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QuestionExposing unsafe methods through an interface. PinPopular
thatdiceygirl16-Jan-11 23:47
thatdiceygirl16-Jan-11 23:47 
I am currently working on a project, which will dynamically load in a C++ library and instantiate one of the contained classes through the use of a common interface.

However, one of the methods that I am trying to expose in the C++ library takes the following set of arguments...

C++Library.MethodName(String^ stringVariable, unsigned char sProblemVariable[])


This is where the problem arises.

Now I know the C# equivalent of the unsigned char [] argument is a byte, so I am attempting to use this method in the following manner.

byte[] byteArr = new byte[127];

unsafe
{
   fixed (byte *bytePointer = byteArr)
   {
      int returnValue = Interface.MethodName(aStringVariable, bytePointer);
   }
}


So I am attempting to expose the C++Library.MethodName through the Interface, using the following method signature...

unsafe int MethodName(string stringVariable, byte *problemVariable);


When compiling the C++ Library, implementing the interface, it builds successfully so I assume that the C++ method signature satisfies the C# interface signature.

However, when I attempt to load the C++ Library, I get a Reflection Exception telling me there is no implementation for the MethodName method, in the Library.

Any help would be greatly appreciated!!

Thanks..
A girl in Engineering AND IT?!...what is this nonsense?

AnswerRe: Exposing unsafe methods through an interface. Pin
#realJSOP17-Jan-11 0:32
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GeneralRe: Exposing unsafe methods through an interface. Pin
thatdiceygirl17-Jan-11 3:51
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GeneralRe: Exposing unsafe methods through an interface. Pin
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AnswerRe: Exposing unsafe methods through an interface. Pin
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GeneralRe: Exposing unsafe methods through an interface. Pin
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GeneralRe: Exposing unsafe methods through an interface. PinPopular
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GeneralRe: Exposing unsafe methods through an interface. Pin
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GeneralRe: Exposing unsafe methods through an interface. Pin
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AnswerRe: Exposing unsafe methods through an interface. Pin
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AnswerRe: Exposing unsafe methods through an interface. Pin
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