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In Google Maps the location which we are searching should be able to traced on the map first.. If the location doesnot exist on the map then it returns error that place not found. I have recently worked on maps where i was able to get the logitude and latitude of places.
Check the address that you are sending to google map API should be correct 
NainaNaina
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Hi thanks for your concern.
I tried those locations on GOOGLE Maps and it shows it with no problem. For ex: If I put Starbucks in Google Map, it shows several markers but when I try to use it in my application it says not found.
I am not sure whats wrong that I am doing.
Please help...
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| Can i know the location address which you are trying to locate so that i can give a try? Naina
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Sorry for delay.
I have written over there STARBUCKS.
Please look it
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Why i am getting this error
Microsoft JScript runtime error: Sys.InvalidOperationException: Two components with the same id can't be added to the application. for pop up extender.
I upgraded my ajaxcontrol toolkit and this error is displaying to me.
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By reading the error message it simply seems like you (by mistake) have added a component with an ID that another component already has. Check the Id's of the components and make sure there aren't any duplicates.
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If i am using the old ajax binary which is provided as demo in ajax site, then my code is running fine.
but i cannot use that old binary, because my existing ajax contols complains that blah blah property not found.
Can any body suggest how can i use old and new ajax toolkit binary.
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Hi all,
we can use to export a report document to stream by following method,
ReportDocument.ExportToHttpResponse(format,responce,boolattch,attachname);
there is also other method like writing the same to the memory stream and taking out via binary write that is
MemoryStream oStream; // using System.IO
oStream = (MemoryStream)
report.ExportToStream(
CrystalDecisions.Shared.ExportFormatType.PortableDocFormat);
Response.Clear();
Response.Buffer= true;
Response.ContentType = "application/pdf";
Response.BinaryWrite(oStream.ToArray());
Response.End();
the above can be called through button click
and this is the main problem.
in my page due to requirement i have more than one crystal report viewer and obviously more that one report document. my requirement is that to print all the report documents in one pdf file? how to concatenate these things?
can any one help me?
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Hi,
To all
I need the functionality just like in code project how it is for example, before login in the code project just click on register page it transfers to the register page lying on the same page provide emailid and password to login to the code project it is logging.Please anyone help me
Thanks & Regards,
K. Amarnath
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If you are using forms authentication try this links
default url is the word you are looking for...!
http://msdn.microsoft.com/en-us/library/system.web.security.formsauthentication.defaulturl.aspx[^]
If you are Not using forms authentication use
Query string i.e. pass the last visited page in the query string so after registering with the help of Request.QueryString[""] You can rediredt to the last visited page
I didnt try this code but try this code..string prevurl = Request.UrlReferrer.AbsoluteUri;
LatestArticle :Log4Net
Why Do Some People Forget To Mark as Answer .If It Helps.
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Hi,
I am facing a strange problem here, I am using a webservice to send emails through my website.
Strangly when I run the application through VS2008 web development server only one email is sent which is normal, but when I publish the website on IIS then two copies of the emails are sent to the sender, which I don't understand.
Any suggestions or help shall be appreciated!Thanks
Shankbond
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can u post ur code, so that we can look into that and give some suggestion.
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I cannot actually post the code its huge, I will simply explain, The webservice accepts a dataset which has all the information related to sending emails,
I have sent emails through this webservice in the past also, but then it used to work fine. Is their something I should check regarding disco, wsdl or other files related to webservice.
Please help!Thanks
Shankbond
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problem is solved now it was a javascript issue, but it was not caught in webdevelopment server. Thanks
Shankbond
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i have 2 listboxes & 2 button. In 1st listbox, there are some items when i select many items from 1st listbox & press button1 then selected items add in 2nd Listbox & remove from 1st listbox. Afterthat i select many items from 2nd listbox & press button2 then selected items add 1st listbox & remove from 2nd one.
How to do this?
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| Did you try to implement this? Just you need to need remove few items from Listbox and adding it into another Listbox.You do easily on the buuton's event. What is the problem? Cheers!!
Brij
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Yoy may try this.
Protected Sub Button1_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles Button1.Click
Do While listbox1.SelectedIndex >= 0
listbox2.Items.Add(listbox1.SelectedItem)
listbox1.Items.RemoveAt(listbox1.SelectedIndex)
Loop
End SubSigurd Johansen
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hi,
i want to display loading image when i change the dropdownlist index and depending on that another dropdownlist wil load the item.So on that time i want to display the loading.gif image and user can able to know that item is under loading.i am using ajax on postback to load items on dropdownlist.
So any one able to help me to show this image on postback of loding dropdownlist.
Thank you.
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You must be having that loading image. Before postback just show that image from javascript and when you get the data from server ,before showing it hide the image.
Let me know if you face any issue.Cheers!!
Brij
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if you have any code for that then please forword me.i need it.
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Do one thing,On selection Changed event of you dropdown, put the fistline of code as
image1.style.display=''
and the last line in selection Changed event put
<code>image1.style.display='none'</code>
This will also resolve you problem.Cheers!!
Brij
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image1.style.display ,display is not the propery of style. any other soliution
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Sorry, that format works in javascript. I c# do it as
for not showing
image1.Style.Add("display", "none")
and when you have to show then
image1.Style.Add("display", "")Cheers!!
Brij
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