Database

17-Sep-12 8:50

You should actually have it in your sig.

Light moves faster than sound. That is why some people appear bright, until you hear them speak.
List of common misconceptions

Re: my SQl

Andrei Straut17-Sep-12 9:45

Andrei Straut

17-Sep-12 9:45

If only you knew how many times a day I think about it... Laugh | :laugh:

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Inline code SQL 2005

Member 916254415-Sep-12 19:52

Member 9162544

15-Sep-12 19:52

I have table A with col1, col2 & table B with col3, col4.

I would like to write a query like

select a.* from A join B on A.col1=B.col3 and A.col2 like col4 + '%'

Is it possible in SQL 2005?

is there a concat function in SQL 2008 or 2005. I have seen it in 2012.

Pls help me.

Thanks in advance

Re: Inline code SQL 2005

Jörgen Andersson16-Sep-12 1:15

format integer number in MySQL

16-Sep-12 1:15

Anything wrong with google today?

Have a look here[^].

String concatenation has been around as long as SQL has. But different dialects have different syntax.
Oracle uses '||', Sql Server uses '+', most implementations can use 'concat(string1, string2)' but not SQL Server AFAIK. Could be wrong about that though.

Light moves faster than sound. That is why some people appear bright, until you hear them speak.
List of common misconceptions

Re: Inline code SQL 2005

Andrei Straut16-Sep-12 23:55

Andrei Straut

16-Sep-12 23:55

Jörgen Andersson wrote:
Anything wrong with google today?

Same impression here, I'm starting to believe I'm the only person with Google access today Smile | :)

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Jassim Rahma15-Sep-12 8:35

Jassim Rahma

15-Sep-12 8:35

Hi,

In MySQL, how can I format a number like this

1000000001

where the first 1 is the weekday and the last one is my LAST_INSERT_ID and I am adding just zeroos to make it always 10 digits?

Re: format integer number in MySQL

Graham Breach15-Sep-12 9:28

Graham Breach

15-Sep-12 9:28

How about this:

SQL

SELECT (DAYOFWEEK(NOW()) * 1E9) + @@LAST_INSERT_ID

Database updates

spankyleo12313-Sep-12 23:55

spankyleo123

13-Sep-12 23:55

Hi,

I want to update the column TID with the top most value of TID as long as MID is the same number.

I want to do this (table after update)

PID SID TID MID RID
3 0 0 4 1
3 NULL 0 4 2
3 NULL 0 4 3
3 NULL 0 4 4
3 NULL 0 4 5
3 NULL 0 4 6
3 NULL 0 4 7
3 4 4 8 1
3 NULL 4 8 2
3 NULL 4 8 3
3 NULL 4 8 4

Below is the actual table before update.

PID SID TID MID RID
3 0 0 4 1
3 NULL NULL 4 2
3 NULL NULL 4 3
3 NULL NULL 4 4
3 NULL NULL 4 5
3 NULL NULL 4 6
3 NULL NULL 4 7
3 4 4 8 1
3 NULL NULL 8 2
3 NULL NULL 8 3
3 NULL NULL 8 4

Any suggestion/solutions deeply appreciated.

Thanks

Re: Database updates

Shameel14-Sep-12 1:31

Shameel

14-Sep-12 1:31

Assuming your DB is SQL Server, you can try this (just out of mind, not tried though)

SQL

UPDATE MyTable A SET A.TID = (SELECT MAX(B.TID) FROM MyTable B WHERE A.MID = B.MID)

Re: Database updates

spankyleo12314-Sep-12 2:12

spankyleo123

14-Sep-12 2:12

Thanks for your help.

I have solved it by creating a view of all 'Not NULL' (top most) rows . Then created a stored proc to loop through the view and update the TID. A long procedure though but it did work.

Cheers !

Update with correlated sub query

David Mujica14-Sep-12 3:16

David Mujica

14-Sep-12 3:16

I think you want to do something like this ...

update table A
set tid = 
(select max(tid) 
from TableA
Group By mid)

Check these for references:
http://msdn.microsoft.com/en-us/library/ms177523.aspx

http://data.bangtech.com/sql/sql_update_with_correlated_subquery.htm

spankyleo12314-Sep-12 3:43

spankyleo123

14-Sep-12 3:43

Hi thanks for your solution and links,

But your query returned an error.

Msg 512, Level 16, State 1, Line 1
Subquery returned more than 1 value. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression.

Jörgen Andersson14-Sep-12 8:55

14-Sep-12 8:55

That's because he forgot a small but important condition.
Try this:

SQL

update table A as a1
set tid = 
(select max(tid) 
from TableA as A2
Where A1.mid = A2.mid
Group By mid)

Light moves faster than sound. That is why some people appear bright, until you hear them speak.
List of common misconceptions

David Mujica15-Sep-12 15:11

David Mujica

15-Sep-12 15:11

Thanks for the refinement to my SQL. Sometimes when you don't have the actual data to test with, you forget some stuff.

Jörgen Andersson16-Sep-12 1:05

16-Sep-12 1:05

David Mujica wrote:
Sometimes when you don't have the actual data to test with, you forget some
stuff.

Tell me about it. Roll eyes | :rolleyes:

That's almost something I can put in my CV.

Light moves faster than sound. That is why some people appear bright, until you hear them speak.
List of common misconceptions

SUM Problem in MSSQL

Basak Oner11-Sep-12 23:41

Basak Oner

11-Sep-12 23:41

Hi everybody,
I have some numbers. Numbers are
(
0
234,9
-27
0
-55,9
0
0
-59
0
100,72
-26
0
-25,72
0
0
0
-82
0
0
0
0
0
0
-134)

I want to this.
SELECT SUM(FIELDX) FROM TBLX

but result is returning (-2,8421709430404007E-14)
actually resutl is 0 (Zero)
How can i solve this problem?

Thanks.

Başak Öner

Eddy Vluggen12-Sep-12 0:16

Eddy Vluggen

12-Sep-12 0:16

Basak Oner wrote:
actually resutl is 0 (Zero)

Not if you're a computer, then it's "almost 0". Try rounding the result.

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if you can't read my code, try converting it here[^]

Basak Oner12-Sep-12 0:27

Basak Oner

12-Sep-12 0:27

sorry I don't understand your message.
I need your detailed explanation.

Thanks.

Eddy Vluggen12-Sep-12 0:31

Eddy Vluggen

12-Sep-12 0:31

Basak Oner wrote:
sorry I don't understand your message.

Try the ROUND function. This is due to how computers work and how they calculate. You know what a fractional number is, but they do not exist within a computer.

Basak Oner wrote:
I need your detailed explanation.

You're not in school anymore. There's an explanation here[^], good luck.

Bastard Programmer from Hell Suspicious | :suss:

if you can't read my code, try converting it here[^]

Basak Oner12-Sep-12 3:58

Basak Oner

12-Sep-12 3:58

Thanks for your free time.

Eddy Vluggen12-Sep-12 6:00

Eddy Vluggen

12-Sep-12 6:00

You actually *read* it?

Ehr.. you're welcome, and yes, well done Smile | :)

Bastard Programmer from Hell Suspicious | :suss:

if you can't read my code, try converting it here[^]

Jörgen Andersson12-Sep-12 1:00