Java

Re: my validation form not working - pls advise. tks.

30-Dec-09 6:31

Whenver there's blank, an error message will appear and when the entry doen't meet the regular expression, it will also show error message.

The thing is that both messages will appear even though I just submit without enter anything.

Then I have problem with radio button validation for gender.

Pls advise. Tks.

karengsh30-Dec-09 6:38

Re: my validation form not working - pls advise. tks.

30-Dec-09 6:38

Sorry...the reset button is also not working. The netbean IDE keeps on asking to to create an Object.

Richard MacCutchan30-Dec-09 11:01

Re: my validation form not working - pls advise. tks.

30-Dec-09 11:01

This obviously requires some more work on your part, your statement above tells us nothing, your previous statement mentions error messages but you don't tell us what those messages are, or where in the code they occur. We cannot guess what is happening.

karengsh30-Dec-09 16:05

Re: my validation form not working - pls advise. tks.

30-Dec-09 16:05

The form allows user to post their particulars to a table.
Now, when I press submit, it will give me 2 kinds of error messages.
However, it is just supposed to flash 1 error message. It is only supposed to flash another kind of error message when the form does not meet the regular expression rules.

Secondly, the reset button is not working. Netbean IDE keeps asking for object wanted.

Thirdly, the radio button validation I am not sure what is wrong with the code.

Hope you can help me. pls. urgent.

Richard MacCutchan30-Dec-09 23:58

30-Dec-09 23:58

You continue to believe that I can guess what these error messages are - I cannot.
Also if the IDE is asking for an object (where, I have no idea) then I suspect there is something missing from your code.

HashMap

002comp29-Dec-09 22:55

29-Dec-09 22:55

Hello Friends
I want to extract values from HashMap.How I can do?Here is the code below:

class VFMMmaterial
{
public:
int matId;
String matName;
}

public HashMap&lt;Integer, VFMMaterial&gt; materialsMap = new HashMap&lt;Integer, VFMMaterial&gt;();

materialsMap.put(material.materialId, material);
all values of id and name r putted in materialmap

Now i tried like this to access material name:

Iterator itr = materialMap.keySet().Iterator();
While(itr.hasNext())
{
   String id = itr.next();

    String name = materiaMap.GetKey(Integer.ParseInt(id)).matName;
}

but it is giving error at run time and I tried also entrySet in place of keySet()

Tell me some solution.
Thanks

Richard MacCutchan29-Dec-09 23:16

29-Dec-09 23:16

Firstly your code is not easy to read, please format it correctly. Secondly you say:

yogeshs wrote:
but it is giving error at run time and I tried also entrySet in place of keySet()

but you do not explain what runtime error, and it is unlikely that we can guess it!

002comp30-Dec-09 18:01

30-Dec-09 18:01

I am getting iterator of Hashmap hmap like this:
Iterator itr = hmap.keySet().Iterator();

Now,I m running this loop to get next value like this:
while(itr.hasNext())
{
Object key = itr.next();
}

Now,the itr.next is returning the object type.But to get the value by using that key needs int type not object type,that code is here:
while(itr.hasNext())
{
Object key = itr.next();
String name = hmap.get(key).materialname;
}
so what can I do?
I want to tell that hmap is having two parameters:
hmap<int id,class="" material="">

Thanks In Advance.
Yogesh

Cedric Moonen30-Dec-09 23:16

Cedric Moonen

30-Dec-09 23:16

First thing: as already mentioned a LOT of times, please format your code properly. Take some time to make your message readable and understandable, you will definitively get much more answers.
Second point, the previous poster asked you about which runtime error you receive. You still didn't provide that information.

Now concerning your problem: why do you iterate over the keys if you need the values D'Oh! | :doh:

? Instead of doing this:

Iterator itr = hmap.keySet().Iterator();

Do this:

Iterator itr = hmap.values().Iterator();

This way you will iterate over the values of your map. You will still need to cast your object to the correct type if you didn't use generics when declaring your map.

yogeshs wrote:
I want to tell that hmap is having two parameters:
hmap

I don't get that part of your message. Could you please clarify what you are trying to do ?

Cédric Moonen
Software developer

Charting control [v3.0 - Updated]
OpenGL game tutorial in C++

002comp30-Dec-09 23:48

Error Message - HTTP 500 & Error Message - no servlet mappings in web.xml

30-Dec-09 23:48

thx a lot .

karengsh29-Dec-09 0:28

Re: Error Message - HTTP 500 & Error Message - no servlet mappings in web.xml

29-Dec-09 0:28

I'm using netbean IDE to create a jsp file which will collect data from another jsp file which contains a form for people to enter data.

However, when I run the jsp file, it gives me the following error:-

There are no servlet mappings specified in web.xml.

org.apache.jasper.JasperException: An exception occurred processing JSP page /processAddMember.jsp at line 34

31: strContact = request.getParameter("txtContact").trim();
32: strDOB = request.getParameter("txtDOB").trim();
33: strGender = request.getParameter("txtGender").trim();
34: strType = request.getParameter("txtMember").trim();
35: strRemarks = request.getParameter("txtRemarks").trim();
36: strCreateRecordSQL = "INSERT INTO tblMember ";
37: strCreateRecordSQL += "(strFullNameME,strEmailME,strAddressME, strNRICNoME, strContactME, "

Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:505)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:416)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
org.netbeans.modules.web.monitor.server.MonitorFilter.doFilter(MonitorFilter.java:390)

root cause

java.lang.NullPointerException
org.apache.jsp.processAddMember_jsp._jspService(processAddMember_jsp.java:87)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
org.netbeans.modules.web.monitor.server.MonitorFilter.doFilter(MonitorFilter.java:390)

note The full stack trace of the root cause is available in the Apache Tomcat/6.0.20 logs.

Pls help me. It's urgent. tks.

Richard MacCutchan29-Dec-09 4:39

Re: Error Message - HTTP 500 & Error Message - no servlet mappings in web.xml

29-Dec-09 4:39

karengsh wrote:
org.apache.jasper.JasperException: An exception occurred processing JSP page /processAddMember.jsp at line 34

The above should point you to the cause; it looks as though txtMember may not have been initialised correctly.

karengsh30-Dec-09 5:06

Re: Error Message - HTTP 500 & Error Message - no servlet mappings in web.xml

30-Dec-09 5:06

May I know how did you identify the error?

Richard MacCutchan30-Dec-09 5:41

Prob in reading .mtl file format.

30-Dec-09 5:41

karengsh wrote:
May I know how did you identify the error?

Simply by reading the error messages. Your original post showed the following (cut out the unimportant parts):

org.apache.jasper.JasperException: An exception occurred processing JSP page /processAddMember.jsp at line 34

34: strType = request.getParameter("txtMember").trim();

This shows that the statement on line 34 caused an error

root cause

java.lang.NullPointerException

A NullPointerException usually indicates that some variable has not been initialised correctly, or has been corrupted or otherwise changed to make it invalid.

From this (and the stack trace) you need to work backwards through your program to identify were this may have occurred.

002comp27-Dec-09 19:35

call by value for objects

27-Dec-09 19:35

Hello Friends
Do anyone of you know about material(.mtl) file?
Do anyone of you read it?
I read most of the file but some option are not getting through java classes like map_ka(ambient textures),map_ks(specular textures).

Thanks In Advance.

Regards
Yogesh

mesho26-Dec-09 8:52

26-Dec-09 8:52

hi all
as u know java is using call by reference with objects
how can i instead call by value for objects??

thanks in advance

Luc Pattyn26-Dec-09 9:18

Luc Pattyn

26-Dec-09 9:18

Hi,

You can't pass an object by value. The best approximation would be to pass a clone of the object.
And why would you need to pass by value?

Smile | :)

Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]

Merry Christmas and a Happy New Year to all.

mesho26-Dec-09 10:33

26-Dec-09 10:33

i have arraylist of objects <schedules>
and i wrote a method that take one object <schedule> from the arraylist
and return a modified object <another schedule="">

the problem is after calling the method all objects in the arraylist changed to the new value!!!

when i debuge my program i realized that all objects (in the array list and the returning object) have the same id (i'm using eclipse), which is suppose to be unique
and because of that any changes to object are applied to all version

i don't know way
can you help please?? Rose | [Rose]

Luc Pattyn26-Dec-09 10:38

Luc Pattyn

26-Dec-09 10:38

from what you told, but did not show, it sounds like you are only creating a single object, and have a loop that (1) modifies it somehow and (2) adds its reference to the arraylist, resulting in a large number of identical references to the single object in its final state.

Check: is the "new Whatever(...)" inside or outside your loop?

If that does not help, then I suggest you show the relevant code.

Smile | :)

Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]

Merry Christmas and a Happy New Year to all.

mesho26-Dec-09 10:54

26-Dec-09 10:54

my code is very long, that's why i don't write it before

i'm writing a program for multiprocessor using genetic algorithm

<br />
ArrayList <schedule> POP=new  ArrayList <schedule>();			<br />
		for(int i=0;i<10;i++)<br />
	    		POP.add(generate_schedule());<br />
<br />
ArrayList <schedule> TMP=new ArrayList <schedule> ();<br />
	    		<br />
	    		<br />
	    		for(int j=0;j < NPOP.size()/2;j++)<br />
	    		{<br />
	    			schedule s1=NPOP.get(j);<br />
	    			<br />
	    			schedule s2=NPOP.get(j+(POP.size()/2));<br />
	    			<br />
	    			Random rand=new Random();<br />
	    	        double r=rand.nextDouble();<br />
	    			if(r<=CrossOver_prob)<br />
	    			{<br />
	    				ArrayList <schedule> result=new ArrayList <schedule>();<br />
	    				result=crossover(s1,s2);<br />
	    				TMP.add(result.get(0));<br />
	    				TMP.add(result.get(1));<br />
	    			}<br />
	    			else<br />
	    			{<br />
	    				TMP.add(s1);<br />
		    			TMP.add(s2);<br />
	    			}<br />
	    			<br />
	    		}<br />
<br />
for(int j=0;j < TMP.size();j++)<br />
	    		{<br />
	    			System.out.println("schedule"+j);<br />
	    			Random rand=new Random();<br />
	    	                double r=rand.nextDouble();<br />
	    			if(r<=Mutation_prob)<br />
	    				POP.add(Mutation(TMP.get(j)););<br />
	    			else<br />
	    				POP.add(TMP.get(j));<br />
	    		}

my problem is on the bold line when calling mutation all schedules in TMP is changed

hope its clear now Smile | :)

Luc Pattyn26-Dec-09 11:22

Luc Pattyn

26-Dec-09 11:22

Sorry, that code is hardly readable; please use PRE tags, not CODE tags, so we get indentation and good contrast. You can still edit the existing message.

Furthermore, what needs to be checked is how the values or objects get created that you are adding to the arraylist, hence one has to inspect Mutation(), and whatever is used to create the entries in NPOP (as those will end up in TMP).

Smile | :)

Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]

Merry Christmas and a Happy New Year to all.

Cedric Moonen26-Dec-09 22:45

Cedric Moonen

26-Dec-09 22:45

Your question is still not very clear because you didn't provide the function prototype (we can only see the content of the function, not the parameters which are passed).
Anyway, in Java whenever you manipulate an object, it is similar as using a pointer to the object. So, when you pass the object to a function, you pass the pointer and not a copy of the object. If you really need to make changes in a copy of the object, then you have to create a new instance of the object yourself.
There's no such thing as passing by value in java.

Cédric Moonen
Software developer

Charting control [v2.0]
OpenGL game tutorial in C++

mesho27-Dec-09 5:38

27-Dec-09 5:38

Luc Pattyn
Cédric Moonen
thank u all for your reply

its clear now that's my problem was i don't create a new insantce of my objects
but i referenced to existing object

schedule s = POP.get(i);
where POP is arraylist of schedules

again thank u for ur help Rose | [Rose]