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Probably couldn't find the library. First, search your system to see if you have that library (look in /usr/lib, /usr/local/lib, or multiarch lib paths[^] if Suse supports them), if you don't find it do an online search to see what package that library is a part of and install that package.
If you find the library in your system already but you're still getting an error, it's also possible that whatever you're running is looking in the wrong location or under the wrong name. For example, if it's looking for libio_misc.so but your system has libio_misc.1.2.0.so (in which case, you just need a symbolic link). If the shared object file is in a non-standard location and you want to add search paths to the loader, you just have to define or add to the LD_LIBRARY_PATH environment variable.
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Hi, I am basically a software developer looking for a laravel based admin template with all the Advanced functionalities which can save my tons of hours of production so that i can develop my projects at a quicker pace,can anyone please suggest me regarding this?
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Hi all,
It's a Nginx and PHP web project, When I run a php script as shell, there shows Access Denide!
X-Powered-By: PHP/7.0.9
Content-type: text/html; charset=UTF-8
Access Denied!
The php file is like this:
#!/usr/bin/php-cgi
<?php
require_once("config.php");
require_once("util.php");
...
..
.
file_put_contents($argv[1], CJSON::encode($obj));
?>
I have try to change all the php file as 777, and try to run like this:
./list.php /home/cache.json
/usr/bin/php list.phph /home/cache.json
Still can not work.
and then I try to make a new php script test.php:
#! /usr/local/php7/bin/php-cgi
<?php
echo "php test";
?>
and then run it:
/usr/local/php7/bin/php-cgi test.php
it works:
[root@localhost ~]# /usr/local/php7/bin/php-cgi test.php
X-Powered-By: PHP/7.0.9
Content-type: text/html; charset=UTF-8
php test
I don't now why, anyone can help? Thanks for advance.
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I think your path to the output file may be wrong. The directory /home is a system directory that contains the user home directories, one for each user. The command ls -l /home will show you what it is and what permissions it has.
Try just:
./list.php cache.json
// or
./list.php ~/cache.json
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hello all,
i am having this issue with trying to connect my php app to sql server and i have edited the php.ini with the required driver needed to the php version 5.5. Below is the error i get anytime i try to connect to the database, i will appreciate if anybody will help with this.
Database connection refused.
Array ( [0] => Array ( [0] => IMSSP [SQLSTATE] => IMSSP [1] => -49 [code] => -49 [2] => This extension requires the ODBC Driver 11 for SQL Server. Access the following URL to download the ODBC Driver 11 for SQL Server for x86: http://go.microsoft.com/fwlink/?LinkId=163712 [message] => This extension requires the ODBC Driver 11 for SQL Server. Access the following URL to download the ODBC Driver 11 for SQL Server for x86: http://go.microsoft.com/fwlink/?LinkId=163712 ) [1] => Array ( [0] => IM002 [SQLSTATE] => IM002 [1] => 0 [code] => 0 [2] => [Microsoft][ODBC Driver Manager] Data source name not found and no default driver specified [message] => [Microsoft][ODBC Driver Manager] Data source name not found and no default driver specified ) )
"
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What part of those instructions are you having a problem with?
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I did the connection from the php using these lines of code "
$serverName = "(THAIWO)";
$connectionInfo = array("Database"=>"examples");
$conn = sqlsrv_connect($serverName,$connectionInfo);
if ($conn){
echo ("Database connection Successful.<br />") ;
}else
{
echo ("Database connection refused.<br />") ;
die(print_r(sqlsrv_errors(), true));
}
"
i did download for
php_pdo_sqlsrv_55_ts.dll
php_pdo_sqlsrv_55_nts.dll
php_sqlsrv_55_ts.dll ,
php_sqlsrv_55_nts.dll
with all these done and checking for solution in the MSDN libary where i used the PDO syntax for connecting to sql server using the function sqlsrv_connect, am still at lost for where am doing things wrong. I want to know why i am refused and the reason for asking for the ODBC driver when i have downloaded and enabled it.
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taiwokaffo wrote: i did download for That's the plugin for PHP, not the ODBC-driver. Follow the link in the instructions, download it and install it.
Bastard Programmer from Hell
If you can't read my code, try converting it here[^]
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Thanks all it now working i used this to connect to the sql server 2012
$serverName = "OurIPAddress";
$connectionInfo = array( "Database"=>"Thenameofourdatabase", "UID"=>"OurID", "PWD"=>"Ourpassword");
$conn = sqlsrv_connect( $serverName, $connectionInfo);
if( $conn ) {
echo "Connection established.<br />";
}else{
echo "Connection could not be established.<br />";
die( print_r( sqlsrv_errors(), true));
}
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Hy everyone ..... I have to select php final year project..... suggest me some unique ideas ...... what sort of application i choose?
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How should we? We have no idea at what level you are, what you have learned, how many time you have to finish and so on...
Skipper: We'll fix it.
Alex: Fix it? How you gonna fix this?
Skipper: Grit, spit and a whole lotta duct tape.
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Choose something that you understand, and is within the limits of your skills and experience.
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where to find your framework...link me
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Hello. I have a list of numbered folders. In each folder there is a lot of .jpg files. I get a list of all including image files from this directories with two glob functions dynamically. I store a list of directory paths and filenames into two separates arrays called $DIR[] and $files[].
<?php
$pathDIR = "dirname/";
$DIR = Array(
);
foreach (glob($pathDIR . '/[0-30]*', GLOB_ONLYDIR) as $dirname) {
$DIR[] = $dirname;
}
for($a = 0; $a < count($DIR); $a++) {
echo $DIR[$a];
}
$pathFILE = Array();
$files = Array();
for($b = 1; $b <= count($DIR); $b++) {
$pathFILE[$b] = "dirname/" . $b . "/";
foreach(glob($pathFILE[$b] . '*.jpg') as $filename) {
$files[] = $filename;
}
}
for($c = 1; $c <= count($files); $c++) {
echo $files[$c-1];
}
?>
I have tried to combine two arrays in one multidimensional array with:
array_push ($DIR, $file);
to display array values I've tried with a pair of loops:
for($d = 0; $d <= count($DIR); $d++) {
for($e = 0; $e <= count($DIR[$d]); $e++) {
echo $DIR[$d][$e];
}
}
unfortunately array values are not properly show. Also, a notice indicate undefined offset .
Thanks a lot for your help.
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My proposition is to modify the code in the following way:
<?php
$pathDIR = "dirname/";
$DIR = Array(
);
foreach (glob($pathDIR . '/[0-30]*', GLOB_ONLYDIR) as $dirname) {
$DIR[] = $dirname;
}
for($a = 0; $a < count($DIR); $a++) {
echo $DIR[$a];
}
$pathFILE = Array();
$files = Array();
for($b = 1; $b <= count($DIR); $b++) {
$pathFILE[$b] = "dirname/" . $b . "/";
$files[$b] = Array();
foreach(glob($pathFILE[$b] . '*.jpg') as $filename) {
$files[$b][] = $filename;
}
}
for($d = 1; $d <= count($files); $d++) {
for($e = 0; $e <= count($files[$d]); $e++) {
echo $files[$d][$e];
}
echo "\r\n\r\n";
}
?>
remember you can display files simlper way:
var_dump($files);
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hy everybody.
I have learn basics in PHP i want to stronger my Object Oriented Concepts In PHP.
Kindly guide me Tutorials .
And what project will be suitable for me to learn things quickly and smartly .... i.e e-commerce or else?? ?
thanks in advance
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AFAIK, PHP is a server side scripting language.
If you want to move to Object Oriented programming, its better to try .net (C#) or Java.
You will get a lot of examples over the internet.
Life is a computer program and everyone is the programmer of his own life.
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Welcome to 2004.
Quote from Wikipedia: On July 13, 2004, PHP 5 was released, [...] PHP 5 included new features such as improved support for object-oriented programming, ... and it's advanced a lot more since then.
Software rusts. Simon Stephenson, ca 1994. So does this signature. me, 2012
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Object-oriented-ism is a concept, not a tool. Any platform can have it if they start following the rules of Object-oriented programming - Wikipedia[^].
Secondly, C# is not a pure object-oriented language either, it just uses the concepts.
The sh*t I complain about
It's like there ain't a cloud in the sky and it's raining out - Eminem
~! Firewall !~
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Sorry dude but php is OOP
Kribo
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Yeah I got a response long back. Thanks for confirming it again.
Life is a computer program and everyone is the programmer of his own life.
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Did you try to Google? A simple Google for "oop in php" would have yielded the following,
Object Oriented Programming in PHP[^].
Quote: And what project will be suitable for me to learn things quickly and smartly .... i.e e-commerce or else?? ? I recommend build applications for your own use. Your own online notes keeping application, your online to-do list, etc. This gives a flexible time to learn and experiment.
The sh*t I complain about
It's like there ain't a cloud in the sky and it's raining out - Eminem
~! Firewall !~
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