Click here to Skip to main content

C / C++ / MFC

How do I update a Form from a function?

Freddie Code20-May-11 4:53

20-May-11 4:53

I'm using Visual Studio 2005 C++.

I want to update the controls on a form from within a function. The function is in a seperate file from the main form so the function can not "see" the memebers of the form.

Do I have to pass the form to the function? The form controls seem to be "private" to the main form so I dont know if it will allow them to be changed from another function.

Can someone give me some guidance on this, or a sample function call would be great.

Thanks.

Re: How do I update a Form from a function?

Freddie Code20-May-11 6:43

20-May-11 6:43

Figured it out....

You need to go to the Class View, right click on your Form, Add New Function then choose the file that you want to add the function to. Make sure that the file you add the function to is #included into the project. Make sure the file you add the function to has #include "stdafx.h" as the first line of the file.

damage after normal block( #24094)

Sakhalean20-May-11 0:45

20-May-11 0:45

Hi All,

I have declared a pointer type variable of DWORD type in CFormView type class.

I am allocating memory using new DWORD[ records ].

And I am freeing the memory in the destructor using delete[].

But I am getting mfc exception

damage after normal block( #24094)at hex address.

Can any body give me reason why I am getting that exception?

I am not able to trace the problem.

Please help me.

Re: damage after normal block( #24094)

C^hris L^osinger20-May-11 0:56

C^hris L^osinger

20-May-11 0:56

you have written past the end of the memory you allocated.

image processing toolkits | batch image processing

Re: damage after normal block( #24094)

Malli_S20-May-11 1:18

20-May-11 1:18

You've written in the memory block beyond the allocated memory size. If you are using the pointer arithmetic, check for your logic for advancing through the items in the array. Check for your memory writing logic too...

[Delegates] [Virtual Desktop] [Tray Me !]

-Malli...!

matrix Rotation

002comp20-May-11 0:08

20-May-11 0:08

hello Friends

I am having one rotation matrix [3x3] of one object at some position,and then I rotate at some angle that object and i found the rotation matrix[3x3] at that place also.

How can I found the offset of object in matrix[3x3] from one place to other?

And then how can i add the offset to rotation matrix?

I know this is not related to c++ but too many genious are here on this Forum.And after all i have to implement it in c++ Wink | ;)

Wink | ;)

Any Ideas?
Thanks In Advance.
Regards
Yogesh

Re: matrix Rotation

Luc Pattyn20-May-11 1:42

20-May-11 1:42

I'm assuming you have an affine transformation matrix M as defined here[^].

The translation component is in the last column. When you add some number to M[0,2] you shift horizontally; to M[1,2] you shift vertically.

Therefore, if the object gets translated (not rotated, not scaled, not sheared) from one position to another, just look at the difference of the respective M[0,2] and M[1,2] values. BTW: Once a rotation/scaling/shearing occurs in between, the "translation" becomes ambiguous.

Suggestion: whatever transformation you do, watch what it does to the matrix, and things should become pretty clear.

Smile | :)

Smile | :)

Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

Re: matrix Rotation

002comp20-May-11 2:56

20-May-11 2:56

Hello Luc, You are Right..I am using transformation Matrix.

I am having two matrix one with original value and other iwth final matrix values but no idea of getting the difference between them.

Thanks for your reply.

regards
yogesh

Re: matrix Rotation

David Crow20-May-11 3:06

20-May-11 3:06

yogeshs wrote:
I know this is not related to c++...i have to implement it in c++

Yeah, that's not confusing at all. Unsure | :~

Unsure | :~

"One man's wage rise is another man's price increase." - Harold Wilson

"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons

"Some people are making such thorough preparation for rainy days that they aren't enjoying today's sunshine." - William Feather

File creation time

tasumisra19-May-11 22:56

19-May-11 22:56

Hi Guys,

Looking for help in finding Timestamp of a text file.
i have tried googling ,seems Stat can help but dont know how to use it.

any help is much apprciated.

Thank you.

vikas da

Re: File creation time

Richard MacCutchan19-May-11 23:18

Richard MacCutchan

19-May-11 23:18

stat is probably not used so much theses days, GetFileTime()[^] will probably be what you need.

The best things in life are not things.

Re: File creation time

mosealex20-May-11 3:55

20-May-11 3:55

Sorry! Dint get your question.
Do you want file creation time?

Re: File creation time

Richard MacCutchan20-May-11 4:23

Richard MacCutchan

20-May-11 4:23

I didn't post a question, I posted an answer.

The best things in life are not things.

Re: File creation time

Chandrasekharan P19-May-11 23:25

Chandrasekharan P

19-May-11 23:25

Have a look at this
http://msdn.microsoft.com/en-us/library/ms724320%28v=vs.85%29.aspx[^]

john563219-May-11 21:53

19-May-11 21:53

Hi,

I am drwaing image using Image::DrawImage and same image using CDC::BitBlt with same x,y position.
But both methods are drawing image on diffrent axis(x,y). How could I draw on same position for both?

Cool_Dev19-May-11 22:17

19-May-11 22:17

show code snippet or give more info..

john563219-May-11 23:07

19-May-11 23:07

using BitMlt:

CRect rect;
	this->GetWindowRect( &rect );
	this->GetParent()->ScreenToClient( rect );
 CBitmap img;
   CDC dc;
   BITMAP bmp;
   img.LoadBitmap(m_nImageID);
   img.GetBitmap(&bmp);
   CDC* pDC = this->GetDC();
   dc.CreateCompatibleDC(pDC);
   CBitmap* pOld = dc.SelectObject(&img);
pDC->BitBlt(rect.left, rect.top, bmp.bmWidth, bmp.bmHeight, &dc, 0, 0, SRCCOPY);

using Image::DrawImage

CRect rect;
	this->GetWindowRect( &rect );
	this->GetParent()->ScreenToClient( rect );
m_img = Gdiplus::Bitmap::FromResource(GetModuleHandle(0),MAKEINTRESOURCE(nImage));
grpx.DrawImage(m_img, 0, 0, m_img->GetWidth(),m_img->GetHeight());

Richard MacCutchan19-May-11 23:21

Richard MacCutchan

19-May-11 23:21

What are the values of rect.left and rect.top in case 1?

The best things in life are not things.

john563219-May-11 23:26

19-May-11 23:26

left = 50 and top = 50 in both cases

Richard MacCutchan19-May-11 23:54

Richard MacCutchan

19-May-11 23:54

Fine, but in the second case you are drawing at Point(0, 0)!

The best things in life are not things.

tagopi19-May-11 23:27

19-May-11 23:27

grpx.DrawImage(m_img, 0, 0, m_img->GetWidth(),m_img->GetHeight());

why don't you try using same rect.left and rect.top instead of 0,0 in drawimage??

Regards,
Gopinath.

How can i create one button for two events in C# 2008 vs?

FeniksReborn19-May-11 21:27

19-May-11 21:27

Hello

How can i create one button for two events?
For example: I want to have one button for start/stop.
At the beginning of the application button name is start (start the event ), when I click the button second time it change the name to Stop (stop the event)????

I am very new to C# programming, i know to do this in VB6... Sorry for my bad english!
ThankYou

Re: How can i create one button for two events in C# 2008 vs?

Rhuros19-May-11 21:44

19-May-11 21:44

This is in the wrong forum, try the C# forum next door...

Re: How can i create one button for two events in C# 2008 vs?

Peter_in_278019-May-11 22:31

19-May-11 22:31

About the best redirect I've seen here. +5 Smile | :)

Smile | :)

Peter

Software rusts. Simon Stephenson, ca 1994.

Re: How can i create one button for two events in C# 2008 vs?

Rhuros19-May-11 22:37

19-May-11 22:37

glad you liked it... Smile | :)

Smile | :)

General News Suggestion Question Bug Answer Joke Praise Rant Admin

Use Ctrl+Left/Right to switch messages, Ctrl+Up/Down to switch threads, Ctrl+Shift+Left/Right to switch pages.