console writing

Question

1.00/5 (3 votes)

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I have codeblock like below i wanna get like an output

hello
ello
llo
lo
o

and I DON NOT want to add any other C statement. Where i did mistake?

char str[] = "hello";
char *p = str;
int i =0
for (i=0;i<5;i++)
{
printf("%c",*p++);
}

my current output is:

h
e
l
l
o

%s for scanf function, also for printf(), as clearly documented in MSDN and every book ever written about the C programming language.

Posted 29-Dec-09 10:05am

bounik

Updated 29-Dec-09 11:27am

Richard MacCutchan

v4

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4 solutions

Solution 4

As already pointed out by Richard, you've to replace the statement

printf("%c", *p++);

that prints just the single character *p (see MSDN [^]) with the following one

printf("%s\n", p++);

that outputs a string starting from (increasing) address p.
:)

Posted 29-Dec-09 10:27am

CPallini

Updated 29-Dec-09 11:13am

v3

Solution 5

Did you even try my suggestion? What is the point of asking a question, if your only response is to challenge what has been posted rather than modifying your code and actually seeing whether it works or not? :mad:

Posted 29-Dec-09 10:33am

Richard MacCutchan

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Richard MacCutchan · Accepted Answer · 2009-12-29T10:11:00

Solution 1

printf("%s\n", p++);

[edit]OK, I messed up and forgot the newline; but, hey, nobody else noticed ;) [/edit]

Posted 29-Dec-09 10:11am

Richard MacCutchan

Updated 29-Dec-09 10:51am

v2

zadeveloper.com · Accepted Answer · 2009-12-29T10:57:00

Mistakes include:
Missing a ; after int i =0.
You are only printing 1 char at a time
There is no line feed (as per you requirement)

Unfortunately you cannot fix this without adding another loop to count the chars to print. I would do it like this (using your restrictions):

char str[] = "hello";
int iLength = 5;

for (int i=0; i<iLength; i++)
{
	for (int j = i; j < iLength; j++)
		printf("%c", (int)str[j]);

	printf ("\r\n");
}

console writing

4 solutions

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