re: How to handle multiple exceptions(Try..Catch)

Bootzilla3321-Sep-17 5:41

Bootzilla33

21-Sep-17 5:41

I have the same thing for prc.Consignee. So what would you suggest something like this:

),
         new XElement("PickupStoreInfo",
         new XElement("PickupDueDateDetails",
            new XElement("Date"),
            new XElement("UTCOffset")
        ),

I pretty much have to pass a value in the node or else how else would I get the values?

Re: How to handle multiple exceptions(Try..Catch)

Richard Deeming21-Sep-17 6:07

Richard Deeming

21-Sep-17 6:07

If you have to pass a value, then pass the value that the API is expecting. Passing the same (invalid) string for each node will most likely cause the API to return an error.

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Re: How to handle multiple exceptions(Try..Catch)

Bootzilla3321-Sep-17 6:15

Bootzilla33

21-Sep-17 6:15

Richard Deeming wrote:
If you have to pass a value, then pass the value that the API is expecting.

What would that be?

Something like:

new XElement("PickupStoreInfo",
        new XElement("PickupDueDateDetails",
           new XElement("Date", Date),
           new XElement("UTCOffset", UTCOffset)
       ),

Not sure???

Re: How to handle multiple exceptions(Try..Catch)

Richard Deeming21-Sep-17 6:19

Richard Deeming

21-Sep-17 6:19

Pass in the values that the API is expecting you to pass in for the request.

You've presumably read the API documentation? The expected values should be documented there.

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Re: How to handle multiple exceptions(Try..Catch)

Bootzilla3321-Sep-17 6:40

Bootzilla33

21-Sep-17 6:40

Yes i've read it and if that is the case then the values in the API are the same as the XElement so

Here the a piece of the API schema:

XML

<xsd:element
name="EventStatus" type="xsd:string">
<xsd:annotation>
<xsd:documentation>Event Status</xsd:documentation>
</xsd:annotation>
</xsd:element>

I guess it will look like this?

    new XElement("EventStatus", "Event Status"),

),

modified 21-Sep-17 13:50pm.

Re: How to handle multiple exceptions(Try..Catch)

Bootzilla3321-Sep-17 18:19

Bootzilla33

21-Sep-17 18:19

Bootzilla33 wrote:

Here the a piece of the API schema:

XML

<xsd:element
name="EventStatus" type="xsd:string">
<xsd:annotation>
<xsd:documentation>Event Status</xsd:documentation>
</xsd:annotation>
</xsd:element>

I guess it will look like this?

    new XElement("EventStatus", "Event Status"),

),

Just need help with this and I think I'm done.

Re: How to handle multiple exceptions(Try..Catch)

Bootzilla3322-Sep-17 2:54

Bootzilla33

22-Sep-17 2:54

Someone please help me with this. I would greatly appreciate it.

Thanks

Re: How to handle multiple exceptions(Try..Catch)

eddieangel19-Sep-17 6:07

eddieangel

19-Sep-17 6:07

The old adage Exceptions should be Exceptional applies here. Rather than using multiple try ... catch blocks, my advice is to validate your known inputs up front. While I personally find it ugly to use a series of If (!x) { return; } it is a solid method of keeping your code simple and implicit. I am not sure what the bold issue is because you are using static values so I don't know what you would catch there. Starting at the third element, though, I would advocate writing a validator of some sort to validate the Shipment object.

And to possibly save you some grief, might I suggest cutting out some of the craziness and just using a serializer to serialize the shipment object? IT can save you a TON of grief trying to validate the XML> If you can't serialize the Shipment directly because of schema differences, try creating a DTO that matches the XML you want and serializing that.

Working with raw XML like this should be a last resort.

That is my 2c

Re: How to handle multiple exceptions(Try..Catch)

Bootzilla3319-Sep-17 6:14

Bootzilla33

19-Sep-17 6:14

@eddieangel,

how would you code what I'm trying to do with API Version, Tracking Number using If (!x) {return}?

Re: How to handle multiple exceptions(Try..Catch)

eddieangel19-Sep-17 6:30

eddieangel

19-Sep-17 6:30

I am not sure what the validation looks like for your situation, but there are a couple of methods.

The most simple is to validate to see if the string exists.

if (string.isNullOrEmpty(apiVariableName)) { return ; }

Since the first two bold items are static text there really isn't anything to validate there unless there is something else we aren't seeing. That said, one of the best methods to validate your data is to set validation attributes on your model class (Data.General.Shipment() and write a method that validates that. For example:

internal class Shipment {
        [Required]
        [StringLength(12)]
        public string ShippingNumber { get; set; }

        [Required(ErrorMessage = "City cannot be empty.")]
        public string City { get; set; }

        [Required(ErrorMessage = "Zip is Required")]
        [RegularExpression(@"^\d{5}(-\d{4})?$", ErrorMessage = "Invalid Zip")]
        public string PostalCode { get; set; }
    }

The trick here is that you really want to leave your model validating to the model or validator class and not be trying to validate when you are building the XML. It is good defensive programming to cover null possibilities and such, but you really want to uncomplicate things as much as possible if you are crafting an XML by hand.

Re: How to handle multiple exceptions(Try..Catch)

Bootzilla3319-Sep-17 6:58

Bootzilla33

19-Sep-17 6:58

So where would the model class go in relation to my code. Would it be outside of the XElement code? Before it? After it?

Re: How to handle multiple exceptions(Try..Catch)

eddieangel19-Sep-17 7:17

eddieangel

19-Sep-17 7:17

Your model class already exists, it is the Data.General.Shipment object. All of this is really outside the scope of your original question of multiple try... catch... blocks, though. If you are able it is always good to step back and ask yourself if this is the right approach. DO you really need XML? It is super wordy and a pain to work with, JSON is way better, but again, outside the scope.

To put an easy stamp on your original question, you can have many try catch blocks but it is going to be a very iterative process for you to figure them out and consider all of the permutations. So you have to ask yourself what the goal is. Is there a recovery path through these exceptions or are you trying to send different error messages to the user? Or maybe just log more detail?

Either way if your try/catch is at the point of building out the XML all you are likely to get is XML formatting exceptions, which do not encapsulate your business rules. A couple notes on generally being defensive in the code you have written:

1. Do not use decimal.Parse. Since you are using the null check operator getting the tracking number, you expose the possibility of errors there. Try this:

var prc = new Data.General.Shipment();
                    var node = mainNode.SelectSingleNode("TrackingNumber");

                    if (node == null)
                    {
                        return; // If your method is not void return the appropriate data type, null, false, etc...
                    }

                    decimal trackingNumber;

                    if (!decimal.TryParse(node.InnertText, out trackingNumber))
                    {
                        return; // Same as above with return type
                    }

                    prc.GetByProNumber(trackingNumber);

                    try
                    {
                        rspxml.Root.Add(new XElement("API", "4.0"));
                        rspxml.Root.Add(new XElement("PackageTrackingInfo"));
                        rspxml.Root.Element("PackageTrackingInfo").Add(new XElement("TrackingNumber", prc.ProNumber.ToString())); // These ToString calls are dangerous without first validating the data
                        rspxml.Root.Add(new XElement("PackageDestinationLocation"));
                        rspxml.Root.Element("PackageDestinationLocation").Add(new XElement("City", prc.Consignee.ToString()));
                        rspxml.Root.Element("PackageDestinationLocation").Add(new XElement("StateProvince", prc.Consignee.ToString()));
                        rspxml.Root.Element("PackageDestinationLocation").Add(new XElement("PostalCode", prc.Consignee.ToString()));
                        rspxml.Root.Element("PackageDestinationLocation").Add(new XElement("CountryCode", prc.Consignee.ToString()));
                        // remainder omitted for brevity
                    }
                    catch (NullReferenceException n)
                    {
                        // NullReferenceException is not super helpful but it will tell you there is an error and provides a general catch all.
                        // Log or alert user there is a problem
                        // A more defensive strategy is to validate that prc.Consignee is not null before trying to covnert to a string
                    }

At very least, make sure you validate that the tracking number comes up and hydrates an object.

Re: How to handle multiple exceptions(Try..Catch)

Bootzilla3319-Sep-17 7:28

Bootzilla33

19-Sep-17 7:28

I am using XML because I'm outputting it to AWS. So I don't have a choice unfortunately.

XSL to get only elements which have no childs

MrKBA18-Sep-17 23:27

MrKBA

18-Sep-17 23:27

Hi,
I make my question after some research in web without any clear response to my problem.

I have the following XML and I need to apply an XSL transformation to get only nodes which haven't child.

Input :

<Root_Element Att_Name="XXX">
  <right Id="100">
    <right Id="110" />
    <right Id="111">
      <right Id="112" />
      <right Id="113">
        <right Id="114" />
        <right Id="115" />
      </right>
      <right Id="116" />
    </right>
    <right Id="117">
      <right Id="118" />
      <right Id="119">
        <right Id="120" />
        <right Id="121" />
      </right>
    </right>
  </right>
</Root_Element>

Expected output :

<Root_Element Att_Name="XXX">
    <right Id="110" />
    <right Id="112" />
    <right Id="114" />
    <right Id="115" />
    <right Id="116" />
    <right Id="118" />
    <right Id="120" />
    <right Id="121" />
</Root_Element>

Re: XSL to get only elements which have no childs

Pete O'Hanlon18-Sep-17 23:49

Pete O'Hanlon

18-Sep-17 23:49

What does this have to do with C#? BTW, when you post a question, it helps if you show us what you've already tried. That way, we won't duplicate things you've already ruled out.

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