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How to do kickstart without using the linux booting cd........?
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Careful you may hurt your toes!
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hi, thnx for ur reply.....
but please do know about the subject before replying......
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hi, thnx for ur reply...
please let me know how could we process from the LAN connections.
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Hi. I a'm writting a simple application on php 5 and zend_framework. I need to create two dropdown lists that depends on each other. Cities and streets for example. I select a new city at my client page and want that my application post me at the other dropdown list streets related to this city in the database. Which would be the better way to do it?
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simple is relative but I would write an ajax call to a php server side script that returned the street data. All of this would started by using a onchange event of the city select from the display page.
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Tnx. Now i know where to look. Big tnx.
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Hi there !
Im using Joomla 1.5 to build my site.
My component(query data from database of website) work well if i don't install joomfish.
After i installed Joom!Fish 2.0.4 Stable into my site for translation my component does not work(with error).
My code of component as bellow:
$query='select * from jos_content where sectionid=11 and state=1
order by catid ';
$database->setQuery( $query );
$result=mysql_query($query);
while($row=mysql_fetch_object($result)){
echo 'data'.$row->title;
}
And i see these bellow warnings if i refer to my component.
Warning: mysql_query() [function.mysql-query]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\so\components\com_products\products.php on line 131
Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in C:\xampp\htdocs\so\components\com_products\products.php on line 131
Warning: mysql_fetch_object(): supplied argument is not a valid MySQL result resource in C:\xampp\htdocs\so\components\com_products\products.php on line 137
Any ideas !
Thanks in regards !
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sharkbc wrote: Access denied for user 'ODBC'@'localhost' (using password: NO)
Check your configuration file as it appears you can't connect to the database using your credentials. Your new install probably overwrote the config file.
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Dear Marc Firth !
The configuration file has no change(I checked).
My website "works well" except my component.
Thanks anyway !
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I found solution. It now work well
sharkbc
Free ware
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Hi Guys,
I am using MySQL Administrator 1.2.17. And my problem is I cannot access the MySQL remotely from the web server. I have the dbHost, dbUsername, dbPassword. But when I tried accessing it through MySQL Administrator tool I got an error that says...
Error:
Could not connect to the specified instance. MySQL Error Number 2005
Unknown MySQL server host '...' (11004)
Is there a way on how can I get through this?
Thanks
hifiger2004
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yeah, fix whatever is in your dbHost variable...
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Hi all.
I am new to PHP and trying to learn it.I have created a web page and defined items as below :
<form method="POST" action="send.php">
<font color="green"> Full Name : </font>
<input type="text" name="name" size="20">
<font color="green"> Gotra(Clan) : </font>
<input type="text" name="gotra" size="20">
<font color="green"> Father's Name : </font>
<input type="text" name="fname" size="20">
<font color="green">Details of Prasad to be Offered : </font>
(eg.: name of temple, quantity of prasad, specific date & any other requirements)
<textarea rows="5" name="prasad" cols="40" ></textarea>
<font color="green"> Any Wish to God : </font>
<textarea rows="5" name="wish" cols="40" ></textarea>
<font color="green"> Postal Address : </font>
<textarea rows="5" name="address" cols="40" ></textarea>
<font color="green"> Phone no. : </font>
<input type="text" name="phone" size="20">
<font color="green"> Preferred Time of Contact : </font>
<input type="text" name="time" size="20">
<font color="green"> Email address : </font>
<input type="text" name="email" size="20">
<br>
<input name="Submit" type="submit" class="input" value="Send">
<input name="Submit2" type="reset" class="input" value="Reset">
</br>
</form>
and the send.php has following block of code :
<?php
if(isset($_POST['submit'])) {
$to = "gagan.u20@gmail.com";
$subject = "E-Prasad Details";
$name_field = $_POST['name'];
$gotra_field=$_POST['gotra'];
$fname_field = $_POST['fname'];
$prasad=$_POST['prasad'];
$wish=$_POST['wish'];
$address=$_POST['address'];
$phone_field=$_POST['phone'];
$time_field=$_POST['time'];
$email_field=$_POST['email'];
$body = "From: $name_field\n Gotra: $gotra_field\n Father's name: $fname_field\n Details of prasad to be offered : $prasad\n Any wish to God: $wish\n Postal address : $address\n Phone no. : $phone_field\n Preferred time of contact : $time_field\n E-mail address : $email_field";
echo "Data has been submitted!";
mail($to, $subject, $body);
} else {
echo "An error occurred! Please try again.";
}
?>
Now the problem is, when I fill the form and click og sublit button, it gives an error that "An error occurred! Please try again."
Tell me where am I wrong in writing the code. Tell me the correct code.
Thanks.
Gagan
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Why do you check
if(isset($_POST['submit'])) ? Obviously that is false and you've trapped the problem and displayed the error message you wrote.
CQ de W5ALT
Walt Fair, Jr., P. E.
Comport Computing
Specializing in Technical Engineering Software
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ok, then tell me what should I write to send e-mail because I am new to PHP.
Help me.
Thanks.
Gagan
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Your email sending part looks fine. I use
mail($to, $subject, $contents, $from_header); with the $from_header, although that might be optional. But that's not the problem you are seeing -- your code isn't even getting there.
Looking at your PHP code, the first thing executed is
if(isset($_POST['submit']))
Since you get the message you showed, obviously that is being evaluated as false, so the else part is executed showing the message.
So my question to you is: Why are you checking to see if the 'submit' POST variable is set? That's where your code is having problems -- before it ever gets to sending the email.
My suggestion is to take the if/else out and run the code to send the email. That should work if email is allowed on your server. If it works, then you can go back and check for whatever you want to check for with the if statement.
See the following links for examples:
http://www.webcheatsheet.com/php/send_email_text_html_attachment.php[^]
http://php.about.com/od/phpapplications/ss/form_mail.htm[^]
CQ de W5ALT
Walt Fair, Jr., P. E.
Comport Computing
Specializing in Technical Engineering Software
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Thanks for your help. I just removed the line if(isset($_POST['submit'])) and it worked.
Thanks 
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Glad to hear it works!
I'd also remove the rest of the if/else braces. To check for errors you probably should wrap the mail command in an if, too. See the links I posted before for examples.
CQ de W5ALT
Walt Fair, Jr., P. E.
Comport Computing
Specializing in Technical Engineering Software
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here:
<input name="Submit" type="submit" class="input" value="Send">
and here :
if(isset($_POST['submit']))
so
if(isset($_POST['submit'])) =>if(isset($_POST['Submit']))
This is a common problem
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regarding reading elements to array from dialog ,i.e i want to read elements from text box and put that in array and display them.any one can can give me.
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This is best handled by javascript. Try doing a google search for "javascript popup writing to parent".
The basic logic of it is when you open a popup window, there s a special reference to the parent window in javascript. You can use this to fill out a variable or array from the popup window.
all the best!
cjoki
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If you take a look at your source code, the "/" are outside of any HTML tag that you echoed onto the page. If I had to venture a guess, it would be a slight discrepancy in the way you echoed your HTML. I use String literal quotes (the single quote) '<p>String Literal</p>' (Versus the normal string using double quotes) "<p>Normal String</p>" . I suggest messing around with different ways to echo the data. Perhaps using the concatenation "." between your variables and other string literals. Say '<p>Dexter Morgan ' . $variable . ' the man discretely.</p>' . You may have used the concat as well as the rest of my suggestions, but I cant see your code :P.
I hope this helps.
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