C#

public class GameObject { ... }
public class Chest : GameObject {...}
public class TresureChest: GameObject {...}
...
public void PlayWithObject(GameObject go)
   {
   ...
   }

Chest ch = go as Chest;
if (ch != null)
   {
   ch.OpenChest();
   }

CsTreval wrote:

Is there any other way to do this other than casting it explicitly to a Chest type?

public class ABC
{
    public virtual string DoIt()
    {
        return "ABC";
    }
}

public class XYZ : ABC
{
    public override string DoIt()
    {
        return "XYZ";
    }
}

// Later on...
ABC a = new XYZ();
// str = "XYZ";
string str = a.DoIt();

Chest ch = new GameObject

Duck d = new Animal();
d.Quack(); // Not all animals know how to quack. You need a duck for that.
d = new Cat();
d.Quack(); // Cats can't quack.

public class GameObject
{
    public virtual void OpenGame() {...}
    public virtual void CloseGame() {...}
    //... and some more functions...
}

Muzammil Saeed wrote:

but it is written on the msdn site that constructor is not called.

Richard MacCutchan wrote:

Where did you see that? If you look here[^] it states explicitly that the constructor is called.

Object initializers let you assign values to any accessible fields or properties of an object at creation time without having to explicitly invoke a constructor.

David Skelly wrote:

I think this is what is confusing the OP.