Regular Expressions

^[^"]*("[^"]*")*[^"]*$

http://www\.google\.com\?(?<QUERY_STRING>.*)

http://www\.google\.com(?=\?)

http://www\.google\.com\??

\<img\>.*?\</img\>

//  using System.Text.RegularExpressions;

/// <summary>
///  Regular expression built for C# on: Mon, Sep 6, 2010, 12:26:15 PM
///  Using Expresso Version: 3.0.3634, http://www.ultrapico.com
///  
///  A description of the regular expression:
///  
///  <%
///      <%
///  Any character that is NOT in this class: [\"], any number of repetitions
///  "
///  [InQuotes]: A named capture group. [.*]
///      Any character, any number of repetitions
///  Match a suffix but exclude it from the capture. [\"]
///      Literal "
///  Any character that is NOT in this class: [%], any number of repetitions
///  %>
///      %>
///  
///
/// </summary>
public static Regex regex = new Regex(
      "<%[^\\\"]*\"(?<InQuotes>.*)(?=\\\")[^%]*%>",
    RegexOptions.IgnoreCase
    | RegexOptions.CultureInvariant
    | RegexOptions.IgnorePatternWhitespace
    | RegexOptions.Compiled
    );


// This is the replacement string
public static string regexReplace = 
      "<Hello>";


//// Replace the matched text in the InputText using the replacement pattern
// string result = regex.Replace(InputText,regexReplace);

//// Split the InputText wherever the regex matches
// string[] results = regex.Split(InputText);

//// Capture the first Match, if any, in the InputText
// Match m = regex.Match(InputText);

//// Capture all Matches in the InputText
// MatchCollection ms = regex.Matches(InputText);

//// Test to see if there is a match in the InputText
// bool IsMatch = regex.IsMatch(InputText);

//// Get the names of all the named and numbered capture groups
// string[] GroupNames = regex.GetGroupNames();

//// Get the numbers of all the named and numbered capture groups
// int[] GroupNumbers = regex.GetGroupNumbers();

OriginalGriff wrote:

It isn't a valid regex.

moein.serpico wrote:

{1}

moein.serpico wrote:

(\s*\w*\s*\W*\s*\d*\s*)*

\[(?<Grp>.*)\]\r\n(?<Keyword>\w+)\s*=\s*(?<Value>.*)\r

(fun)?$